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Describe the sampling distribution of \(\hat{p}\). Assume that the size of the population is 25,000 for each problem. $$ n=1010, p=0.84 $$

Short Answer

Expert verified
The sampling distribution of \(\hat{p}\) is approximately normal with mean 0.84 and standard deviation 0.0115.

Step by step solution

01

Identify the parameters

Given: \(n = 1010\) (sample size)\(p = 0.84\) (population proportion)
02

Calculate the mean of the sampling distribution

The mean of the sampling distribution of \(\hat{p}\) is the same as the population proportion: \(\mu_{\hat{p}} = p = 0.84\).
03

Calculate the standard deviation of the sampling distribution

The standard deviation of the sampling distribution of the sample proportion \(\hat{p}\) is given by: \(\sigma_{\hat{p}} = \sqrt{ \frac{ p(1 - p)}{n} }\)Substitute the given values:\(\sigma_{\hat{p}} = \sqrt{ \frac{ 0.84(1 - 0.84)}{1010} } = \sqrt{ \frac{ 0.84 \cdot 0.16 }{1010} } = \sqrt{ \frac{ 0.1344 }{1010} } = \sqrt{0.000133} \approx 0.0115\).
04

Determine the shape of the distribution

Since \(np\) and \(n(1-p)\) are both greater than 5, the sampling distribution of \(\hat{p}\) can be approximated by a normal distribution.
05

Summarize the sampling distribution

The sampling distribution of \(\hat{p}\) is approximately normal with mean \(\mu_{\hat{p}} = 0.84 \) and standard deviation \(\sigma_{\hat{p}} \approx 0.0115\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Population Proportion
Understanding the concept of population proportion is essential in statistics. Population proportion, denoted as 'p', represents the fraction or percentage of the total population with a particular characteristic. For instance, in the original exercise, the population proportion is given as 0.84. This means that 84% of the population of 25,000 individuals exhibits the characteristic in question.
Considering population proportion helps in making inferences about a population. For example, if we are studying how many people prefer a certain product, and 84% of our sample prefers it, we can use this proportion to make educated guesses about the entire population.
Sample Size
Sample size, indicated as 'n', refers to the number of observations or data points collected from the population for analysis. In the given problem, the sample size is 1010. Choosing an appropriate sample size is crucial for accuracy as it affects the reliability of the estimates about the population.
A larger sample size generally leads to more precise estimates. This is because it reduces the margin of error, making the data more representative of the population. However, it’s essential to balance between sample size and resources like time and cost. Properly selecting a sample size can make statistical analysis efficient and reliable.
Standard Deviation
Standard deviation is a measure that quantifies the amount of variation or dispersion in a set of data values. In the context of the sampling distribution of the sample proportion (denoted as \( \hat{p} \)), the standard deviation provides insight into how much the sample proportion is expected to vary from the true population proportion.
The formula for the standard deviation of \( \hat{p} \) is: \[ \sigma_{\hat{p}} = \sqrt{\frac{ p(1 - p)}{n} } \].
Using the values from the exercise: \[ \sigma_{\hat{p}} = \sqrt{\frac{ 0.84(1 - 0.84)}{1010} } = \sqrt{\frac{ 0.84 \cdot 0.16 }{1010} } = \sqrt{ \frac{ 0.1344 }{1010} } = \sqrt{0.000133} \approx 0.0115 \].
This calculation tells us that the standard deviation is approximately 0.0115, indicating how much the sample proportions vary from the actual population proportion.
Normal Distribution
A normal distribution is a bell-shaped curve that is symmetrical around the mean. This distribution is especially significant in statistics because it represents the distribution of many natural phenomena and measurement errors. When sample sizes are large enough, the sampling distribution of the sample proportion \( \hat{p} \) tends to be normally distributed due to the Central Limit Theorem.
In our exercise, both \( np \) and \( n(1-p) \) are greater than 5, allowing the sampling distribution of \( \hat{p} \) to be approximated by a normal distribution. This approximation lets us use properties of the normal distribution to make inferences about the population proportion. Knowing this is useful for constructing confidence intervals and performing hypothesis tests effectively.
To summarize the sampling distribution of \( \hat{p} \): it is approximately normal with a mean \( \mu_{\hat{p}} = 0.84 \) and standard deviation \( \sigma_{\hat{p}} \approx 0.0115 \).

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Most popular questions from this chapter

Are You Satisfied? According to a study done by the Gallup organization, the proportion of Americans who are satisfied with the way things are going in their lives is 0.82 . (a) Suppose a random sample of 100 Americans is asked, "Are you satisfied with the way things are going in your life?" Is the response to this question qualitative or quantitative? Explain. (b) Explain why the sample proportion, \(\hat{p}\), is a random variable. What is the source of the variability? (c) Describe the sampling distribution of \(\hat{p},\) the proportion of Americans who are satisfied with the way things are going in their life. Be sure to verify the model requirements. (d) In the sample obtained in part (a), what is the probability the proportion who are satisfied with the way things are going in their life exceeds \(0.85 ?\) (e) Would it be unusual for a survey of 100 Americans to reveal that 75 or fewer are satisfied with the way things are going in their life? Why?

Assessments Consider the homeowners association presented at the beginning of this section. A random sample of 20 households resulted in 15 indicating that they would favor an increase in assessments. Explain why the normal model could not be used to determine if a sample proportion of \(\frac{15}{20}=0.75\) or higher from a population whose proportion is 0.65 is unusual.

State the Central Limit Theorem

Determine \(\mu_{\bar{x}}\) and \(\sigma_{\bar{x}}\) from the given parameters of the population and the sample size. \(\mu=64, \sigma=18, n=36\)

Reincarnation Suppose \(21 \%\) of all American teens (age 13-17 years) believe in reincarnation. (a) Bob and Alicia both obtain a random sample of 100 American teens and ask each participant to disclose whether they believe in reincarnation or not. Is "belief in reincarnation" qualitative or quantitative? Explain. (b) Explain why Bob's sample of 100 randomly selected American teens might result in 18 who believe in reincarnation, while Alicia's independent sample of 100 randomly selected American teens might result in 22 who believe in reincarnation. (c) Why is it important to randomly select American teens to estimate the population proportion who believe in reincarnation? (d) In a survey of 100 American teens, how many would you expect to believe in reincarnation? (e) Below is the histogram of the sample proportion of 1000 different surveys in which \(n=20\) American teens were asked to disclose whether they believed in reincarnation. Explain why the normal model should not be used to describe the distribution of the sample proportion. (f) What minimum sample size would you require in order for the distribution of the sample proportion to be modeled by the normal distribution?

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