/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 35 The lengths of human pregnancies... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The lengths of human pregnancies are normally distributed with \(\mu=266\) days and \(\sigma=16\) days. (a) The figure represents the normal curve with \(\mu=266\) days and \(\sigma=16\) days. The area to the right of \(x=280\) is 0.1908 . Provide two interpretations of this area. (b) The figure represents the normal curve with \(\mu=266\) days and \(\sigma=16\) days. The area between \(x=230\) and \(x=260\) is \(0.3416 .\) Provide two interpretations of this area.

Short Answer

Expert verified
Part (a): 19.08% of pregnancies last more than 280 days. Part (b): 34.16% of pregnancies last between 230 and 260 days.

Step by step solution

01

- Understand the Problem

The problem involves interpreting areas under a normal distribution curve. It is given that the lengths of human pregnancies are normally distributed with a mean \(\mu = 266\) days and standard deviation \(\sigma = 16\) days.
02

- Know the Information for Part (a)

For part (a), you need to interpret the area to the right of \(x = 280\), which is given as 0.1908.
03

- First Interpretation for Part (a)

The area to the right of \(x = 280\) (0.1908) represents the probability that a randomly selected pregnancy will last more than 280 days. In other words, there is a 19.08% chance that a pregnancy will be longer than 280 days.
04

- Second Interpretation for Part (a)

Another way to look at it is that 19.08% of all pregnancies last more than 280 days, based on the normal distribution with \(\mu = 266\) days and \(\sigma = 16\) days.
05

- Know the Information for Part (b)

For part (b), you need to interpret the area between \(x = 230\) and \(x = 260\), which is given as 0.3416.
06

- First Interpretation for Part (b)

The area between \(x = 230\) and \(x = 260\) (0.3416) represents the probability that a randomly selected pregnancy will last between 230 and 260 days. This means that there is a 34.16% chance that a pregnancy will fall within this range.
07

- Second Interpretation for Part (b)

Another way to interpret this is that 34.16% of all pregnancies last between 230 and 260 days, based on the normal distribution with \(\mu = 266\) days and \(\sigma = 16\) days.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mean and Standard Deviation
In the context of a normal distribution, **mean** (\( \text{\textmu} \)) and **standard deviation** (\( \text{\textsigma} \)) are fundamental concepts. The mean represents the average or central value of the data. For example, in our exercise, the mean length of human pregnancies is \( 266 \) days. This means that on average, pregnancies last \( 266 \) days.
The standard deviation, on the other hand, measures the spread or dispersion of the data around the mean. A smaller standard deviation indicates that the data points are closer to the mean, while a larger standard deviation shows more variability. In this exercise, the standard deviation is \( 16 \) days. This tells us that the lengths of pregnancies tend to vary by about \( 16 \) days on either side of the mean.
So, in summary, mean helps us understand the central tendency of the data, and standard deviation indicates how much the data tends to deviate from this central point.
Probability Interpretation
When interpreting probabilities in the context of a normal distribution, imagine the entire area under the curve as representing 100% of all possible outcomes.
For part (a) of the exercise, the area to the right of \( x = 280 \) is 0.1908. This area tells us the probability of a pregnancy lasting more than \( 280 \) days. In other words, there is a 19.08% chance of a pregnancy going beyond \( 280 \) days.
In part (b), the area between \( x = 230 \) and \( x = 260 \) is 0.3416. This means there is a 34.16% chance that a pregnancy will last within this range. Another way to interpret this is that if we randomly select a pregnancy, there’s a 34.16% probability it will fall between \( 230 \) and \( 260 \) days.
Area under the Curve
The area under the normal distribution curve represents probabilities. Each section of the curve corresponds to a different probability. The curve is symmetrical and centered around the mean.
For example, the area to the right of \( x = 280 \) represents the probability of a pregnancy lasting more than \( 280 \) days, which is 0.1908 or 19.08%. This area is shaded to the right of \( x = 280 \).
Similarly, the area between \( x = 230 \) and \( x = 260 \) represents the probability of a pregnancy falling within that range, which is 0.3416 or 34.16%. This area is shaded between \( x = 230 \) and \( x = 260 \).
Understanding the area under the curve helps us interpret different probabilities and make sense of the data.
Normal Distribution Curve
The normal distribution curve is a bell-shaped curve that is symmetrical around the mean. It is characterized by its mean \( \text{\textmu} \) and standard deviation \( \text{\textsigma} \).
The highest point on the curve represents the mean, where most of the data points are concentrated. As you move away from the mean, the curve drops off, showing fewer occurrences of the data.
In the context of our exercise, the normal distribution curve has a mean of \( 266 \) days and a standard deviation of \( 16 \) days. This curve allows us to visualize the distribution of pregnancy lengths.
Areas under the curve represent different probabilities, making it a powerful tool for statistical analysis. For instance, whether interpreting probabilities for a pregnancy lasting more than \( 280 \) days or falling between \( 230 \) and \( 260 \) days, the normal distribution curve helps us understand these probabilities effectively.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Fast-food restaurants spend quite a bit of time studying the amount of time cars spend in their drive-through. Certainly, the faster the cars get through the drive-through, the more the opportunity for making money. QSR Magazine studied drive-through times for fast-food restaurants, and found Wendy's had the best time, with a mean time a car spent in the drive-through equal to 138.5 seconds. Assume that drive-through times are normally distributed, with a standard deviation of 29 seconds. Suppose that Wendy's wants to institute a policy at its restaurants that it will not charge any patron that must wait more than a certain amount of time for an order. Management does not want to give away free meals to more than \(1 \%\) of the patrons. What time would you recommend Wendy's advertise as the maximum wait time before a free meal is awarded?

Assume that the random variable \(X\) is normally distributed, with mean \(\mu=50\) and standard deviation \(\sigma=7 .\) Compute the following probabilities. Be sure to draw a normal curve with the area corresponding to the probability shaded. \(P(X>35)\)

Adiscrete random variable is given. Assume the probability of the random variable will be approximated using the normal distribution. Describe the area under the normal curve that will be computed. For example, if we wish to compute the probability of finding at least five defective items in a shipment, we would approximate the probability by computing the area under the normal curve to the right of \(x=4.5 .\) The probability that fewer than 35 people support the privatization of Social Security.

In a recent poll, the Gallup Organization found that \(45 \%\) of adult Americans believe that the overall state of moral values in the United States is poor. Suppose a survey of a random sample of 500 adult Americans is conducted in which they are asked to disclose their feelings on the overall state of moral values in the United States. Use the normal approximation to the binomial to approximate the probability that (a) exactly 250 of those surveyed feel the state of morals is poor. (b) no more than 220 of those surveyed feel the state of morals is poor. (c) more than 250 of those surveyed feel the state of morals is poor. (d) between 220 and 250 , inclusive, believe the state of morals is poor. (e) at least 260 adult Americans believe the overall state of moral values is poor. Would you find this result unusual? Why?

Compute \(P(x)\) using the binomial probability formula. Then determine whether the normal distribution can be used as an approximation for the binomial distribution. If so, approximate \(P(x)\) and compare the result to the exact probability. $$ n=40, p=0.25, x=30 $$

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.