/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 50 Fast-food restaurants spend quit... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Fast-food restaurants spend quite a bit of time studying the amount of time cars spend in their drive-through. Certainly, the faster the cars get through the drive-through, the more the opportunity for making money. QSR Magazine studied drive-through times for fast-food restaurants, and found Wendy's had the best time, with a mean time a car spent in the drive-through equal to 138.5 seconds. Assume that drive-through times are normally distributed, with a standard deviation of 29 seconds. Suppose that Wendy's wants to institute a policy at its restaurants that it will not charge any patron that must wait more than a certain amount of time for an order. Management does not want to give away free meals to more than \(1 \%\) of the patrons. What time would you recommend Wendy's advertise as the maximum wait time before a free meal is awarded?

Short Answer

Expert verified
206.07 seconds

Step by step solution

01

Understand the Problem

We need to find the maximum time (in seconds) a car can spend in the drive-through before Wendy's gives a free meal to no more than 1% of patrons.
02

Define the Distribution

The drive-through times are normally distributed with a mean (\(\text{mean} = 138.5\) seconds) and a standard deviation (\(\text{sd} = 29\) seconds).
03

Identify the Percentile

We need to find the time corresponding to the 99th percentile of the normal distribution, since 1% of patrons should get free meals due to waiting time.
04

Use the Z-Score Formula

The formula to convert a percentile to a time is:\[X = \text{mean} + (Z \times \text{sd})\]Where \(Z\) corresponds to the 99th percentile. From Z-tables or a standard normal distribution calculator, \(Z_{99\text{th percentile}}\) = 2.33.
05

Calculate the Maximum Time

Using the Z-score of 2.33, we have:\[X = 138.5 + (2.33 \times 29) = 138.5 + 67.57 = 206.07 \text{ seconds}\]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Normal Distribution
In business and statistics, many processes and measurements follow a pattern called the normal distribution. It is often represented as a bell-shaped curve. Most values cluster around a central mean, and the probability of values decreases as you move away from the mean. For Wendy's drive-through times, the mean is 138.5 seconds with a standard deviation of 29 seconds. This means most customers experience a waiting time close to 138.5 seconds, and fewer will have times much lower or higher.
Percentile Calculation
Percentiles help you understand the relative standing of a value within a dataset. If we say a value is at the 99th percentile, it means 99% of the data points fall below this value. For Wendy's, we want to set a waiting time limit such that only the top 1% of waiting times (that might qualify for a free meal) exceed this limit. This means finding the 99th percentile of the normal distribution of waiting times.
Z-Score
Z-scores are a standardized way of describing where a value lies within a normal distribution. The formula for calculating the z-score is:o\[ Z = \frac{(X - \text{mean})}{\text{sd}} \]o\where **X** is the value you are standardizing, **mean** is the average of the dataset, and **sd** is the standard deviation. To reverse this and find a specific value from a z-score and percentile, you use:o\[ X = \text{mean} + (Z \times \text{sd}) \]o FFor the 99th percentile, **Z** = 2.33, and thus for Wendy's:o\[ X = 138.5 + (2.33 \times 29) \approx 206.07 \text{ seconds} \]
Business Applications of Statistics
Statistics play a crucial role in aiding decision-making in business. Fast-food chains like Wendy's use it to streamline operations and improve customer satisfaction. By analyzing waiting times with normal distribution and determining specific percentiles, businesses can make data-informed decisions. This helps set achievable goals and service standards—like not charging patrons whose waiting time exceeds a certain threshold—which can enhance customer experience and operational efficiency.
Waiting Time Analysis
Analyzing waiting times is vital for service-based businesses. Long waiting times can lead to customer dissatisfaction and lost revenue. By understanding the distribution of waiting times, businesses can pinpoint areas needing improvement. For Wendy's, setting a wait time policy based on the top 1% of distribution helps minimize the number of free meals while keeping wait times practical and acceptable for most customers. This analysis ensures they can balance service quality with operational costs effectively.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Assume that the random variable \(X\) is normally distributed, with mean \(\mu=50\) and standard deviation \(\sigma=7 .\) Compute the following probabilities. Be sure to draw a normal curve with the area corresponding to the probability shaded. \(P(40 \leq X \leq 49)\)

The lengths of human pregnancies are approximately normally distributed, with mean \(\mu=266\) days and standard deviation \(\sigma=16\) days. (a) What proportion of pregnancies lasts more than 270 days? (b) What proportion of pregnancies lasts less than 250 days? (c) What proportion of pregnancies lasts between 240 and 280 days? (d) What is the probability that a randomly selected pregnancy lasts more than 280 days? (e) What is the probability that a randomly selected pregnancy lasts no more than 245 days? (f) A "very preterm" baby is one whose gestation period is less than 224 days. Are very preterm babies unusual?

Compute \(P(x)\) using the binomial probability formula. Then determine whether the normal distribution can be used as an approximation for the binomial distribution. If so, approximate \(P(x)\) and compare the result to the exact probability. $$ n=85, p=0.8, x=70 $$

Chips per Bag In a 1998 advertising campaign, Nabisco claimed that every 18-ounce bag of Chips Ahoy! cookies contained at least 1000 chocolate chips. Brad Warner and Jim Rutledge tried to verify the claim. The following data represent the number of chips in an 18 -ounce bag of Chips Ahoy! based on their study. $$ \begin{array}{lllll} \hline 1087 & 1098 & 1103 & 1121 & 1132 \\ \hline 1185 & 1191 & 1199 & 1200 & 1213 \\ \hline 1239 & 1244 & 1247 & 1258 & 1269 \\ \hline 1307 & 1325 & 1345 & 1356 & 1363 \\ \hline 1135 & 1137 & 1143 & 1154 & 1166 \\ \hline 1214 & 1215 & 1219 & 1219 & 1228 \\ \hline 1270 & 1279 & 1293 & 1294 & 1295 \\ \hline 1377 & 1402 & 1419 & 1440 & 1514 \\ \hline \end{array} $$ (a) Draw a normal probability plot to determine if the data could have come from a normal distribution. (b) Determine the mean and standard deviation of the sample data. (c) Using the sample mean and sample standard deviation obtained in part (b) as estimates for the population mean and population standard deviation, respectively, draw a graph of a normal model for the distribution of chips in a bag of Chips Ahoy! (d) Using the normal model from part (c), find the probability that an 18-ounce bag of Chips Ahoy! selected at random contains at least 1000 chips. (e) Using the normal model from part (c), determine the proportion of 18 -ounce bags of Chips Ahoy! that contains between 1200 and 1400 chips, inclusive.

The lives of refrigerators are normally distributed with mean \(\mu=14\) years and standard deviation \(\sigma=2.5\) years Source: Based on information from Consumer Reports (a) Draw a normal curve with the parameters labeled. (b) Shade the region that represents the proportion of refrigerators that last for more than 17 years. (c) Suppose the area under the normal curve to the right of \(x=17\) is 0.1151 . Provide two interpretations of this result.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.