/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 15 Suppose that \(E\) and \(F\) are... [FREE SOLUTION] | 91Ó°ÊÓ

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Suppose that \(E\) and \(F\) are two events and \(P(E)=0.9\) and \(P(F \mid E)=0.3 .\) Find \(P(E\) and \(F)\).

Short Answer

Expert verified
P(E \cap F) = 0.27

Step by step solution

01

Understand the Given Information

The problem provides the probabilities of two events, where: \[ P(E) = 0.9 \] and \[ P(F \,|\, E) = 0.3 \].
02

Recall the Definition of Conditional Probability

Conditional probability is defined as: \[P(F \,|\, E) = \frac{P(E \cap F)}{P(E)} \].
03

Rearrange the Formula to Solve for \(P(E \cap F)\)

Multiply both sides of the equation by \(P(E)\) to isolate \(P(E \cap F)\): \[ P(E \cap F) = P(F \,|\, E) \times P(E) \].
04

Substitute the Given Values

Using the provided values in the formula: \[ P(E \cap F) = 0.3 \times 0.9 \].
05

Perform the Calculation

Calculate the product to find \(P(E \cap F)\): \[ P(E \cap F) = 0.27 \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Events
In probability theory, an event represents a collection of outcomes from a particular experiment or situation. Think of it as a specific result or a set of results that you are interested in. Suppose you are rolling a die, one possible event could be rolling an even number. In this case, the events are getting a 2, 4, or 6. Since events can be anything specific happening, it’s important to name and define them clearly.

Events are usually denoted using capital letters like \(E\) and \(F\). When events are written mathematically, we use probability notation like \(P(E)\) to express that we are finding the probability of event \(E\) happening. For example, \(P(E) = 0.9\) means there's a 90% chance event \(E\) occurs. Understanding events in this clear manner can help avoid confusion later on.
Probability
Probability refers to the measure of how likely an event is to occur. It ranges from 0 to 1, where 0 indicates an impossible event and 1 indicates a certain event. For example, the probability of getting heads when flipping a fair coin is 0.5, or 50%. The probability of an event \(E\) is written as \(P(E)\).

Probability helps us quantify uncertainty and make informed decisions based on it. A common way to find probability is by considering all possible outcomes and the outcomes that are favorable to the event. If you had to roll a die, the probability of getting a number less than 4 would mean counting all favorable outcomes (1, 2, and 3) and then dividing by the total number of outcomes (6), hence \(P(E) = \frac{3}{6} = 0.5\).

In the provided exercise, \(P(E) = 0.9\) indicates there's a 90% chance that event \(E\) will happen.
Intersection of Events
The intersection of two events \(E\) and \(F\), denoted as \(E \triangle F\)m represents the situation where both events happen simultaneously. In other words, it is the set of all outcomes that are common to both events.

For instance, if event \(E\) is rolling an even number on a die, and event \(F\) is rolling a number greater than 3, the intersection of these events would be rolling a 4 or 6, since these are the only numbers that are both even and greater than 3. In mathematical terms, this intersection is expressed as \(P(E \triangle F)\).

In the provided exercise, we calculated the probability of the intersection of events \(E\) and \(F\). First, we used conditional probability \(P(F|E) = \frac{P(E \triangle F)}{P(E)}\) and then rearranged the formula to solve for \(P(E \triangle F)\): \(P(E \triangle F) = P(F|E) \times P(E)\). Finally, substituting the given values: \(P(E \triangle F) = 0.3 \times 0.9 = 0.27\). This means there is a 27% chance that both events happen together.

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