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Suppose that a digital music player has 13 tracks. After listening to all the songs, you decide that you like 5 of them. With the random feature on your player, each of the 13 songs is played once in random order. Find the probability that among the first two songs played (a) You like both of them. Would this be unusual? (b) You like neither of them. (c) You like exactly one of them. (d) Redo (a)-(c) if a song can be replayed before all 13 songs are played (if, for example, track 2 can play twice in a row).

Short Answer

Expert verified
(a) 0.128, not unusual. (b) 0.359. (c) 0.513. (d) With replacement: (a) 0.148, (b) 0.379, (c) 0.473.

Step by step solution

01

Calculate total number of ways to pick 2 songs

The total number of ways to choose 2 songs out of 13 is given by the combination formula \[ C(n, k) = \frac{n!}{k!(n-k)!} \] where n = 13 and k = 2. Therefore, \[ C(13, 2) = \frac{13!}{2!(13-2)!} = 78 \] There are 78 ways to pick 2 songs out of 13.
02

Calculate the probability of liking both (a)

The number of ways to choose 2 liked songs out of 5 is given by how many combinations of 2 you can form out of the 5 liked songs. Therefore, \[ C(5, 2) = \frac{5!}{2!(5-2)!} = 10 \] The probability is the ratio of the favorable outcomes to the total outcomes: \[ P(A) = \frac{C(5, 2)}{C(13, 2)} = \frac{10}{78} = \frac{5}{39} \approx 0.128 \] So, the probability is approximately 0.128. Since probabilities less than 0.05 are often considered unusual, this probability of 0.128 is not unusual.
03

Calculate the probability of liking neither (b)

The number of ways to choose 2 not liked songs out of 8 is found similarly. Therefore, \[ C(8, 2) = \frac{8!}{2!(8-2)!} = 28 \] The probability is: \[ P(B) = \frac{C(8, 2)}{C(13, 2)} = \frac{28}{78} = \frac{14}{39} \approx 0.359 \] So, the probability is approximately 0.359.
04

Calculate the probability of liking exactly one (c)

To like exactly one song out of two, you can either like the first song and not like the second one, or not like the first song and like the second one. The calculations are: If the first song is liked and the second is not liked: \[ P(C_1) = \frac{5}{13} \times \frac{8}{12} = \frac{5}{13} \times \frac{2}{3} = \frac{10}{39} \] If the first song is not liked and the second is liked: \[ P(C_2) = \frac{8}{13} \times \frac{5}{12} = \frac{8}{13} \times \frac{5}{12} = \frac{10}{39} \] Therefore, total probability is: \[ P(C) = P(C_1) + P(C_2) = \frac{10}{39} + \frac{10}{39} = \frac{20}{39} \approx 0.513 \] So, the probability is approximately 0.513.
05

Redo calculations if songs can be replayed (d)

(a) Probability of liking both songs with replacement: The probability of liking the first song is \( \frac{5}{13} \) and the probability of liking the second song is also \( \frac{5}{13} \): \[ P(A) = \frac{5}{13} \times \frac{5}{13} = \frac{25}{169} \approx 0.148 \] (b) Probability of liking neither song with replacement: The probability of not liking the first song is \( \frac{8}{13} \) and the probability of not liking the second song is also \( \frac{8}{13} \): \[ P(B) = \frac{8}{13} \times \frac{8}{13} = \frac{64}{169} \approx 0.379 \] (c) Probability of liking exactly one song with replacement: Probability of liking the first song and not liking the second song: \[ P(C_1) = \frac{5}{13} \times \frac{8}{13} = \frac{40}{169} \] Probability of not liking the first song and liking the second song: \[ P(C_2) = \frac{8}{13} \times \frac{5}{13} = \frac{40}{169} \] Therefore, total probability is: \[ P(C) = P(C_1) + P(C_2) = \frac{40}{169} + \frac{40}{169} = \frac{80}{169} \approx 0.473 \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

combinations and permutations
Combinations and permutations are fundamental concepts in probability. Both are methods to count the possible arrangements of a certain number of items, but they differ in whether the order of items matters.

Combinations are selections of items where the order does not matter. If you are picking 2 songs out of 13, you use the combination formula: \[ C(n, k) = \frac{n!}{k!(n-k)!} \]
This formula counts the number of ways to choose k items from a set of n items without considering the order. For example, choosing 2 songs out of 13: \[ C(13, 2) = \frac{13!}{2!(13-2)!} = 78 \]
There are 78 ways to pick 2 songs without worrying about the order.

Permutations involve selections where the order does matter. For instance, if you care about the arrangement of the two songs, you'd use permutations. Permutations have a higher count because the same items can be arranged in different ways.

Understanding the difference between combinations and permutations helps in calculating probabilities correctly.
dependent and independent events
Determining whether events are dependent or independent is crucial in probability calculations.

Independent events are those whose outcomes do not affect each other. For example, when using a digital music player that replays songs, the probability of any song being played is always the same, regardless of previous selections.
In mathematical terms: \[ P(A) \text{ and } P(B) \text{ are independent if } P(A \cap B) = P(A) \times P(B) \]

Dependent events are those where the outcome of one event influences the other. With a music player that doesn't replay songs, the choice of the first song affects what can be chosen next. The probability of the second song changes based on the first pick.
For example: \[ P(A \text{ and } B) = P(A) \times P(B|A) \]
This means the probability of event B occurring, given that A has occurred, is different than if they were independent.

Recognizing the nature of events helps in applying the correct formulas and understanding the scenarios better.
probability with replacement
Probability calculations change significantly when considering replacement.

Probability with replacement occurs when each selected item is put back before making another selection. This keeps the total number of items constant, and all probabilities remain unchanged.
For example, if the player can replay songs, the probability of liking a song on each draw remains the same throughout: \[ P(\text{liking both}) = \frac{5}{13} \times \frac{5}{13} = \frac{25}{169} \]

Probability without replacement means selected items are not placed back, reducing the number of items with each draw. This changes the probability for subsequent selections.
For example, the probability of liking the first and not liking the second song when songs are not replayed is: \[ P(\text{liking first}) = \frac{5}{13}, \ P(\text{not liking second}) = \frac{8}{12} \]
Thus: \[ P(\text{like first and not like second}) = \frac{5}{13} \times \frac{8}{12} = \frac{10}{39} \]

Understanding the difference between with and without replacement is essential for accurate probability calculations in real-world scenarios.

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