/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 27 According to the U.S. Census Bur... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

According to the U.S. Census Bureau, \(20.2 \%\) of American women aged 25 years or older have a Bachelor's Degree; \(16.5 \%\) of American women aged 25 years or older have never married; among American women aged 25 years or older who have never married, \(22.8 \%\) have a Bachelor's Degree; and among American women aged 25 years or older who have a Bachelor's Degree, \(18.6 \%\) have never married. (a) Are the events "have a Bachelor's Degree" and "never married" independent? Explain. (b) Suppose an American woman aged 25 years or older is randomly selected, what is the probability she has a Bachelor's Degree and has never married? Interpret this probability.

Short Answer

Expert verified
a) Events are not independent.b) Probability is approximately 3.76%. This means there is a 3.76% chance that both conditions are met.

Step by step solution

01

- Define Events

Define the events: Let A be the event that a woman has a Bachelor's Degree and B be the event that a woman has never married.
02

- Given Probabilities

List the given probabilities: - P(A) = 0.202 - P(B) = 0.165 - P(A|B) = 0.228 - P(B|A) = 0.186
03

- Determine Independence

Determine if events A and B are independent. For events to be independent, P(A|B) should equal P(A) and P(B|A) should equal P(B). Check P(A|B): P(A|B) = 0.228 P(A) = 0.202 Since P(A|B) \( e \) P(A), events A and B are not independent.
04

- Probability of Intersection

Calculate the probability of both events occurring using the multiplication rule: P(A ∩ B) = P(A|B) * P(B) or P(B|A) * P(A) Using P(A|B) and P(B): P(A ∩ B) = 0.228 * 0.165 = 0.03762 Alternative check with P(B|A) and P(A): P(A ∩ B) = 0.186 * 0.202 = 0.037572 Both methods confirm P(A ∩ B) ≈ 0.0376
05

- Interpret the Probability

Interpret the probability P(A ∩ B) ≈ 0.0376. This means there is approximately a 3.76% chance that a randomly selected American woman aged 25 years or older both has a Bachelor's Degree and has never married.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conditional Probability
Conditional probability is a concept that describes the likelihood of an event occurring, given that another event has already happened. In simpler terms, it's asking 'what are the chances of event A happening, if we know that event B has already occurred?'. The formula for conditional probability is given by:
\( P(A|B) = \frac{P(A ∩ B)}{P(B)} \)
In this exercise, we looked at the probability of an American woman having a Bachelor's Degree, given that she has never married, and vice versa. By examining the given probabilities, we determined that:
- \( P(A|B) = 0.228 \)
This means there is a 22.8% chance she has a Bachelor's Degree if we've already established that she has never married.
It helps in understanding how one condition affects the likelihood of another event.
This is crucial when determining if two events are independent or dependent.
Intersection of Events
The intersection of events in probability refers to the scenario where both events A and B occur at the same time. It is denoted by \( A ∩ B \). In this exercise, we found the probability of both having a Bachelor's Degree and never marrying, represented as \( P(A ∩ B) \). We can determine this probability using either conditional probabilities \( P(A|B) \) and \( P(B) \), or \( P(B|A) \) and \( P(A) \).
For example:
\( P(A ∩ B) = P(A|B) \times P(B) \)
Substituting the values:
\( P(A ∩ B) = 0.228 * 0.165 = 0.03762 \)
Hence, the probability that a woman both has a Bachelor's Degree and has never married is approximately 3.76%. This intersection helps us understand how two dependent or independent events align in the probability scope.
Dependent Events
Events are termed dependent when the occurrence of one affects the likelihood of the other. This means that the outcome of event A will influence the probability of event B happening. In our exercise, to determine if the events 'having a Bachelor's Degree' and 'never married' are dependent, we compared the conditional probabilities with the given individual probabilities:
  • \( P(A|B) = 0.228 \)
  • \( P(A) = 0.202 \)
We noticed that \( P(A|B) \) is not equal to \( P(A) \), meaning the events are not independent. Therefore, 'having a Bachelor's Degree' and 'never married' are dependent events, as knowing whether a woman has never married changes the probability of her having a Bachelor's Degree, and vice versa. Understanding dependent events is vital because it affects how we calculate combined probabilities and interpret data in real-world scenarios.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Because of a manufacturing error, three cans of regular soda were accidentally filled with diet soda and placed into a 12 -pack. Suppose that two cans are randomly selected from the 12 -pack. (a) Determine the probability that both contain diet soda. (b) Determine the probability that both contain regular soda. Would this be unusual? (c) Determine the probability that exactly one is diet and one is regular?

According to the U.S. National Center for Health Statistics, \(0.15 \%\) of deaths in the United States are 25 - to 34-year-olds whose cause of death is cancer. In addition, \(1.71 \%\) of all those who die are \(25-34\) years old. What is the probability that a randomly selected death is the result of cancer if the individual is known to have been \(25-34\) years old?

The distribution of National Honor Society members among the students at a local high school is shown in the table. A student's name is drawn at random. $$ \begin{array}{lcc} \text { Class } & \text { Total } & \text { National Honor Society } \\ \hline \text { Senior } & 92 & 37 \\ \hline \text { Junior } & 112 & 30 \\ \hline \text { Sophomore } & 125 & 20 \\ \hline \text { Freshman } & 120 & 0 \\ \hline \end{array} $$ (a) What is the probability that the student is a junior? (b) What is the probability that the student is a senior, given that the student is in the National Honor Society?

Find the value of each combination. $$ { }_{10} C_{2} $$

Suppose that you just received a shipment of six televisions and two are defective. If two televisions are randomly selected, compute the probability that both televisions work. What is the probability that at least one does not work?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.