/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 7 The following data represent the... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The following data represent the measure of a variable before and after a treatment. $$\begin{array}{lccccc}\text { Individual } & \mathbf{1} & \mathbf{2} & \mathbf{3} & \mathbf{4} & \mathbf{5} \\\\\hline \text { Before, } X_{i} & 93 & 102 & 90 & 112 & 107 \\\\\hline \text { After, } Y_{i} & 95 & 100 & 95 & 115 & 107 \\\\\hline\end{array}$$ Does the sample evidence suggest that the treatment is effective in increasing the value of the response variable? Use the \(\alpha=0.05\) level of significance. Note: Assume that the differenced data come from a population that is normally distributed with no outliers.

Short Answer

Expert verified
The treatment is effective based on the significance level of 0.05.

Step by step solution

01

- State the hypotheses

The null hypothesis (
02

Data Preparation

List the 'Before' and 'After' treatment measures.
03

Hypothesis Testing

Choose appropriate test for the provided data.
04

Conclusion

Interpret the results.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Paired Sample t-test
The paired sample t-test is a statistical method used to determine if there is a significant difference between the means of two related groups. In our case, the two related groups are the 'Before' and 'After' treatment measures for the same individuals. This test is particularly useful when you want to compare two conditions or time points for the same subjects. Here’s a step-by-step outline of how it works:
  • Calculate the difference between 'Before' and 'After' measures for each individual.
  • Find the mean and standard deviation of these differences.
  • Use these values to compute the t-statistic, which tells you how much the mean difference deviates from zero.
  • Compare the t-statistic to a critical value from the t-distribution table, based on your chosen level of significance and degrees of freedom (number of pairs minus one).
This test assumes that the differences between pairs are normally distributed. More about this important concept in our normal distribution section.
Level of Significance
Level of significance, often denoted as \(\alpha\), is a threshold set by the researcher which defines the probability of rejecting the null hypothesis when it is actually true, also known as a Type I error. In simpler terms, it determines how confident you want to be in your results before concluding that your findings are statistically significant.
  • Common levels of significance used are 0.05, 0.01, and 0.10. In this exercise, we use \(\alpha=0.05\), meaning we are willing to accept up to a 5% probability of making a Type I error.
  • If the p-value (calculated from your test statistic) is lower than your \(\alpha\), you reject the null hypothesis.
  • Conversely, if the p-value is higher, you do not reject the null hypothesis.
This helps you decide whether the observed effect is statistically significant or if it could have happened by random chance.
Normal Distribution
The normal distribution is a key concept in statistics, often referred to as the bell curve due to its shape. It is symmetric about its mean, with data values more concentrated around the mean and sparser the further away you go. For the paired sample t-test to be valid, the differences between pairs should be normally distributed. Here’s why normal distribution is important and some of its properties:
  • Symmetry: The left and right halves of a normal distribution are mirror images of each other.
  • Central Peak: The highest point on the curve is the mean, median, and mode of the data.
  • Empirical Rule: Approximately 68% of data falls within one standard deviation of the mean, 95% within two standard deviations, and 99.7% within three standard deviations.
In practice, if you plot the differences between 'Before' and 'After' measures and they form this bell shape, your data likely follows a normal distribution. This ensures that the assumptions of the paired sample t-test are met, making your results valid and reliable.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Kids and Leisure Young children require a lot of time and this time commitment cuts into a parent's leisure time. A sociologist wanted to estimate the difference in the amount of daily leisure time (in hours) of adults who do not have children under the age of 18 years and adults who have children under the age of 18 years. A random sample of 40 adults with no children under the age of 18 years results in a mean daily leisure time of 5.62 hours, with a standard deviation of 2.43 hours. A random sample of 40 adults with children under the age of 18 years results in a mean daily leisure time of 4.10 hours, with a standard deviation of 1.82 hours. Construct and interpret a \(90 \%\) confidence interval for the mean difference in leisure time between adults with no children and adults with children. Source: American Time Use Survey

Clifford Adelman, a researcher with the Department of Education, followed a cohort of students who graduated from high school in \(1992,\) monitoring the progress the students made toward completing a bachelor's degree. One aspect of his research was to compare students who first attended a community college to those who immediately attended and remained at a four-year institution. The sample standard deviation time to complete a bachelor's degree of the 268 students who transferred to a four-year school after attending community college was \(1.162 .\) The sample standard deviation time to complete a bachelor's degree of the 1145 students who immediately attended and remained at a four-year institution was \(1.015 .\) Assuming the time to earn a bachelor's degree is normally distributed, does the evidence suggest the standard deviation time to earn a bachelor's degree is different between the two groups? Use the \(\alpha=0.05\) level of significance.

A researcher wants to know if students who do not plan to apply for financial aid had more variability on the SAT I math test than those who plan to do so. She obtains a random sample of 35 students who do not plan to apply for financial aid and a random sample of 38 students who do plan to apply for financial aid and obtains the following results: $$ \begin{array}{cc} \begin{array}{l} \text { Do Not Plan to Apply } \\ \text { for Financial Aid } \end{array} & \begin{array}{l} \text { Plan to Apply } \\ \text { for Financial Aid } \end{array} \\ \hline n_{1}=35 & n_{2}=38 \\ \hline s_{1}=123.1 & s_{2}=119.4 \\ \hline \end{array} $$ Do students who do not plan to apply for financial aid have a higher standard deviation on the SAT I math exam than students who plan to apply for financial aid at the \(\alpha=0.01\) level of significance? SAT I math exam scores are known to be normally distributed.

The following data represent the muzzle velocity (in feet per second) of rounds fired from a 155 -mm gun. For each round, two measurements of the velocity were recorded using two different measuring devices, with the following data obtained: $$ \begin{array}{ccccccc} \text { Observation } & \mathbf{1} & \mathbf{2} & \mathbf{3} & \mathbf{4} & \mathbf{5} & \mathbf{6} \\ \hline \mathbf{A} & 793.8 & 793.1 & 792.4 & 794.0 & 791.4 & 792.4 \\ \hline \mathbf{B} & 793.2 & 793.3 & 792.6 & 793.8 & 791.6 & 791.6 \\ \hline \end{array} $$ $$ \begin{array}{ccccccc} \text { Observation } & 7 & 8 & 9 & 10 & 11 & 12 \\ \hline \text { A } & 791.7 & 792.3 & 789.6 & 794.4 & 790.9 & 793.5 \\ \hline \text { B } & 791.6 & 792.4 & 788.5 & 794.7 & 791.3 & 793.5 \\ \hline \end{array} $$ (a) Why are these matched-pairs data? (b) Is there a difference in the measurement of the muzzle velocity between device \(A\) and device \(B\) at the \(\alpha=0.01\) level of significance? Note: A normal probability plot and boxplot of the data indicate that the differences are approximately normally distributed with no outliers. (c) Construct a \(99 \%\) confidence interval about the population mean difference. Interpret your results. (d) Draw a boxplot of the differenced data. Does this visual evidence support the results obtained in part (b)?

In an experiment conducted online at the University of Mississippi, study participants are asked to react to a stimulus. In one experiment, the participant must press a key on seeing a blue screen and reaction time (in seconds) to press the key is measured. The same person is then asked to press a key on seeing a red screen, again with reaction time measured. The results for six randomly sampled study participants are as follows: $$ \begin{array}{lcccccc} \text { Participant } & \mathbf{1} & \mathbf{2} & \mathbf{3} & \mathbf{4} & \mathbf{5} & \mathbf{6} \\ \hline \text { Blue } & 0.582 & 0.481 & 0.841 & 0.267 & 0.685 & 0.450 \\ \hline \text { Red } & 0.408 & 0.407 & 0.542 & 0.402 & 0.456 & 0.533 \\ \hline \end{array} $$ (a) Why are these matched-pairs data? (b) In this study, the color that the participant was first asked to react to was randomly selected. Why is this a good idea in this experiment? (c) Is the reaction time to the blue stimulus different from the reaction time to the red stimulus at the \(\alpha=0.01\) level of significance? Note: A normal probability plot and boxplot of the data indicate that the differences are approximately normally distributed with no outliers. (d) Construct a \(99 \%\) confidence interval about the population mean difference. Interpret your results. (e) Draw a boxplot of the differenced data. Does this visual evidence support the results obtained in part (c)?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.