91影视

The combination formula is$$\begin{gathered} \left(\mathbf{N} \\ \mathbf{r} \\ \right)\mathbf{=}\frac{\mathbf{N}\mathbf{!}}{\mathbf{r}\mathbf{!}\mathbf{(}\mathbf{N}-\mathbf{r}\mathbf{)}\mathbf{!}} \end{gathered}$$

According to the given information, since an ace can be drawn 4 times and a face card can be drawn 12 times, then $\left(4\right)\left(12\right)=48$

So, there are 48 different ways.

Here total cards are 52, and 2 two cards are drawn. To get the result use a combination formula.

$$\begin{gathered} \begin{array}{rcl}\left(N \\ r \\ \right)& =& \frac{N!}{r!鈥�\left(N-r\right)!}\\ & =& \frac{52!}{2!\left(52-2\right)! \\ =\frac{52!}{2!50!} \\ =1326 \\ }\\ & & \end{array} \end{gathered}$$

$$\begin{gathered} \mathbf{P}\mathbf{\left(}\mathbf{DB}\mathbf{\right)}\mathbf{=}\frac{\mathbf{48}}{\mathbf{1326}} \\ \mathbf{=}\mathbf{0}\mathbf{.}\mathbf{0362} \end{gathered}$$

Hence, the probability that the dealer will draw a blackjack is 0.0362

To the given information, an ace can be drawn 4 times, and a 3-face card can be drawn 11 times$\left(3\right)\left(11\right)=33$

So, there are 33 different ways.

Here total cards are 50, and 2 two cards are drawn. To get the result use a combination formula.

$$\begin{gathered} \begin{array}{rcl}\left(N \\ r \\ \right)& =& \frac{N!}{r!鈥�\left(N-r\right)!}\\ & =& \frac{50!}{2!\left(50-2\right)!}\\ & =& \frac{52!}{2!鈥�48!}\\ & =& 1225\\ & & \end{array} \end{gathered}$$

Now,

$\begin{array}{rcl}P\left(B{J}^C|PLAYER\right)& =& 1-\frac{33}{1225}\\ & =& \frac{1192}{1225}\\ & =& 0.973\\ & & \end{array}$

$$\begin{gathered} \mathbf{P}\mathbf{(}\mathbf{player}鈭�{\mathbf{Dealernotdrawablackjck}}^{\mathbf{c}}\mathbf{)}\mathbf{=}\mathbf{0}\mathbf{.}\mathbf{0362}\mathbf{(}\mathbf{0}\mathbf{.}\mathbf{973}\mathbf{)} \\ \mathbf{=}\mathbf{0}\mathbf{.}\mathbf{0352} \end{gathered}$$

Therefore, the probability that the player wins with blackjack is 0.0352.