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$$\begin{gathered} {\mathbf{R}}^{\mathbf{2}}\mathbf{=}\mathbf{1}\mathbf{-}\frac{\mathbf{SSE}}{{\mathbf{SS}}_{\mathbf{yy}}} \\ \mathbf{=}\mathbf{1}\mathbf{-}\frac{\mathbf{21}}{\mathbf{479}} \\ \mathbf{=}\mathbf{0}\mathbf{.}\mathbf{95615} \end{gathered}$$

The value of${\mathbf{R}}^{\mathbf{2}}$close to 95% indicates that almost 95% of the variation in the variables can be explained by the model.

${\mathbf{H}}_{\mathbf{0}}\mathbf{:}{\mathbf{尾}}_{\mathbf{1}}\mathbf{=}{\mathbf{尾}}_{\mathbf{2}}\mathbf{=}{\mathbf{尾}}_{\mathbf{3}}\mathbf{=}\mathbf{0}$

${\mathbf{H}}_{\mathbf{a}}:$At least one of the parameters ${\mathbf{尾}}_{\mathbf{1}},{\mathbf{尾}}_{\mathbf{2}},{\mathbf{尾}}_{\mathbf{3}}$ is non zero

Here, F test statistic $\mathbf{=}\frac{\mathbf{SSe}}{\mathbf{n}\mathbf{-}\mathbf{(}\mathbf{k}\mathbf{+}\mathbf{1}\mathbf{)}}\mathbf{=}\frac{\mathbf{21}}{\mathbf{32}\mathbf{-}\mathbf{4}}\mathbf{=}\mathbf{0}\mathbf{.}\mathbf{75}$

Value of ${\mathbf{F}}_{\mathbf{0}\mathbf{.}\mathbf{05}\mathbf{,}\mathbf{28}\mathbf{,}\mathbf{28}}$ is 1.915

${\mathbf{H}}_{\mathbf{0}}$is rejected if F statistic > ${\mathbf{F}}_{\mathbf{0}\mathbf{.}\mathbf{05}\mathbf{,}\mathbf{28}\mathbf{,}\mathbf{28}}$. For $\mathbf{伪}\mathbf{=}\mathbf{0}\mathbf{.}\mathbf{05}$, since F < ${\mathbf{F}}_{\mathbf{0}\mathbf{.}\mathbf{05}\mathbf{,}\mathbf{28}\mathbf{,}\mathbf{28}}$

We do not have sufficient evidence to reject ${\mathbf{H}}_{\mathbf{0}}$ at a 95% confidence interval.

$\mathbf{Therefore}\mathbf{,}$ ${\mathbf{尾}}_{\mathbf{1}}\mathbf{=}{\mathbf{尾}}_{\mathbf{2}}\mathbf{=}{\mathbf{尾}}_{\mathbf{3}}\mathbf{=}\mathbf{0}$

When there鈥檚 an interaction term in the model, the model is estimated assuming one variable constant, and the relationship between the dependent and the other independent variable is plotted given the value of an independent variable.

In this case, two lines are plotted, where one line is drawn assuming ${\mathbf{x}}_{\mathbf{2}}$ as constant ${\mathbf{K}}_{\mathbf{1}}$ and the other line is drawn assuming ${\mathbf{x}}_{\mathbf{1}}$ constant as ${\mathbf{t}}_{\mathbf{1}}$ Since these two variables are interacting, it can be seen in the graph that the regression lines will interact at some point on the Cartesian graph.

${\mathbf{H}}_{\mathbf{0}}\mathbf{:}{\mathbf{尾}}_{\mathbf{3}}\mathbf{=}\mathbf{0}$

${\mathbf{H}}_{\mathbf{0}}\mathbf{:}{\mathbf{尾}}_{\mathbf{3}}鈮�\mathbf{0}$

Here, t-test statistic $\mathbf{=}\frac{{\widehat{\mathbf{尾}}}_{\mathbf{3}}}{\mathbf{s}{\widehat{\mathbf{尾}}}_{\mathbf{3}}}\mathbf{=}\frac{\mathbf{10}}{\mathbf{4}}\mathbf{=}\mathbf{2}\mathbf{.}\mathbf{5}$

Value of ${\mathbf{t}}_{\mathbf{0}\mathbf{.}\mathbf{05}\mathbf{,}\mathbf{31}}$ is 1.6955

${\mathbf{x}}_{\mathbf{1}}{\mathbf{H}}_{\mathbf{0}}$is rejected if statistic >${\mathbf{t}}_{\mathbf{0}\mathbf{.}\mathbf{05}\mathbf{,}\mathbf{24}\mathbf{,}\mathbf{24}}$. For, Since t > ${\mathbf{t}}_{\mathbf{0}\mathbf{.}\mathbf{05}\mathbf{,}\mathbf{31}}$

Sufficient evidence to reject ${\mathbf{H}}_{\mathbf{0}}$ at 95% confidence interval.

Therefore,${\mathbf{尾}}_{\mathbf{3}}鈮�\mathbf{4}$ . Hene it can be concluded with enough evidence that ${\mathbf{x}}_{\mathbf{1}}$ and ${\mathbf{x}}_{\mathbf{2}}$ interact in the model.