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The following model was used to relate E(y) to a single qualitative variable with four levels:E(y)=β0+β1x1+β2x2+β3x3where

x1=1iflevel20ifnotx2=1iflevel30ifnotx3=1iflevel40ifnot

This model was fit to n = 30 data points, and the following result was obtained:

y^=10.2-4x1+12x2+2x3

  1. Use the least-squares prediction equation to find the estimate of E(y) for each level of the qualitative independent variable.
  2. Specify the null and alternative hypotheses you would use to test whether E(y) is the same for all four levels of the independent variable.

Short Answer

Expert verified

a.For x1=1,x2=0and x3=0;

y^=10.2-4(1)+12(0)+2(0)=6.2


For x2=1,x1=0and x3=0

y^=10.2-4(0)+12(1)+2(0)=1.8


. Forx3=1,x1=0andx2=0

y^=10.2-4(0)+12(0)+2(1)=8.2

b. The hypothesis to be tested can be written asH0:β1=β2=β3=0

Ha:At least one of the parameters β1,β2andβ3differfrom0

Step by step solution

01

Mean values for each level of the qualitative independent variable

The value E(Y) for a different level of the qualitative independent variable

Can be found by substituting in place of other two variables

Forx1=1,x2=0andx3=0;

y^=10.2-4(1)+12(0)+2(0)=6.2

Forx2=1,x1=0,andx3=0;

y^=10.2-4(0)+12(1)+2(0)=1.8

Forx3=1,x1=0,andx2=0;

y^=10.2-4(0)+12(0)+2(1)=8.2

02

Hypothesis testing

Here, the null hypothesis becomes that the means for the three groups are equal meaning μ1=μ2=μ3while the alternate hypothesis implies that at least two of the three means (μ1,μ2,and μ3) differ.

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