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Consider the following sample of five measurements: 2, 1, 1, 0, 3.

a.Calculate the range, s2, and s.

b.Add 3 to each measurement and repeat part a.

c.Subtract 4 from each measurement and repeat part a.

d.Considering your answers to parts a, b, and c, what seems to be the effect on the variability of a data set by adding the same number to or subtracting the same number from each measurement?

Short Answer

Expert verified
  1. Range = 3, s2 = 1.3, s = 1.14
  2. Range = 3, s2 = 1.3, s = 1.14
  3. Range = 3, s2 = 1.3, s = 1.14
  4. There is no effect.

Step by step solution

01

 Step 1: Calculating the range, s2, and s

Range = 3 – 0 = 3

s2 = 1.3

s = 1.14

x¯=2+1+1+0+35=75=1.4s2=∑(x-x¯)2n-1=(2-1.4)2+(1-1.4)2+(1-1.4)2+(0-1.4)2+(3-1.4)25-1=0.36+0.16+0.16+1.96+2.564=5.24=1.3s=s2=1.3=1.14

02

Adding 3 to each measurement and repeating Step 1

After adding 3, the new measurements are as follows:

5, 4, 4, 3, 6

x¯=5+4+4+3+65=225=4.4s2=∑(x-x¯)2n-1=(5-4.4)2+(4-4.4)2+(4-4.4)2+(3-4.4)2+(6-4.4)25-1=0.36+0.16+0.16+1.96+2.564=5.24=1.3s=s2=1.3=1.14

Range = 6 – 3 = 3

s2 = 1.3

s = 1.14

03

Subtracting 4 from each measurement and repeating Step 1

After subtracting 4, we get,

-2, -3, -3, -4, -1

x¯=(-2)+(-3)+(-3)+(-4)+(-1)5=-135=-2.6s2=∑(x-x¯)2n-1=(-2--2.6)2+(-3--2.6)2+(-3--2.6)2+(-4--2.6)2+(-1--2.6)25-1=0.36+0.16+0.16+1.96+2.564=5.24=1.3s=s2=1.3=1.14

Range = 6 – 3 = 3

s2 = 1.3

s = 1.14

04

Comparing results from a, b and c

There is no effect on the variability of a data set by adding the same number to or subtracting the same number from each measurement. All values remain constant.

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