91影视

$\begin{array}{c}\frac{{\displaystyle 鈭�\text{蠂}}}{\text{n}}\\ \text{=}\frac{\text{4+6+6+5+6+7}}{\text{6}}\\ \text{=}\frac{\text{34}}{\text{6}}\\ \text{=5.66}\end{array}$

$\begin{array}{c}{\text{s}}^{\text{2}}\text{=}\frac{{\displaystyle 鈭�{\left(\text{蠂}鈭�\right)}^2}}{\text{n}鈭�\text{1}}\\ \text{=}\frac{{\left(\text{4}鈭�\text{5.66}\right)}^{\text{2}}\text{+}{\left(\text{6}鈭�\text{5.66}\right)}^{\text{2}}\text{+}{\left(\text{6}鈭�\text{5.66}\right)}^{\text{2}}\text{+}{\left(\text{5}鈭�\text{5.66}\right)}^{\text{2}}\text{+}{\left(\text{6}鈭�\text{5.66}\right)}^{\text{2}}\text{+}{\left(\text{7}鈭�\text{5.66}\right)}^{\text{2}}}{\text{6}鈭�\text{1}}\\ \text{=}\frac{\text{2.7556+0.1156+0.1156+0.4356+0.1156+1.7956}}{\text{5}}\\ \text{=}\frac{\text{5.3336}}{\text{5}}\end{array}$

$\text{=1.066}$

$\begin{array}{c}\text{s=}\sqrt{{\text{s}}^{\text{2}}}\\ \text{=}\sqrt{\text{1.066}}\\ \text{=1.03}\end{array}$

Therefore, mean = 5.66, s² = 1.066, s = 1.03

$\begin{array}{c}\frac{{\displaystyle 鈭�\text{蠂}}}{\text{n}}\\ \text{=}\frac{鈭�\text{1+4+(}鈭�\text{3)+0+(}鈭�\text{3)+(}鈭�\text{6)}}{\text{6}}\\ \text{=}\frac{鈭�\text{9}}{\text{6}}\\ \text{=}鈭�\text{1.5}\end{array}$

$\begin{array}{c}{\text{s}}^{\text{2}}=\frac{{\displaystyle 鈭�{\left(\text{蠂}鈭�\right)}^2}}{\text{n}鈭�\text{1}}\\ \text{=}\frac{{\left(\left(鈭�\text{1}\right)鈭�\left(鈭�\text{1.5}\right)\right)}^{\text{2}}\text{+}{\left(\text{4}鈭�\left(鈭�\text{1.5}\right)\right)}^{\text{2}}\text{+}{\left(\left(鈭�\text{3}\right)鈭�\left(鈭�\text{1.5}\right)\right)}^{\text{2}}\text{+}{\left(\text{0}鈭�\left(鈭�\text{1.5}\right)\right)}^{\text{2}}\text{+}{\left(\left(鈭�\text{3}\right)鈭�\left(鈭�\text{1.5}\right)\right)}^{\text{2}}\text{+}{\left(\left(鈭�\text{6}\right)鈭�\left(鈭�\text{1.5}\right)\right)}^{\text{2}}}{\text{6}鈭�\text{1}}\\ \text{=}\frac{\text{0.25+30.25+3+3+3+20.25}}{\text{5}}\\ \text{=}\frac{\text{59.75}}{\text{5}}\\ \text{=11.95}\end{array}$

$\begin{array}{c}\text{s=}\sqrt{{\text{s}}^{\text{2}}}\\ \text{=}\sqrt{\text{11.95}}\\ \text{=3.45}\end{array}$

Therefore, mean = -$1.5, s² = 11.95, s = $3.45

$\begin{array}{c}\frac{{\displaystyle 鈭�\text{蠂}}}{\text{n}}\\ =\frac{0.6+0.8+0.4+0.2+0.0625}{5}\\ =\frac{2.0625}{5}\\ =0.4125\%\end{array}$

$\begin{array}{c}{\text{s}}^{\text{2}}=\frac{{\displaystyle 鈭�{\left(\text{蠂}鈭�\right)}^2}}{\text{n}鈭�\text{1}}\\ =\frac{{\left(0.6鈭�0.4125\right)}^2+{\left(0.8鈭�0.4125\right)}^2+{\left(0.4鈭�0.4125\right)}^2+{\left(0.2鈭�0.4125\right)}^2+{\left(0.0625鈭�0.4125\right)}^2}{5鈭�1}\\ =\frac{0.035+0.15+0.00015+0.045+0.1225}{4}\\ =\frac{0.35}{4}\end{array}$

$\text{=0.088}$

$\begin{array}{c}\text{s=}\sqrt{{\text{s}}^{\text{2}}}\\ \text{=}\sqrt{\text{0.088}}\\ \text{=0.29\%}\end{array}$

Therefore, mean = 0.4125%, s² = 0.088, s = 0.29%

$\begin{array}{c}{\text{s}}^{\text{2}}=\frac{{\displaystyle 鈭�{\left(\text{蠂}鈭�\right)}^2}}{\text{n}鈭�\text{1}}\\ =\frac{{\left(0.6鈭�0.4125\right)}^2+{\left(0.8鈭�0.4125\right)}^2+{\left(0.4鈭�0.4125\right)}^2+{\left(0.2鈭�0.4125\right)}^2+{\left(0.0625鈭�0.4125\right)}^2}{5鈭�1}\\ =\frac{0.035+0.15+0.00015+0.045+0.1225}{4}\\ =\frac{0.35}{4}\end{array}$

Range = Max 鈥� Min

$\begin{array}{c}\text{Range}=\text{Max}鈥�\text{Min}\\ =\text{7}鈥�\text{4}\\ =\text{3}\end{array}$