91影视

$\begin{array}{rcl}zscorehighestsalary& =& \frac{Max-Mean}{S\tan dardDeviation}\\ & =& \frac{\$75,000-\$52,334}{\$9,224}\\ & =& 2.45\end{array}$

The z-score for the highest salary is 2.45. Because the z-score is less than 3, it is a possible outlier.

$\begin{array}{rcl}zscorelowestsalary& =& \frac{Min-Mean}{S\tan dardDeviation}\\ & =& \frac{\$35,000-\$52,334}{\$9,224}\\ & =& -1.87\end{array}$

The z-score of the lowest salary indicates that it is not an outlier.

$\begin{array}{rcl}zscoremeansalary& =& \frac{Mean-Mean}{S\tan dardDeviation}\\ & =& \frac{\$52,334-\$52,334}{\$9,224}\\ & =& \frac{\$0}{\$9,224}\\ & =& 0\\ & & \end{array}$

The mean salary offer lies within the range and is not an outlier.

No, I would not consider the highest salary offer as unusually high because it is not an outlier and lies well within the 3 standard deviations from the mean range.

Suspect outliers lie between the inner and outer fences.

The inner fences are the first and the third quartiles. Therefore, Q_L = $45,725 and Q_U = $ 58,900.

The outer fences are approx. $75,000 and $35,000.

$\begin{array}{rcl}SuspectOutliers& =& Q_L-1.5\left(IQR\right)and{Q}_L-1.5\left(IQR\right)\\ & =& 45,725-1.5\left(13,175\right)and45,725-3\left(13,175\right)\\ & =& 45,725-19,762.5and45,725-39,525\\ & =& \$25,962.5and\$6,200\end{array}$

$\begin{array}{rcl}\mathrm{Suspect}\mathrm{Outliers}& =& {\mathrm{Q}}_{\mathrm{U}}+1.5\left(\mathrm{IQR}\right)\mathrm{and}{\mathrm{Q}}_{\mathrm{U}}+1.5\left(\mathrm{IQR}\right)\\ & =& 58,900+1.5\left(13,175\right)\mathrm{and}58,900+3\left(13,175\right)\\ & =& 58,900+19,762.5\mathrm{and}58,900+39,525\\ & =& \$78,662\mathrm{and}\$98,425\end{array}$

Any observations that lie between $25,962.5 and $6,200; and $78,662.5 and $98,425 are suspect outliers.

Highly suspect outliers lie above or below the outer fences.

Therefore, any observation above $75,000 and below $35,000 is a highly suspect outlier.