91影视

A hospital sample is chosen at random from one state

$$\begin{gathered} \text{n=}20 \\ \begin{array}{c}\text{Mean}\left(\stackrel{-}{蠂}\right)=3.8\text{days}\\ 蟽=1.2\text{days}\end{array} \end{gathered}$$

The calculation is given below:

$$\begin{gathered} \text{Thedegreesoffreedom=n}鈭�\text{1} \\ \text{=20}鈭�\text{1} \\ \text{=19} \end{gathered}$$

90% confidence interval using.

Hence, the confidence interval is 0.90

$\begin{array}{c}\text{1}鈭�鈭�\text{=0.90}\\ 鈭�\text{=0.1}\\ \frac{鈭�}{2}\text{=0.05}\end{array}$

The value ${\text{t}}_{\text{0.05,19}}$ is 1.729

localid="1651473954295" ${\stackrel{-}{蠂}}_{+鈭�\text{12}}\left(\frac{\text{S}}{\sqrt{\text{n}}}\right)$

$$\begin{gathered} \stackrel{-}{蠂}=3.8 \\ {\text{t}}_{鈭�\text{12}}=1.729 \\ \begin{array}{c}\text{S}=1,2\\ \text{n}=20\end{array} \end{gathered}$$

$\begin{array}{l}\text{=3.8}卤\text{1.729}\left(\frac{\text{1.2}}{\sqrt{\text{20}}}\right)\\ =\text{3.8}卤\text{1.729}脳0.2683\\ =\text{3.8}卤0.4638\\ =(3.3362,4.2638)\end{array}$

The 90 percent Confident interval for the population implies that the LOS for the state's hospitals is$3.3362\text{and}4.2638.$

In terms of this application, the interval.

Interpretation

90 percent confident that the populations mean length of remain (LOS) for the state鈥檚 hospitals$\left(渭\right)$lies among $3.3362\text{and}4.2638$.

The term 90% confidence interval. Equally generated intervals will include the genuine population mean score$\left(渭\right)$ is repeated sampling. A confidence interval expresses the likelihood that a number will fall within the upper as well as lower boundaries of a probability distribution.