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A manufacturer of car batteries claims that his batteries will last, on average, 3 years with a variance of 1 year. If 5 of these batteries have lifetimes of 1.9 \(2.4,3.0,3.5,\) and 4.2 years, construct a \(95 \%\) confidence interval for \(\sigma^{2}\) and decide if the manufacturer's claim that \(\sigma^{2}=1\) is valid. Assume the population of battery lives to be approximately normally distributed.

Short Answer

Expert verified
The calculated 95% confidence interval for the variance \(\sigma^{2}\) is [0.255, 5.01]. Since the manufacturer's claim of \(\sigma^{2} = 1\) lies within this interval, the claim is statistically acceptable.

Step by step solution

01

Identify Given Data

Given data consists of the sample received from the manufacturer. The sample size, \(n = 5\), and the sample values are 1.9, 2.4, 3.0, 3.5, and 4.2. Additionally, it is known that manufacturer claims \(\sigma^{2}=1\).
02

Calculate Sample Variance

First, calculate the sample mean. Then, compute the variance by summing the squared differences of each data point from the mean, and dividing by the number of data points minus 1. Mean = \(\frac{1.9+2.4+3.0+3.5+4.2}{5} = 3.0\), Variance = \(\frac{(1.9-3.0)^{2}+(2.4-3.0)^{2}+(3.0-3.0)^{2}+(3.5-3.0)^{2}+(4.2-3.0)^{2}}{4}= 0.605\).
03

Find Chi-square Critical Values

For a 95% confidence interval and a sample size of 5, degrees of freedom will be \(n - 1 = 4\). Looking these values up in a Chi-square table, the critical values are 0.484 and 9.488.
04

Calculate Confidence Interval

Use the critical values and the sample variance to calculate the confidence interval. The confidence interval for \(\sigma^{2}\) is \(\left[ \frac{(n-1) \cdot s^{2}}{X2 \text{ upper}}, \frac{(n-1) \cdot s^{2}}{X2 \text{ lower}} \right]\), which becomes \(\left[ \frac{4 \cdot 0.605}{9.488}, \frac{4 \cdot 0.605}{0.484} \right]\) or \([0.255, 5.01]\).
05

Evaluate Manufacturer's Claim

The manufacturer's claimed \(\sigma^{2} = 1\) lies within the calculated confidence interval (0.255, 5.01). Therefore, the claim is statistically valid.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Variance Calculation
Understanding the calculation of sample variance is crucial when assessing the variability of a dataset. In our example, to calculate the sample variance, we first determine the sample mean, which represents the average value of the data points. This is done by adding all the sample values and dividing the sum by the total number of observations.

Once we have the mean, the variance is calculated as the average of the squared differences between each data point and the sample mean. Mathematically, this is expressed as: \[\begin{equation}\text{Sample Variance } (s^2) = \frac{\sum_{i=1}^{n} (x_i - \bar{x})^2}{n-1}\end{equation}\] where \(x_i\) represents each value in the sample, \(\bar{x}\) is the sample mean, and \(n\) is the total number of observations. Importantly, we divide by \(n-1\) rather than \(n\) to account for the degrees of freedom in the sample—this corrects the bias in the estimation of the population variance from a sample. In our car batteries example, the calculation of sample variance was a crucial step for further analysis.
Chi-Square Distribution
The chi-square distribution plays a pivotal role when working with variance, especially in constructing confidence intervals. It is a family of distributions that differ based on degrees of freedom and is used extensively in hypothesis testing and confidence interval estimation for variances.

When we compute a confidence interval for a variance, we use the chi-square distribution to find the critical values that correspond to our desired confidence level, such as 95%. These critical values serve as our thresholds to create an interval within which the true population variance is likely to lie. In our example, critical values from the chi-square distribution were used to determine the range of the confidence interval. \[\begin{equation} \text{Chi-square critical values} = X^2(\alpha/2, n-1), X^2(1-\alpha/2, n-1) \end{equation}\] where \(\alpha\) is the significance level (5% for a 95% confidence interval) and \(n-1\) corresponds to the degrees of freedom. By understanding the chi-square distribution, we can interpret and apply the concept of confidence intervals for variance more effectively.
Hypothesis Testing
Hypothesis testing is a statistical method that allows us to make decisions about a population parameter based on sample data. The idea is to formulate two hypotheses: the null hypothesis \(H_0\), which is a statement of no effect or no difference, and the alternative hypothesis \(H_a\), which states the expected effect or difference.

The process involves calculating a test statistic based on the sample data and then comparing this value to a critical value from an appropriate distribution, like the chi-square distribution in the case of variance testing. If the test statistic falls into the critical region, we reject the null hypothesis. In the context of our car battery example, hypothesis testing could be used to formally test the manufacturer's claim about the variance of battery life. The null hypothesis would be \(H_0: \sigma^2 = 1\), and we would use our sample data to determine whether there is enough evidence to support or reject this claim. Using the calculated confidence interval, if it contains the hypothesized variance, we would not reject the null hypothesis, indicating that the sample evidence is consistent with the manufacturer's claim.

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Most popular questions from this chapter

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