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A random sample of 25 bottles of buffered aspirin contain, on average, \(325.05 \mathrm{mg}\) of aspirin with a standard deviation of \(0.5 \mathrm{mg}\). Find the \(95 \%\) tolerance limits that will contain \(90 \%\) of the aspirin contents for this brand of buffered aspirin. Assume that the aspirin content is normally distributed.

Short Answer

Expert verified
The 95% tolerance limits that will contain 90% of the aspirin contents for this brand of buffered aspirin are approximately between 324.854 mg and 325.246 mg.

Step by step solution

01

Calculate the standard error

The standard error can be calculated using the formula: \[SE=\frac{σ}{\sqrt{n}}\] where \(σ\) is the standard deviation and \(n\) is the sample size. Here, \(σ=0.5 \,mg\) and \(n=25\). So, \[SE=\frac{0.5}{\sqrt{25}}=\frac{0.5}{5}=0.1 \,mg\]
02

Determine the Z-scores

The Z-score corresponding to a confidence level can be found from the standard normal distribution table. The Z-score for 95% confidence level is approximately 1.96. The Z-score for 90% of the population is also 1.645. Note that the ± sign is used because the standard normal distribution is symmetrical about the mean.
03

Calculate the tolerance limits

The tolerance limits can be calculated using the formula: \[Tolerance \, limit = Mean ± (Z × SE)\] For the lower limit, calculate: \[Lower \, limit = 325.05 - (1.96 × 0.1) = 325.05 - 0.196 = 324.854 \,mg\] For the upper limit, calculate: \[Upper \, limit = 325.05 + (1.96 × 0.1) = 325.05 + 0.196 = 325.246 \,mg\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Standard Error Calculation
Understanding standard error is essential for students working with sample data to infer about a population. It is a measure of how much the sample mean is expected to fluctuate if different samples are taken from the same population.

In the provided exercise, we calculated the standard error (SE) to understand the variability of aspirin content in small samples of bottles. Since the standard deviation (\( \text{σ} \text{)} \) of the sample is known to be 0.5 mg, we needed to account for the size of the sample (25 bottles) to get a true sense of the SE. Here's the straightforward calculation we performed: \
\
\( SE = \frac{\text{σ}}{\text{sqrt}{\text{n}}} = \frac{0.5}{5} = 0.1 \text{ mg} \)

This tells us that if different samples of 25 bottles each were repeatedly taken, the average aspirin content we calculate from those samples would typically vary by 0.1 mg from the sample to sample. This concept is crucial, as it is the basis for calculating confidence intervals and tolerance limits, which help us make predictions about the entire brand's aspirin content based on our small sample.
Z-scores
Z-scores are a way to standardize individual data points relative to a given distribution. They indicate how many standard deviations an element is from the mean. In the context of our exercise, Z-scores were used to identify the standard normal distribution values corresponding to specific confidence and percentage levels.

To find the tolerance limits that include a certain percentage of the population, we need to look at the Z-score associated with that percentage. We used a Z-score for 95% confidence and 90% population coverage. The Z-score for 95% confidence is 1.96, reflecting the number of standard errors away from the mean needed to cover that level of confidence. Meanwhile, the Z-score for the middle 90% of our normal distribution is 1.645.

It's important for students to learn how to find these values using a standard normal distribution table or statistical software, as these scores are fundamental to many statistical inference techniques.
Normal Distribution
The normal distribution is a foundational concept in statistics, often referred to as the 'bell curve' due to its distinctive shape. It is characterized by its symmetry around the mean, implying that data near the mean are more frequent in occurrence than data far from the mean.

In our exercise, we assumed that the aspirin content is normally distributed. This assumption is crucial; it allows us to use the properties of the normal distribution to make statistical inferences. Because the normal distribution is predictable, knowing the standard deviation and mean provides enough information to calculate the probability of observing a given range of values.

In practice, this means the tolerance limits we calculated will contain 90% of the aspirin contents for this brand, provided that the normality assumption holds true. When dealing with real-world data, it's important for students to test this assumption, as the validity of the results hinges upon the accuracy of the distributional fit.

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