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In testing a certain kind of truck tire over a rugged terrain, it is found that \(25 \%\) of the trucks fail to complete the test run without a blowout. Of the next 15 trucks tested, find the probability that (a) from 3 to 6 have blowouts; (b) fewer than 4 have blowouts: (c) more than 5 have blowouts.

Short Answer

Expert verified
Use the binomial formula to calculate individual probabilities as required in each part. For (a), find the sum of probabilities of having 3,4,5,6 blowouts. For (b), find the sum of probabilities of having 0,1,2,3 blowouts. For (c), subtract the sum of probabilities of having 0 to 5 blowouts from 1.

Step by step solution

01

Identifying Parameters

The first step is to identify the parameters for the binomial distribution. The trials(n) is given as 15 and the probability of success(p) which is the probability of a tire blowout is 0.25. The binomial distribution function is \(P(X=k) = C(n,k) * p^k * (1-p)^{n-k}\) where X is the random variable representing the number of successes in n trials, C(n,k) is the combination of n items taken k at a time.
02

Calculating Probability for Part (a)

For part (a), to find the probability that 3 to 6 trucks have blowouts, we must apply the binomial distribution for each number of successes from 3 to 6, then sum the result. This gives us: \(P(3≤X≤6) = P(X=3) + P(X=4) + P(X=5) + P(X=6)\). Each term is calculated using the binomial formula by replacing k with the corresponding value.
03

Calculating Probability for Part (b)

For part (b), to find the probability that fewer than 4 trucks have blowouts, that means we want the probability where 0 to 3 trucks have blowouts. So we sum the probabilities for 0, 1, 2, and 3 blowouts. This gives us: \(P(X<4) = P(X=0) + P(X=1) + P(X=2) + P(X=3)\). Each term can be calculated using the binomial formula, replacing k with the corresponding value.
04

Calculating Probability for Part (c)

For part (c), to find the probability where more than 5 trucks have a blowout, we want to find 1 - P(X≤5). This would give us the sum of probabilities for 6 to 15 blowouts. Important to remember that the sum of all probabilities (0 to 15 blowouts) equals 1. So subtracting the sum of probabilities for 0 to 5 blowouts from 1, gives us the sum of probabilities for 6 to 15 blowouts

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability of Tire Blowout
When we examine the likelihood of an event occurring, such as a tire blowout during a test run, we're discussing a fundamental concept in probability. This percentage is derived from empirical evidence or calculated estimations based on known data. In our exercise, it was determined that there is a 25% chance that a truck will not complete the test run without experiencing a tire blowout.

This information plays a pivotal role as it sets the parameter for success or failure in our binomial distribution problem. To clarify, the 'success' in this context is actually an undesirable outcome (the tire blowout), but from a statistical standpoint, we refer to the event we're measuring the probability of as our 'success' scenario. Understanding this probability is crucial because it defines one of the key parameters needed to calculate binomial probabilities, which in turn, will allow us to answer questions such as the likelihood of a specific number of blowouts occurring across a series of tests.
Binomial Distribution Formula
The binomial distribution formula is indispensable for calculating the probability of a fixed number of successes in a given number of trials. The general formula is represented as:
\[\begin{equation}P(X=k) = C(n,k) \cdot p^k \cdot (1-p)^{n-k}\right)where:\end{equation}\]
  • n is the number of trials (in our exercise, this is 15 trucks),
  • k is the number of successful outcomes we're interested in,
  • p is the probability of 'success' on a single trial (25% chance of a blowout),
  • C(n,k) is the number of combinations of n items taken k at a time, also known as the binomial coefficient.
This formula allows us to calculate individual probabilities for each possible outcome and then sum them up to get the probability for a range of outcomes. Understanding and applying this formula correctly is paramount in solving many problems that follow the binomial probability distribution.
Calculating Binomial Probabilities
When doing calculations involving binomial probabilities, we're seeking to determine the probability of obtaining a certain number of successes across a series of independent trials. The steps to perform these calculations involve applying the binomial distribution formula to each potential outcome individually.

For instance, in the provided exercise to find the probability that fewer than 4 trucks have blowouts, we would calculate the probabilities of having 0, 1, 2, and 3 blowouts using the formula and sum them up. This summing process is key because it reflects the total probability of the event occurring in that specific range of outcomes. Conversely, to find probabilities for 'greater than' scenarios, we leverage the property that the sum of probabilities for all possible outcomes equals 1. Therefore, subtracting the cumulative probability of the complement scenarios from 1 gives us our desired probability.

By mastering these steps, students can approach a broad variety of binomial probability questions with confidence. It is essential to have a clear understanding of each component of the formula and how to piece together the individual probability values to obtain the final result for the collective range or specific condition outlined in the problem statement.

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Most popular questions from this chapter

An electronics firm claims that the proportion of defective units of a certain process is \(5 \%\). A buyer has a standard procedure of inspecting 15 units selected randomly from a large lot. On a particular occasion, the buyer found 5 items defective. (a) What is the probability of this occurrence, given that the claim of \(5 \%\) defective is correct? (b) What would be your reaction if you were the buyer?

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