/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 96 The probability that a person vi... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The probability that a person visiting his dentist will have an X-ray is \(0.6 ;\) the probability that a person who has an X-ray will also have a cavity filled is \(0.3 ;\) and the probability that a person who has had an X-ray and a cavity filled will also have a tooth extracted is 0.1 . What is the probability that a person visiting his dentist will have an X-ray, a cavity filled, and a tooth extracted?

Short Answer

Expert verified
The probability that a person visiting his dentist will have an X-ray, a cavity filled, and a tooth extracted is 0.018 or 1.8%.

Step by step solution

01

Identify the given probabilities

The probability of having an X-ray is given as 0.6, the probability of having a cavity filled given an X-ray was had is 0.3, and the probability of having a tooth extracted given an X-ray and a cavity were had is 0.1.
02

Understand the principle of dependent events

Dependent events' probabilities can be obtained by multiplying the probabilities of the individual events. This is because the occurrence of one event influences the occurrence of the subsequent event.
03

Calculate the combined probability

The combined probability of the three events - X-ray, cavity fill, and extraction - is given by the multiplication of the respective probabilities. Therefore, it is \(0.6 * 0.3 * 0.1 = 0.018.\) This means that the probability of all three events happening is 0.018 or 1.8%.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Dependent Events
In probability theory, understanding dependent events is critical, especially when one event influences the likelihood of another event occurring. A dependent event's probability changes because the outcome of one event affects the others. For example, in a sequence of events where having an X-ray at the dentist influences the chances of needing a cavity filled, and subsequently, the extraction of a tooth, each event's condition modifies the next.

To determine probabilities involving dependent events, like our dentist visit example, we must consider these influences:
  • The probability of the first event occurring on its own, such as having an X-ray.
  • Subsequent probabilities are dependent on the outcomes of previous events. Thus, having a cavity filled depends on having an X-ray.
  • Finally, the event of a tooth extraction depends on both prior events happening—X-ray and cavity filling.
By multiplying the probabilities of each event chain, we obtain the overall probability of all events happening together. This approach helps analyze situations where events are interconnected.
Joint Probability
Joint probability refers to the likelihood of two or more events occurring together. It is often used when considering sequences of events that are linked, such as the dentist example. Here, finding the joint probability involves calculating the probability that a person will have both an X-ray and a cavity filled and also undergo a tooth extraction.

To compute joint probabilities, especially in scenarios involving dependent sequences:
  • Start by identifying each event's probability in isolation.
  • For dependent events, consider how each event's probability is affected by preceding ones.
  • Then, multiply the individual probabilities of the related events. In our example, this means multiplying the probabilities of having an X-ray, a cavity filled, and a tooth extracted.
This process gives us insight into the chance of the entire chain of events happening simultaneously, which is crucial in decision-making and predicting outcomes in real-world scenarios.
Conditional Probability
Conditional probability is a key component of understanding dependent events. It defines the likelihood of an event occurring given that another event has already occurred. In our scenario, the probability of having a cavity filled (given the patient had an X-ray) is a conditional probability, as is having a tooth extracted given both previous events have occurred.

Calculating conditional probabilities involves these steps:
  • Determine the probability of the initial event, such as having an X-ray.
  • Identify how subsequent events rely on the occurrence of prior ones. For example, the likelihood of needing a cavity filled depends on already having an X-ray.
  • Use these relations to compute the conditional probability, multiplying as necessary for each event in the chain.
By examining each event conditionally, we demonstrate how the outcome of one event impacts others and can calculate the ripple effect throughout the sequence. This approach deepens our understanding of how probabilities of interconnected events change with dependencies.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A box contains 500 envelopes of which 75 contain \(\$ 100\) in cash, 150 contain \(\$ 25,\) and 275 contain \$10. An envelope may be purchased for \(\$ 25 .\) What is the sample space for the different amounts of money? Assign probabilities to the sample points and then find the probability that the first envelope purchased contains less than \$100.

An engineering firm is hired to determine if certain waterways in Virginia are safe for fishing. Samples are taken from three rivers. (a) List the elements of a sample space \(\mathrm{S}\), using the letters \(F\) for "safe to fish" and \(N\) for "not safe to fish." (b) List the elements of \(S\) corresponding to event \(E\) that at least two of the rivers are safe for fishing. (c) Define an event that has as its elements the points \\{FFF, NFF, FFN, NFN\\}.

A certain form of cancer is known to be found in women over 60 with probability 0.07 . A blood test exists for the detection of the disease but the test is not infallible. In fact, it is known that \(10 \%\) of the time the test gives a false negative (i.e., the test incorrectly gives a negative result) and \(5 \%\) of the time the test gives a false positive (i.e., incorrectly gives a positive result). If a woman over 60 is known to have taken the test and received a favorable (i.e., a negative result), what is the probability that she has the disease?

The probabilities that a service station will pump gas into \(0,1,2,3,4,\) or 5 or more cars during a certain 30 -minute period are 0.03,0.18,0.24,0.28 , \(0.10,\) and \(0.17,\) respectively. Find the probability that in this 30 -minute period (a) more than 2 cars receive gas; (b) at most 4 cars receive gas; (c) 4 or more cars receive gas.

A college plays 12 football games during a season. In how many ways can the team end the season with 7 wins, 3 losses, and 2 ties?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.