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If the probability is 0.1 that a person will make a mistake on his or her state income tax return, find the probability that (a) four totally unrelated persons each make a mistake; (b) Mr. Jones and Ms. Clark both make a mistake, and Mr. Roberts and Ms. Williams do not make a mistake.

Short Answer

Expert verified
The answer to part (a) of the exercise is 0.0001, and the answer to part (b) is 0.0081.

Step by step solution

01

Establish Given Probability

The probability that a person makes a mistake on their state income tax is given as 0.1. This means that the probability of a person not making a mistake is 1 - 0.1 = 0.9 as the total probability must add up to 1.
02

Calculate Probability for Part (a)

We have 4 unrelated individuals. The probability that each will make a mistake is independent and hence can be multiplied together. So, the probability that all 4 make a mistake is \(0.1 * 0.1 * 0.1 * 0.1 = 0.0001\).
03

Calculate Probability for Part (b)

Here, we know that Mr. Jones and Ms. Clark both make a mistake, and Mr. Roberts and Ms. Williams do not make a mistake. Given the independent nature of these events, we again multiply the probabilities. This results in \(0.1 * 0.1 * 0.9 * 0.9 = 0.0081\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Independent Events
In the world of probability theory, the concept of independent events is foundational. Two events are considered independent if the outcome of one event does not affect the outcome of another. For instance, when flipping two coins, the result of the first flip has no influence on the result of the second flip. This principle can be applied to broader scenarios, such as the one described in the textbook exercise where individual taxpayers filling out their state income tax returns are independent events.

To compute the probability of independent events occurring simultaneously, one simply multiplies the probability of each event occurring individually. If the probability of a single event A is given by P(A), and the probability of another independent event B is P(B), then the probability both events occur, denoted by P(A and B), is P(A) * P(B). This fundamental rule helps unfold complex probability questions involving several independent events.
Probability Theory
The textbook problem is a practical application of probability theory, a branch of mathematics concerned with the analysis of random events. The foundational rule is that probabilities range from 0 to 1, where 0 indicates an impossibility and 1 signifies certainty. A crucial aspect of probability is the total probability of all possible outcomes of a random event, which always sums to 1.

When determining the likelihood of an event, such as making a mistake on a tax return, we assign a numerical value representing its probability. In our example, the likelihood is 0.1 that an individual makes a mistake. Conversely, the probability of not making a mistake is the complement of this event, which is calculated as 1 minus the probability of the event, resulting in 0.9. Understanding how to use these probabilities in different scenarios forms the bedrock of solving real-world probability problems.
Binomial Probability
The exercise given leads to the concept of binomial probability, relevant when we are dealing with two outcomes, success (making a mistake) or failure (not making a mistake), in a fixed number of independent trials. The binomial probability formula is:
\[ P(X=k) = \binom{n}{k} \times p^k \times (1-p)^{(n-k)} \]
where
  • \( n \) is the number of trials (in this case, four taxpayers),
  • \( k \) is the number of successful events we are interested in (e.g., the number of mistakes),
  • \( p \) is the probability of success on a single trial (0.1 chance of making a mistake), and
  • \( 1-p \) is the probability of failure (0.9 chance of not making a mistake).
In both parts (a) and (b) of the exercise, we are working with binomial scenarios with different values of \( k \). For part (a), we want all four people to make a mistake (\( k = 4 \)), while for part (b), we have a mixed outcome (two mistakes and two correct filings, \( k = 2 \)). These scenarios are calculated using the principles of binomial probability, underlining the versatility of this concept in a variety of settings.

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