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For which of the given \(P\)-values would the null hypothesis be rejected when performing a level \(.05\) test? a. \(.001\) b. \(.021\) c. \(.078\) d. \(.047\) e. \(.148\)

Short Answer

Expert verified
Reject the null hypothesis for P-values 0.001, 0.021, and 0.047.

Step by step solution

01

Understanding the Null Hypothesis and Significance Level

When conducting a hypothesis test at a significance level of \( \alpha = 0.05 \), the null hypothesis \( H_0 \) is rejected if the \( P \)-value is less than or equal to 0.05. This significance level represents a 5% probability of rejecting the null hypothesis when it is actually true.
02

Evaluating Each P-Value

We will compare each given \( P \)-value to the significance level of 0.05 to determine if the null hypothesis should be rejected:- a. \( P = 0.001 \) is less than 0.05- b. \( P = 0.021 \) is less than 0.05- c. \( P = 0.078 \) is greater than 0.05- d. \( P = 0.047 \) is less than 0.05- e. \( P = 0.148 \) is greater than 0.05
03

Determining Which P-Values Lead to Rejection

Based on the comparisons, the null hypothesis would be rejected for \( P \)-values of \( 0.001 \), \( 0.021 \), and \( 0.047 \) because they are less than or equal to the significance level, 0.05.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Level of Significance
The Level of Significance, represented as \( \alpha \), is a critical threshold in hypothesis testing. It quantifies the probability of rejecting the null hypothesis when it is actually true, which is known as a Type I error. A commonly used level of significance is 0.05, meaning there is a 5% risk of incorrectly rejecting the null hypothesis.

When you hear about a hypothesis test being at the 0.05 level, it means the researchers have decided they are willing to take a 5% chance that they are making an error in rejecting the null hypothesis. This level is selected before the test is conducted and provides a benchmark for deciding whether the observed data differ significantly from what was expected.
Null Hypothesis
In the realm of hypothesis testing, the Null Hypothesis, denoted as \( H_0 \), is a statement that there is no effect or no difference. It is a kind of default position that the test seeks to challenge. For example, if you were testing whether a new drug is more effective than an old one, the null hypothesis would likely be that both drugs are equally effective.

The null hypothesis is a fundamental concept because it establishes the framework for statistical testing. The goal of most hypothesis tests is to determine whether there is enough evidence to reject this "no change" hypothesis, suggesting that the alternative hypothesis \( H_1 \) is true instead. During the testing process, if the evidence is strong enough against \( H_0 \), it is rejected in favor of \( H_1 \).
P-Value
A \( P \)-Value is a statistical measure that helps you determine the strength of your results in hypothesis testing. It represents the probability that the observed data would occur if the null hypothesis were true. In simpler terms, it's a way to measure how well your sample data support your null hypothesis.

A small \( P \)-Value (usually \( < 0.05 \) when the level of significance is 0.05) indicates strong evidence against the null hypothesis, so you reject the \( H_0 \). Conversely, a larger \( P \)-Value suggests that the data are consistent with the null hypothesis, and you do not reject \( H_0 \). Importantly, \( P \)-Values provide a standard method to decide whether your observations are unusual under the null hypothesis, thus guiding decision-making and inference.
Rejection Criteria
Rejection Criteria are the conditions under which you reject the null hypothesis \( H_0 \) in a hypothesis test. Typically, this is determined by comparing the \( P \)-Value to the pre-established level of significance \( \alpha \).

- If the \( P \)-Value is less than or equal to \( \alpha \), you reject the null hypothesis. In such cases, you conclude that there is a statistically significant effect or difference.- If the \( P \)-Value is greater than \( \alpha \), you do not reject the null hypothesis. Here, the data do not provide strong enough evidence against \( H_0 \).

These criteria ensure that decisions made from statistical tests are grounded in the balance between risk and evidence. By setting clear rejection criteria before conducting a test, researchers maintain objectivity and consistency in the application of statistical inference.

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Most popular questions from this chapter

When \(X_{1}, X_{2}, \ldots, X_{n}\) are independent Poisson variables, each with parameter \(\lambda\), and \(n\) is large, the sample mean \(\bar{X}\) has approximately a normal distribution with \(\mu=E(\bar{X})=\lambda\) and \(\sigma^{2}=V(\bar{X})=\lambda / n\). This implies that $$ Z=\frac{X-\lambda}{\sqrt{\lambda / n}} $$ has approximately a standard normal distribution. For testing \(H_{0}: \lambda=\lambda_{0}\), we can replace \(\lambda\) by \(\lambda_{0}\) in the equation for \(Z\) to obtain a test statistic. This statistic is actually preferred to the large-sample statistic with denominator \(S / \sqrt{n}\) (when the \(X_{i}\) s are Poisson) because it is tailored explicitly to the Poisson assumption. If the number of requests for consulting received by a certain statistician during a 5 -day work week has a Poisson distribution and the total number of consulting requests during a 36 -week period is 160 , does this suggest that the true average number of weekly requests exceeds 4.0? Test using \(\alpha=.02\).

To obtain information on the corrosion-resistance properties of a certain type of steel conduit, 45 specimens are buried in soil for a 2-year period. The maximum penetration (in mils) for each specimen is then measured, yielding a sample average penetration of \(\bar{x}=52.7\) and a sample standard deviation of \(s=4.8\). The conduits were manufactured with the specification that true average penetration be at most 50 mils. They will be used unless it can be demonstrated conclusively that the specification has not been met. What would you conclude?

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A sample of 50 lenses used in eyeglasses yields a sample mean thickness of \(3.05 \mathrm{~mm}\) and a sample standard deviation of \(.34 \mathrm{~mm}\). The desired true average thickness of such lenses is \(3.20 \mathrm{~mm}\). Does the data strongly suggest that the true average thickness of such lenses is something other than what is desired? Test using \(\alpha=.05\).

Let \(\mu\) denote the true average radioactivity level (picocuries per liter). The value \(5 \mathrm{pCi} / \mathrm{L}\) is considered the dividing line between safe and unsafe water. Would you recommend testing \(H_{0}: \mu=5\) versus \(H_{\mathrm{a}}: \mu>5\) or \(H_{0}: \mu=5\) versus \(H_{\mathrm{a}}\) : \(\mu<5\) ? Explain your reasoning.

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