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Scientists think that robots will play a crucial role in factories in the next several decades. Suppose that in an experiment to determine whether the use of robots to weave computer cables is feasible, a robot was used to assemble 500 cables. The cables were examined and there were 15 defectives. If human assemblers have a defect rate of .035 (3.5\%), does this data support the hypothesis that the proportion of defectives is lower for robots than humans? Use a .01 significance level.

Short Answer

Expert verified
If the calculated z-value is less than -2.33, the robot defect rate is lower than humans at a 0.01 significance level.

Step by step solution

01

Formulate the Hypotheses

We need to test if the defect rate of robots is less than that of humans. Let the proportion of defective cables made by robots be \( p \). The null hypothesis \( H_0 \) is \( p = 0.035 \), indicating no difference from humans. The alternative hypothesis \( H_a \) is \( p < 0.035 \). This suggests that robots have a lower defect rate.
02

Define the Test Statistic

We will use the one-sample z-test for proportions. The test statistic is calculated by the formula: \[ z = \frac{\hat{p} - p_0}{\sqrt{\frac{p_0 (1 - p_0)}{n}}} \]where \( \hat{p} = \frac{x}{n} = \frac{15}{500} = 0.03 \) is the sample proportion of defective cables, \( p_0 = 0.035 \) is the human defect rate, and \( n = 500 \) is the sample size.
03

Calculate the Test Statistic

Plug in the values into the test statistic formula. \[ z = \frac{0.03 - 0.035}{\sqrt{\frac{0.035(1 - 0.035)}{500}}} \]Calculate this to find the value of \( z \).
04

Determine the Critical Value

At a significance level of \( \alpha = 0.01 \), for a one-tailed test, find the critical value for \( z \) from the standard normal distribution. The critical value \( z_c \) is approximately -2.33.
05

Compare Test Statistic and Critical Value

Check if the calculated \( z \)-value from Step 3 is less than the critical value \( -2.33 \). If \( z < -2.33 \), we reject the null hypothesis; otherwise, we do not reject it.
06

Make a Decision

If the \( z \)-value indicates that the proportion of robot-made defective cables is significantly lower than the human defect rate, conclude that the hypothesis is supported.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Null Hypothesis
In hypothesis testing, the Null Hypothesis is a statement that suggests there is no effect or no difference. It is often represented by the symbol \( H_0 \). In the context of the exercise, the Null Hypothesis is that the proportion of defective cables assembled by robots is equal to the defect rate of human assemblers, which is 3.5% or 0.035. This hypothesis serves as the baseline or status quo and is the statement we aim to test.

The Null Hypothesis is crucial because it sets the framework for testing whether any observed differences are due to chance. In most scenarios, we assume the Null Hypothesis to be true until proven otherwise. The process of hypothesis testing involves gathering evidence through data, and checking if this evidence sufficiently contradicts the Null Hypothesis. Only when the evidence strongly contradicts \( H_0 \) do we reject it in favor of the alternative.
Alternative Hypothesis
The Alternative Hypothesis, denoted as \( H_a \), is the statement we want to test against the null hypothesis. It represents the possibility that there is indeed an effect or a difference. In our example, the Alternative Hypothesis is that the proportion of defective cables made by robots is less than that by humans, or \( p < 0.035 \).

An alternative hypothesis can be one-tailed or two-tailed:
  • In a one-tailed hypothesis, as in this case, we are only interested in whether one parameter is less (or more) than the other.
  • In a two-tailed hypothesis, we would be interested in whether the parameters are different in either direction.
The alternative hypothesis is what we accept if we find enough evidence to reject the null hypothesis. This means that, in our example, if a substantial amount of data supports it, we conclude that robots produce fewer defective cables than humans.
Proportion Test
A Proportion Test is a statistical method used to determine if a sample proportion compares significantly to a known proportion. In the exercise, we are trying to compare the defect rate of robot-made cables with the known human defect rate of 0.035.

We use the one-sample z-test for proportions, which involves:
  • Calculating the sample proportion \( \hat{p} \), which is the number of defective cables divided by the total number assembled (15/500).
  • Using the test statistic formula: \[ z = \frac{\hat{p} - p_0}{\sqrt{\frac{p_0 (1 - p_0)}{n}}} \]where \( p_0 \) is the known population proportion, and \( n \) is the sample size.
The z-value obtained tells us how far away our sample proportion is from the human defect rate in terms of standard deviations. By comparing this to a critical value, we can make a decision about our hypotheses.
Significance Level
The Significance Level is a critical component in hypothesis testing, often denoted by the Greek letter \( \alpha \). It represents the probability of rejecting the null hypothesis when it is actually true. In our exercise, we are using a significance level of \( \alpha = 0.01 \), which means we tolerate a 1% chance of making a Type I error (wrongly rejecting the true null hypothesis).

Choosing a significance level involves a balance between risk and confidence. Lower values, such as 0.01, indicate a more stringent test with lesser tolerance for error, thus stronger evidence is required to reject the null hypothesis. In contrast, higher values, like 0.05 or 0.10, indicate greater tolerance for error but require less evidence to reach a conclusion.

The significance level also helps determine the critical value for the test. This critical value acts as the threshold—if our test statistic exceeds (in magnitude) this value, we reject the null hypothesis. In the context of the exercise, since it's a one-tailed test, the critical z-value is approximately -2.33 for \( \alpha = 0.01 \). This signifies that the calculated z-value must be less than -2.33 for us to conclude that robots have a significantly lower defect rate compared to humans.

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Most popular questions from this chapter

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