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A surveyor wishes to lay out a square region with each side having length \(L\). However, because of measurement error, he instead lays out a rectangle in which the north-south sides both have length \(X\) and the east-west sides both have length \(Y\). Suppose that \(X\) and \(Y\) are independent and that each is uniformly distributed on the interval \([L-A, L+A]\) (where \(0

Short Answer

Expert verified
The expected area of the rectangle is \(L^2\).

Step by step solution

01

Define Expected Values of Lengths

Given the uniform distribution of the lengths \(X\) and \(Y\) on the interval \([L-A, L+A]\), the expected value of a uniformly distributed random variable over an interval \([a, b]\) is \((a+b)/2\). Therefore, the expected values are \(E(X) = \frac{(L-A) + (L+A)}{2} = L\) and \(E(Y) = \frac{(L-A) + (L+A)}{2} = L\).
02

Express the Expected Area of the Rectangle

The area \(A\) of the rectangle formed using sides \(X\) and \(Y\) is given by \(A = X \times Y\). Since \(X\) and \(Y\) are independent random variables, the expected value of their product can be expressed as the product of their expected values: \(E(XY) = E(X) \times E(Y)\).
03

Calculate the Expected Area

Using the results from Step 1, the expected area \(E(XY)\) becomes \(E(XY) = E(X) \times E(Y) = L \times L = L^2\). Thus, the expected area is \(L^2\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Expected Value
In probability theory, the concept of expected value plays a crucial role in understanding the average outcome of random events. For any random variable, the expected value is essentially the "weighted average" of all possible values the variable can take, with the weights being their probabilities. When dealing with a uniform distribution over an interval, say \[ [a, b] \] the expected value can be calculated using the formula:\[ E(X) = \frac{a + b}{2} \]
This formula indicates that the expected value is the midpoint of the interval. In the scenario of the surveyor, the lengths of the rectangle's sides, denoted by \( X \) and \( Y \), are uniform random variables over the interval \([L-A, L+A]\). Therefore, their expected values are both \( L \). This insight is crucial for determining the average area of the rectangle later on.
Uniform Distribution
A uniform distribution is one where all outcomes are equally likely over a specified interval. This means that if you have a random variable that is uniformly distributed, each point in its interval of definition has an equal chance of being selected. In the surveyor's problem, measurements of north-south and east-west sides, \( X \) and \( Y \), are both independently drawn from a uniform distribution spanning from \[ L-A \] to \[ L+A \].
  • The main characteristic of the uniform distribution that is utilized is its consistency in probability across the interval.
  • This simplicity allows us to easily compute expected values, as reflected in the expected lengths of \( X \) and \( Y \) being exactly \( L \).
Understanding that both measurements are independent and uniform helps simplify the determination of expected outcomes like area.
Independent Random Variables
When random variables are independent, the occurrence of one event does not affect the probability of another event. This independence is a critical concept in probability theory, as it simplifies the calculation of expectations and variances. In our problem, the lengths \( X \) and \( Y \) are independent random variables. This independence allows us to use the multiplication rule for expected values. Given that the expected values \[ E(X) = L \] and \[ E(Y) = L \]are independent, we can express the expected value of the product \[ E(XY) \] as the product of the expected values:\[ E(XY) = E(X) \times E(Y) = L \times L = L^2 \].This property greatly simplifies the task of finding the expected area of the rectangle in the surveyor's problem.
Measurement Errors
Measurement errors are inevitable in any real-world data collection process. They can result from a variety of factors such as equipment inaccuracies, human error, or environmental conditions. In the surveyor's problem, the lack of precision leads to the formation of rectangles instead of squares.

To model such errors effectively, assuming a uniform distribution helps illustrate the range within which actual measurements may deviate from the intended value \( L \). This provides a realistic view of possible variation:
  • It acknowledges errors but bounds them within a defined range \( [L-A, L+A] \).
  • It ensures that assumptions regarding symmetry and equal deviation probability around the target measure hold true.
By considering these errors in calculations, we obtain a more accurate expected area, acknowledging the inherent uncertainties of physical measurements.

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Most popular questions from this chapter

There are 40 students in an elementary statistics class. On the basis of years of experience, the instructor knows that the time needed to grade a randomly chosen first examination paper is a random variable with an expected value of \(6 \mathrm{~min}\) and a standard deviation of \(6 \mathrm{~min}\). a. If grading times are independent and the instructor begins grading at 6:50 P.M. and grades continuously, what is the (approximate) probability that he is through grading before the 11:00 P.M. TV news begins? b. If the sports report begins at \(11: 10\), what is the probability that he misses part of the report if he waits until grading is done before turning on the TV?

When an automobile is stopped by a roving safety patrol, each tire is checked for tire wear, and each headlight is checked to see whether it is properly aimed. Let \(X\) denote the number of headlights that need adjustment, and let \(Y\) denote the number of defective tires. a. If \(X\) and \(Y\) are independent with \(p_{X}(0)=.5, p_{X}(1)=.3\), \(p_{X}(2)=.2\), and \(p_{Y}(0)=.6, p_{Y}(1)=.1, p_{Y}(2)=p_{Y}(3)=\) \(.05, p_{Y}(4)=.2\), display the joint pmf of \((X, Y)\) in a joint probability table. b. Compute \(P(X \leq 1\) and \(Y \leq 1)\) from the joint probability table, and verify that it equals the product \(P(X \leq 1)\) • \(P(Y \leq 1)\) c. What is \(P(X+Y=0)\) (the probability of no violations)? d. Compute \(P(X+Y \leq 1)\).

In an area having sandy soil, 50 small trees of a certain type were planted, and another 50 trees were planted in an area having clay soil. Let \(X=\) the number of trees planted in sandy soil that survive 1 year and \(Y=\) the number of trees planted in clay soil that survive 1 year. If the probability that a tree planted in sandy soil will survive 1 year is \(.7\) and the probability of 1-year survival in clay soil is .6, compute an approximation to \(P(-5 \leq X-Y \leq 5\) ) (do not bother with the continuity correction).

A box contains ten sealed envelopes numbered \(1, \ldots, 10\). The first five contain no money, the next three each contains \(\$ 5\), and there is a \(\$ 10\) bill in each of the last two. A sample of size 3 is selected with replacement (so we have a random sample), and you get the largest amount in any of the envelopes selected. If \(X_{1}, X_{2}\), and \(X_{3}\) denote the amounts in the selected envelopes, the statistic of interest is \(M=\) the maximum of \(X_{1}, X_{2}\), and \(X_{3}\). a. Obtain the probability distribution of this statistic. b. Describe how you would carry out a simulation experiment to compare the distributions of \(M\) for various sample sizes. How would you guess the distribution would change as \(n\) increases?

Show that if \(X\) and \(Y\) are independent rv's, then \(E(X Y)=\) \(E(X) \cdot E(Y)\). Then apply this in Exercise 25.

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