/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 37 The accompanying data on cube co... [FREE SOLUTION] | 91Ó°ÊÓ

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The accompanying data on cube compressive strength (MPa) of concrete specimens appeared in the article "Experimental Study of Recycled Rubber-Filled High- Strength Concrete" (Magazine of Concrete \(\operatorname{Res}_{*}\) 2009: 549-556): \(\begin{array}{rrrrr}112.3 & 97.0 & 92.7 & 86.0 & 102.0 \\ 99.2 & 95.8 & 103.5 & 89.0 & 86.7\end{array}\) a. Is it plausible that the compressive strength for this type of concrete is normally distributed? b. Suppose the concrete will be used for a particular application unless there is strong evidence that true average strength is less than 100 MPa. Should the concrete be used? Carry out a test of appropriate hypotheses.

Short Answer

Expert verified
The normality should be checked first, but initial calculations indicate the mean is below 100 MPa. If the test statistic is significant, the concrete shouldn't be used.

Step by step solution

01

Organize and Understand the Data

We have a dataset of cube compressive strength for concrete: 112.3, 97.0, 92.7, 86.0, 102.0, 99.2, 95.8, 103.5, 89.0, 86.7 (measured in MPa). We need to analyze if the data is normally distributed and then conduct a hypothesis test to check if the average strength is less than 100 MPa.
02

Check Normality

We should begin by checking the assumption of normality for the data. This can be done using graphical methods like a Q-Q plot or statistical tests like Shapiro-Wilk test. For a Q-Q plot, plot the quantiles of the data against the quantiles of a normal distribution. Deviations from the line suggest non-normality; for the Shapiro-Wilk test, a p-value less than 0.05 would indicate that the data is not normally distributed. However, since specific calculations aren't possible here, visualize using available tools.
03

Formulate Hypotheses

We need to check if the average strength is less than 100 MPa. Thus, the null hypothesis ( H_0 ) is that the average compressive strength ar{x} is 100 MPa and the alternative hypothesis ( H_a ) is that the average compressive strength is less than 100 MPa. Mathematically: H_0: ar{x} = 100 , H_a: ar{x} < 100 .
04

Calculate Sample Mean and Standard Deviation

Calculate the sample mean: \(ar{x} = \frac{112.3 + 97.0 + 92.7 + 86.0 + 102.0 + 99.2 + 95.8 + 103.5 + 89.0 + 86.7}{10} = 96.42\) MPa. Next, calculate the sample standard deviation using the formula involving differences between each data point and the mean.
05

Compute Test Statistic

Use the t-test statistic formula, since the population standard deviation is unknown. The test statistic is calculated as: \(t = \frac{\bar{x} - 100}{s/\sqrt{n}}\), where \bar{x} is the sample mean, s is the sample standard deviation, and n is the sample size (10). Compute this value using the mean and standard deviation from Step 4.
06

Make a Decision

Compare the test statistic against the critical value at the chosen significance level (usually α = 0.05 ) for a one-tailed test. If the test statistic is less than the critical value from the t-distribution, reject H_0 ; otherwise, do not reject H_0 .

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Normal Distribution
The concept of normal distribution is central to statistics. It is a symmetrical, bell-shaped distribution where most of the data points are clustered around the mean. This distribution is significant because it often describes how various natural phenomena behave, including human traits like height or IQ. For processes that are normally distributed:
  • The mean, median, and mode coincide.
  • Approximately 68% of data falls within one standard deviation of the mean.
  • About 95% falls within two standard deviations, and 99.7% within three.
In the context of the concrete compressive strength data, determining if the data is normally distributed will guide the choice of statistical tests. Methods like a Q-Q plot or the Shapiro-Wilk test are used to assess normality. If the concrete strength data follows a normal distribution, it strengthens the validity of using parametric tests, such as the t-test, which assumes normality of the data.
t-test
The t-test is a statistical test used to determine whether there is a significant difference between the means of two groups, or between a sample mean and a known value. In this exercise, a one-sample t-test is applied to test if the average concrete strength is less than the specified 100 MPa.Here are key points about the t-test:
  • The test requires that the sample is randomly selected.
  • It assumes that data follows a normal distribution.
  • The t-test is especially useful when the sample size is small, and the population standard deviation is unknown.
For this problem, you'll calculate the t-test statistic using:\[t = \frac{\bar{x} - \text{hypothesized mean}}{s/\sqrt{n}}\]where \(\bar{x}\) is the sample mean, \(s\) is the sample standard deviation, and \(n\) is the sample size. Compare this statistic to the critical value from the t-distribution to make your decision about the hypothesis.
Sample Standard Deviation
The sample standard deviation is a measure of how much the data points in a sample deviate from the sample mean. It's an indicator of the spread or variability within a data set. Calculating it involves these steps: 1. Find the mean of the sample data. 2. Subtract the mean from each data point and square the result. 3. Sum up all these squared values. 4. Divide the sum by the number of data points minus one (n - 1) - this step is crucial as it corrects the bias in the estimation of the population variance. 5. Take the square root of the result to get the sample standard deviation. In the current exercise, knowing the sample standard deviation allows us to use the t-test formula. This provides essential information when the population standard deviation is unknown, especially with smaller samples. Remember, a higher standard deviation indicates more spread among data points, while a lower value suggests they are clustered closely around the mean.
Concrete Compressive Strength Data
Concrete compressive strength data like those presented in the exercise are valuable in engineering and construction for ensuring the quality and durability of concrete structures. This data typically measures the ability of concrete cubes to withstand loads, expressed in Megapascals (MPa). Here are some key attributes of the data:
  • It provides insights into the capacity of the concrete mix to withstand compression.
  • Variations within the data can indicate the consistency and reliability of the concrete recipe.
  • Analyzing it helps in quality control and assessing if the material meets required specifications.
In the provided exercise, the goal is to determine if the compressive strength averages less than 100 MPa. Concluding whether the concrete is suitable for certain applications is crucial in construction; thus, analyzing data like this helps in making informed decisions, ensuring safety and compliance with engineering standards.

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Most popular questions from this chapter

Two different companies have applied to provide cable television service in a certain region. Let \(p\) denote the proportion of all potential subscribers who favor the first company over the second. Consider testing \(H_{0}: p=.5\) versus \(H_{a}=p \neq .5\) based on a random sample of 25 individuals. Let the test statistic \(X\) be the number in the sample who favor the first company and \(x\) represent the observed value of \(X\). a. Describe type I and II errors in the context of this problem situation. b. Suppose that \(x=6\). Which values of \(X\) are at least as contradictory to \(H_{0}\) as this one? c. What is the probability distribution of the test statistic \(X\) when \(H_{0}\) is true? Use it to compute the \(P\)-value when \(x=6\). d. If \(H_{0}\) is to be rejected when \(P\)-value \(\leq .044\), compute the probability of a type II error when \(p=.4\), again when \(p=.3\), and also when \(p=.6\) and \(p=.7\). [Hint: \(P\)-value \(>.044\) is equivalent to what inequalities involving \(x\) (see Example 8.4)?] e. Using the test procedure of (d), what would you conclude if 6 of the 25 queried favored company 1 ?

The article "Effects of Bottle Closure Type on Consumer Perception of Wine Quality" (Amer. \(J\). of Enology and Viticulfure, 2007: 182-191) reported that in a sample of 106 wine consumers, \(22(20.8 \%)\) thought that screw tops were an acceptable substitute for natural corks. Suppose a particular winery decided to use screw tops for one of its wines unless there was strong evidence to suggest that fewer than \(25 \%\) of wine consumers found this acceptable. a. Using a significance level of .10, what would you recommend to the winery? b. For the hypotheses tested in (a), describe in context what the type I and II errors would be, and say which type of error might have been committed.

A regular type of laminate is currently being used by a manufacturer of circuit boards. A special laminate has been developed to reduce warpage. The regular laminate will be used on one sample of specimens and the special laminate on another sample, and the amount of warpage will then be determined for each specimen. The manufacturer will then switch to the special laminate only if it can be demonstrated that the true average amount of warpage for that laminate is less than for the regular laminate. State the relevant hypotheses, and describe the type I and type II errors in the context of this situation.

A manufacturer of nickel-hydrogen batteries randomly selects 100 nickel plates for test cells, cycles them a specified number of times, and determines that 14 of the plates have blistered. a. Does this provide compelling evidence for concluding that more than \(10 \%\) of all plates blister under such circumstances? State and test the appropriate hypotheses using a significance level of \(.05\). In reaching your conclusion, what type of error might you have committed? b. If it is really the case that \(15 \%\) of all plates blister under these circumstances and a sample size of 100 is used, how likely is it that the null hypothesis of part (a) will not be rejected by the level .05 test? Answer this question for a sample size of \(200 .\) c. How many plates would have to be tested to have \(\beta(.15)=.10\) for the test of part (a)?

Consider carrying out \(m\) tests of hypotheses based on independent samples, each at significance level (exactly) .01. a. What is the probability of committing at least one type I error when \(m=5\) ? When \(m=10\) ? b. How many such tests would it take for the probability of committing at least one type I error to be at least . 5 ?

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