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In five-card poker, a straight consists of five cards with adjacent denominations (e.g., 9 of clubs, 10 of hearts, jack of hearts, queen of spades, and king of clubs). Assuming that aces can be high or low, if you are dealt a five-card hand, what is the probability that it will be a straight with high card 10 ? What is the probability that it will be a straight? What is the probability that it will be a straight flush (all cards in the same suit)?

Short Answer

Expert verified
Probability of straight with high card 10: 0.000394. Probability of any straight: 0.00392. Probability of a straight flush: 0.0000154.

Step by step solution

01

Understanding the deck

A standard deck of cards has 52 cards divided into 4 suits (hearts, diamonds, clubs, spades), each with 13 ranks (2, 3, ..., 10, Jack, Queen, King, Ace). A straight is any sequence of five cards in consecutive order.
02

Calculate total possible five-card hands

The total number of ways to deal a five-card hand from a 52-card deck is given by the combination formula \( \binom{52}{5} \). This is calculated as follows:\[ \binom{52}{5} = \frac{52 \times 51 \times 50 \times 49 \times 48}{5 \times 4 \times 3 \times 2 \times 1} = 2,598,960. \]
03

Calculate straights with high card 10

For a straight with the high card 10, the cards must be 6, 7, 8, 9, 10 across any suits. Each card in the straight can be any of the 4 suits, so the number of ways to form this particular straight is \( 4^5 = 1,024 \).
04

Calculate probability of a straight with high card 10

The probability of being dealt a straight with the high card 10 is the number of successful outcomes divided by the total possible outcomes: \[ P(\text{straight, high card 10}) = \frac{1,024}{2,598,960} \approx 0.000394. \]
05

Calculate total straight possibilities

A straight can have one of the 10 sequences: Ace-to-5, 2-to-6, ..., 10-to-Ace. Like previous calculations, each sequence has \( 4^5 \) ways. Thus the total number of straights is \( 10 \times 4^5 = 10,240 \).
06

Calculate probability of any straight

The probability of being dealt any straight is given by the ratio of straight possibilities to total possible hands: \[ P(\text{any straight}) = \frac{10,240}{2,598,960} \approx 0.00392. \]
07

Calculate straight flush possibilities

For a straight flush, all cards are in the same suit. Each suit has 10 possible straights (Ace-to-5, ..., 10-to-Ace), resulting in \( 10 \) straight flushes per suit. With 4 suits, it gives \( 4 \times 10 = 40 \) possible straight flush hands.
08

Calculate probability of a straight flush

The probability of being dealt a straight flush is \( \frac{40}{2,598,960} \approx 0.0000154 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Combinatorics in Card Games
In card games, combinatorics is used to determine the number of possible outcomes for various situations. For poker, this involves counting the number of ways certain hands can be formed. The foundation of combinatorics in poker relies on understanding combinations. Combinations refer to selecting a subset of items from a larger set, where the order does not matter.

For example, when picking 5 cards from a deck of 52, the combination formula, denoted as \( \binom{52}{5} \), tells us how many different 5-card hands can be dealt. It uses the formula \( \binom{n}{k} = \frac{n!}{k!(n-k)!} \). In this case, \( n \) is 52 and \( k \) is 5. This calculation results in 2,598,960 possible hands.

Mastering these basics of combinatorics allows you to delve deeper into calculating poker hand probabilities, such as straights and flushes, by accurately determining how often these can occur among all possible hands.
Poker Hand Probabilities
Understanding poker hand probabilities is key to evaluating the strength of a hand. This involves calculating the likelihood of obtaining specific combinations of cards. In poker, hands like pairs, flushes, straights, and flushes each have different probabilities and are ranked differently based on how often they occur.

For example, achieving a straight with a high card of 10 involves identifying how many 5-card combinations produce such a hand. Within each set of ranks, each card can belong to any of the four suits. Thus, the combinations multiply significantly, turning into probabilities based on the entire deck's combinations.

Therefore, understanding poker hand probabilities provides players with a strategic advantage, knowing which hands to pursue and which to fold during play.
Straight and Straight Flush Calculation
The calculation of straights and straight flushes in poker involves understanding the unique patterns and limitations of these hands. A straight consists of any sequence of five consecutive cards, regardless of their suits. If all cards also share the same suit, it becomes a straight flush.

For a specific straight, such as one with a high card of 10, you must account for all suits. If each card can be any suit (hearts, diamonds, clubs, or spades), there are \( 4^5 = 1,024 \) possible straight combinations. To calculate the probability, divide this by the total number of possible 5-card hands, which results in approximately 0.000394.

For a straight flush, all cards must be in one suit, significantly reducing the combinations. With only 10 possible sequences per suit and 4 suits, there are only 40 possible straight flush hands. Consequently, its probability is even lower, around 0.0000154.
Probability Theory Applications
Probability theory has wide applications in poker, influencing both strategic decision-making and long-term expectation management. In poker, probability helps players understand the likelihood of improving a hand based on unseen cards and adjusting strategies depending on these odds.

For example, when holding four consecutive cards, players calculate the probability of receiving the needed fifth card to complete a straight. These calculations stem from the total deck's remaining cards and the unseen cards. Applying these probabilities ensures that decisions during a game align with anticipated outcomes, aiding in proficient risk management.

Probabilities also underpin the calculation of expected value, which influences whether players should call, bet, or fold in any given situation.
Calculation of Card Combinations
Calculating combinations of cards is essential to determining poker hand probabilities. By breaking down the total possible outcomes and comparing them to the specific desired outcomes, you can understand the rarity and value of different hands.

As mentioned earlier, using combinations \( \binom{n}{k} \) allows you to calculate possible 5-card hands. For straights, it involves counting sequences of consecutive ranks, and for combinations like flushes, ensuring all cards are of the same suit.

Each poker hand configuration requires unique calculations to determine its frequency among all possible hand combinations. Mastering these calculations can significantly improve one’s understanding of the game and aid in making more strategic decisions.

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Most popular questions from this chapter

As of April 2006 , roughly 50 million .com web domain names were registered (e.g., yahoo.com). a. How many domain names consisting of just two letters in sequence can be formed? How many domain names of length two are there if digits as well as letters are permitted as characters? [Note: A character length of three or more is now mandated.] b. How many domain names are there consisting of three letters in sequence? How many of this length are there if either letters or digits are permitted? [Note: All are currently taken.] c. Answer the questions posed in (b) for four-character sequences. d. As of April \(2006,97,786\) of the four-character sequences using either letters or digits had not yet been claimed. If a four-character name is randomly selected, what is the probability that it is already owned?

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According to a July 31,2013 , posting on cnn.com subsequent to the death of a child who bit into a peanut, a 2010 study in the journal Pediatrics found that \(8 \%\) of children younger than 18 in the United States have at least one food allergy. Among those with food allergies, about \(39 \%\) had a history of severe reaction. a. If a child younger than 18 is randomly selected, what is the probability that he or she has at least one food allergy and a history of severe reaction? b. It was also reported that \(30 \%\) of those with an allergy in fact are allergic to multiple foods. If a child younger than 18 is randomly selected, what is the probability that he or she is allergic to multiple foods?

Use Venn diagrams to verify the following two relationships for any events \(A\) and \(B\) (these are called De Morgan's laws): a. \((A \cup B)^{\prime}=A^{\prime} \cap B^{\prime}\) b. \((A \cap B)^{\prime}=A^{\prime} \cup B^{\prime}\)

An ATM personal identification number (PIN) consists of four digits, each a \(0,1,2, \ldots 8\), or 9 , in succession. a. How many different possible PINs are there if there are no restrictions on the choice of digits? b. According to a representative at the author's local branch of Chase Bank, there are in fact restrictions on the choice of digits. The following choices are prohibited: (i) all four digits identical (ii) sequences of consecutive ascending or descending digits, such as 6543 (iii) any sequence starting with 19 (birth years are too easy to guess). So if one of the PINs in (a) is randomly selected, what is the probability that it will be a legitimate PIN (that is, not be one of the prohibited sequences)? c. Someone has stolen an ATM card and knows that the first and last digits of the PIN are 8 and 1 , respectively. He has three tries before the card is retained by the ATM (but does not realize that). So he randomly selects the \(2^{\text {nd }}\) and \(3^{\text {rd }}\) digits for the first try, then randomly selects a different pair of digits for the second try, and yet another randomly selected pair of digits for the third try (the individual knows about the restrictions described in (b) so selects only from the legitimate possibilities). What is the probability that the individual gains access to the account? d. Recalculate the probability in (c) if the first and last digits are 1 and 1 , respectively.

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