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As of April 2006 , roughly 50 million .com web domain names were registered (e.g., yahoo.com). a. How many domain names consisting of just two letters in sequence can be formed? How many domain names of length two are there if digits as well as letters are permitted as characters? [Note: A character length of three or more is now mandated.] b. How many domain names are there consisting of three letters in sequence? How many of this length are there if either letters or digits are permitted? [Note: All are currently taken.] c. Answer the questions posed in (b) for four-character sequences. d. As of April \(2006,97,786\) of the four-character sequences using either letters or digits had not yet been claimed. If a four-character name is randomly selected, what is the probability that it is already owned?

Short Answer

Expert verified
(a) 676, 1296; (b) 17576, 46656; (c) 456976, 1679616; (d) 0.942.

Step by step solution

01

Calculate Two-Letter Domains with Only Letters

To find the number of two-letter domain names using only letters, consider there are 26 letters in the English alphabet. Each letter can be chosen independently for each position in a two-character domain. Thus, the total number of combinations is given by the product of choices for each position: \[ 26 \times 26 = 676 \] So, there are 676 two-letter domain names using only letters.
02

Calculate Two-Letter Domains with Letters and Digits

When both letters and digits are allowed, there are 36 options for each character (26 letters + 10 digits). The number of possible domains is:\[ 36 \times 36 = 1296 \] So, there are 1296 two-character domain names when letters and digits are allowed.
03

Calculate Three-Letter Domains with Only Letters

With three letters in sequence, and each being one of the 26 letters, the total combinations are:\[ 26 \times 26 \times 26 = 26^3 = 17576 \] Thus, there are 17,576 three-letter domain names using only letters.
04

Calculate Three-Character Domains with Letters and Digits

With three characters and each being either a letter or a digit (36 possibilities):\[ 36 \times 36 \times 36 = 36^3 = 46656 \] Thus, there are 46,656 three-character domain names using letters and digits.
05

Calculate Four-Letter Domains with Only Letters

With four letters, each one of the 26 possibilities, the total combinations are:\[ 26 \times 26 \times 26 \times 26 = 26^4 = 456976 \] Thus, there are 456,976 four-letter domain names using only letters.
06

Calculate Four-Character Domains with Letters and Digits

For four-character domains allowing both letters and digits:\[ 36 \times 36 \times 36 \times 36 = 36^4 = 1679616 \] Thus, there are 1,679,616 four-character domain names when letters and digits are used.
07

Calculate the Probability of a Claimed Four-Character Domain

Out of a total of 1,679,616 possible four-character domains using letters and digits, 97,786 were unclaimed. The number of claimed domains is:\[ 1679616 - 97786 = 1581830 \] Thus, the probability that a randomly selected domain is already owned is:\[ \frac{1581830}{1679616} \approx 0.942 \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability
Probability is a core concept in mathematics that helps us understand how likely an event is to occur. It is calculated as the ratio of the number of favorable outcomes to the total number of possible outcomes. In the context of our domain names problem, we're interested in finding the probability that a four-character domain name is already taken.
To find this probability, we need to know the total number of possible four-character domains and how many of those domains are already claimed. We saw that there are 1,679,616 possible combinations for four-character domains using letters and digits. Out of these, 97,786 were unclaimed as of April 2006, meaning that 1,581,830 were claimed. Using this information, the probability that a randomly selected domain is claimed is calculated as follows:
\[ P(\text{claimed}) = \frac{\text{number of claimed domains}}{\text{total possible domains}} = \frac{1,581,830}{1,679,616} \approx 0.942 \]
This probability tells us that there is approximately a 94.2% chance that a randomly selected four-character domain is already owned. This high probability illustrates the rarity of finding available short domain names, which is why longer or more complicated names are often used.
Counting Principles
Counting principles are fundamental to solving problems related to combinations and permutations. They help us determine the number of ways an event can happen in a systematic way. In our domain name problem, we use the basic counting principle, which states that if one event can happen in "m" ways and a second can happen independently in "n" ways, the two events together can happen in \( m \times n \) ways.
When dealing with domain names, every character position in a domain name is considered an independent event. For a two-character domain using only letters, each character has 26 choices, leading to \( 26 \times 26 = 676 \) possible combinations. If we allow both letters and digits, each position has 36 options, increasing the possibilities to \( 36 \times 36 = 1,296 \).
The same principle applies to longer domain names like the three or four-character sequences we calculated. For instance, for three-letter domains using letters and digits, the number of possibilities is \( 36 \times 36 \times 36 = 46,656 \), demonstrating how the number of combinations rapidly grows with longer sequences.
Permutations and Combinations
Permutations and combinations are important concepts in combinatorics, helping us organize and count different arrangements. In our domain name example, the focus is on permutations, as the order in which characters appear in the sequence matters.
Permutations define the number of ways to arrange or order a set of elements. In our context, each letter or digit must be unique within its sequence and arranged to form a domain name. For a simple two-letter domain using only letters, there are \( 26! \) ways if ordering mattered for each letter, but since we allow repetition in positions, we simply multiply the choices for each.
The core difference between permutations and combinations is that permutations consider the sequence or order whereas combinations do not. For our exercise with domains, we are counting permutations due to the ordered sequence of characters required to form a valid domain name. Thus, using permutations ensures we capture every possible arrangement across the character positions, reflecting the massive number of domain possibilities.

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