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According to a July 31,2013 , posting on cnn.com subsequent to the death of a child who bit into a peanut, a 2010 study in the journal Pediatrics found that \(8 \%\) of children younger than 18 in the United States have at least one food allergy. Among those with food allergies, about \(39 \%\) had a history of severe reaction. a. If a child younger than 18 is randomly selected, what is the probability that he or she has at least one food allergy and a history of severe reaction? b. It was also reported that \(30 \%\) of those with an allergy in fact are allergic to multiple foods. If a child younger than 18 is randomly selected, what is the probability that he or she is allergic to multiple foods?

Short Answer

Expert verified
a. 0.0312; b. 0.024

Step by step solution

01

Understanding the Given Information

We are given that 8% of children younger than 18 have at least one food allergy, which translates to a probability of 0.08. Additionally, for those with food allergies, 39% have a history of severe reaction. This translates to a conditional probability of 0.39 for having a severe reaction given a food allergy.
02

Calculating Probability of Severe Reaction with Allergy

To find the probability that a randomly selected child has an allergy and a history of severe reaction, multiply the probability of having an allergy by the conditional probability of having a severe reaction given an allergy: \[0.08 \times 0.39 = 0.0312\].
03

Understanding Allergy to Multiple Foods

We are given that 30% of those with an allergy are allergic to multiple foods, translating to a conditional probability of 0.30 for being allergic to multiple foods given an allergy.
04

Calculating Probability of Multiple Food Allergies

To find the probability that a randomly selected child is allergic to multiple foods, multiply the probability of having an allergy by the conditional probability of being allergic to multiple foods given an allergy: \[0.08 \times 0.30 = 0.024\].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conditional Probability
Conditional probability is a fascinating concept that helps us understand how likely something is to happen, given that another event has already occurred. It's like asking: "Given that a child has a food allergy, what is the chance they will have a severe reaction?" This is precisely what's meant by conditional probability.

To calculate conditional probability, we start by identifying two events: let's call them Event A and Event B. The formula used is:
  • \( P(B | A) = \frac{P(A \cap B)}{P(A)} \)
Here, \( P(B | A) \) represents the probability of Event B occurring, provided Event A has also occurred. The numerator \( P(A \cap B) \) stands for the probability that both Event A and Event B happen, while \( P(A) \) is simply the likelihood of Event A happening on its own.

In our exercise, Event A is a child having a food allergy, and Event B is them having a severe reaction. Thus, the conditional probability of severe reaction given the allergy was calculated by multiplying the general probability of Event A (having an allergy) by the conditional probability of B given A.
Food Allergy Statistics
Food allergy statistics offer essential insights into how many individuals, particularly children, are affected by food allergies. These statistics help raise awareness and guide public health policies. According to the data given in our exercise, 8% of children under 18 in the United States have at least one food allergy. This number indicates that food allergies are not uncommon and can affect a significant portion of the youth population.

Additionally, among kids with food allergies, 39% have experienced severe reactions. "Severe reactions" may involve symptoms like difficulty breathing, hives, or even anaphylaxis, a life-threatening condition.

Understanding these numbers is crucial. They highlight the importance of monitoring food allergies and creating environments—like schools and public spaces—that are safer for allergic children. Parental and community awareness is key to reducing risks and improving children's quality of life.
Calculating Probabilities
Calculating probabilities involves determining how often an event will occur relative to all potential outcomes. It's a foundational concept in statistics that allows us to make informed predictions and decisions.

In the context of our exercise, to find the probability that a child has a food allergy and a history of severe reaction, we multiplied the probability of having an allergy (0.08) by the conditional probability of having a severe reaction given an allergy (0.39).
  • The result is \( 0.08 \times 0.39 = 0.0312 \).
This product gives us the combined probability of both events occurring together for a randomly selected child.

Similarly, to find the probability that a child is allergic to multiple foods, we multiplied the probability of having an allergy by the conditional probability of being allergic to multiple foods given an allergy, which was 30%. The calculation was as follows:
  • \( 0.08 \times 0.30 = 0.024 \).
Thus obtaining a probability of 0.024 for this specific occurrence.
Children's Health Statistics
Children's health statistics, like those related to food allergies, offer valuable insights into the health challenges faced by children today. They enable researchers and policymakers to focus on critical issues and work towards better health outcomes for young people.

In our example, statistics tell us that a significant 8% of children under 18 have a food allergy. These allergies can range from mild to severe, potentially affecting the child's daily activities and overall wellbeing.

Moreover, the fact that 39% of these children have experienced severe allergic reactions is a call for concern. It suggests the need for precautions and preparedness, such as having emergency medications like epinephrine available in schools and homes.

Also, the statistic that 30% of allergic children are allergic to multiple foods highlights the importance of comprehensive food labeling and better recipe transparency. With these efforts, risks can be minimized and the health and safety of children with allergies improved significantly.

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Most popular questions from this chapter

The population of a particular country consists of three ethnic groups. Each individual belongs to one of the four major blood groups. The accompanying joint probability table gives the proportions of individuals in the various ethnic group-blood group combinations. $$ \begin{array}{lccccc} &&&{\text { Blood Group }} \\ & & \text { O } & \mathbf{A} & \mathbf{B} & \mathbf{A B} \\ \hline {\text { Ethnic Group }} & \mathbf{1} & .082 & .106 & .008 & .004 \\ & \mathbf{2} & .135 & .141 & .018 & .006 \\ & \mathbf{3} & .215 & .200 & .065 & .020 \\ \hline \end{array} $$ Suppose that an individual is randomly selected from the population, and define events by \(A=\\{\) type A selected \(\\}, B=\\{\) type B selected \(\\}\), and \(C=\\{\) ethnic group 3 selected \(\\}\). a. Calculate \(P(A), P(C)\), and \(P(A \cap C)\). b. Calculate both \(P(A \mid C)\) and \(P(C \mid A)\), and explain in context what each of these probabilities represents. c. If the selected individual does not have type B blood, what is the probability that he or she is from ethnic group 1?

If \(P(B \mid A)>P(B)\), show that \(P\left(B^{\prime} \mid A\right)

Blue Cab operates \(15 \%\) of the taxis in a certain city, and Green Cab operates the other \(85 \%\). After a nighttime hitand-run accident involving a taxi, an eyewitness said the vehicle was blue. Suppose, though, that under night vision conditions, only \(80 \%\) of individuals can correctly distinguish between a blue and a green vehicle. What is the (posterior) probability that the taxi at fault was blue? In answering, be sure to indicate which probability rules you are using.

An ATM personal identification number (PIN) consists of four digits, each a \(0,1,2, \ldots 8\), or 9 , in succession. a. How many different possible PINs are there if there are no restrictions on the choice of digits? b. According to a representative at the author's local branch of Chase Bank, there are in fact restrictions on the choice of digits. The following choices are prohibited: (i) all four digits identical (ii) sequences of consecutive ascending or descending digits, such as 6543 (iii) any sequence starting with 19 (birth years are too easy to guess). So if one of the PINs in (a) is randomly selected, what is the probability that it will be a legitimate PIN (that is, not be one of the prohibited sequences)? c. Someone has stolen an ATM card and knows that the first and last digits of the PIN are 8 and 1 , respectively. He has three tries before the card is retained by the ATM (but does not realize that). So he randomly selects the \(2^{\text {nd }}\) and \(3^{\text {rd }}\) digits for the first try, then randomly selects a different pair of digits for the second try, and yet another randomly selected pair of digits for the third try (the individual knows about the restrictions described in (b) so selects only from the legitimate possibilities). What is the probability that the individual gains access to the account? d. Recalculate the probability in (c) if the first and last digits are 1 and 1 , respectively.

The three most popular options on a certain type of new car are a built-in GPS \((A)\), a sunroof \((B)\), and an automatic transmission \((C)\). If \(40 \%\) of all purchasers request \(A, 55 \%\) request \(B, 70 \%\) request \(C, 63 \%\) request \(A\) or \(B\), \(77 \%\) request \(A\) or \(C, 80 \%\) request \(B\) or \(C\), and \(85 \%\) request \(A\) or \(B\) or \(C\), determine the probabilities of the following events. [Hint: " \(A\) or \(B\) " is the event that at least one of the two options is requested; try drawing a Venn diagram and labeling all regions.] a. The next purchaser will request at least one of the three options. b. The next purchaser will select none of the three options. c. The next purchaser will request only an automatic transmission and not either of the other two options. d. The next purchaser will select exactly one of these three options.

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