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Show that if one event \(A\) is contained in another event \(B\) (i.e., \(A\) is a subset of \(B)\), then \(P(A) \leq P(B)\). [Hint: For such \(A\) and \(B, A\) and \(B \cap A^{\prime}\) are disjoint and \(B=\) \(A \cup\left(B \cap A^{\prime}\right)\), as can be seen from a Venn diagram.] For general \(A\) and \(B\), what does this imply about the relationship among \(P(A \cap B), P(A)\) and \(P(A \cup B)\) ?

Short Answer

Expert verified
If \(A \subseteq B\), then \(P(A) \leq P(B)\). For any \(A\) and \(B\), \(P(A \cap B) \leq P(A) \leq P(A \cup B)\).

Step by step solution

01

Understanding the Subset Relationship

Given that event \(A\) is a subset of event \(B\), denoted by \(A \subseteq B\), every outcome of \(A\) is also an outcome of \(B\). This basic set theory concept shows that everything in \(A\) is part of \(B\).
02

Exploring Event Probability

The probability of an event is the sum of the probabilities of its individual outcomes. For \(A \subseteq B\), all outcomes in \(A\) are also in \(B\), meaning that \(P(A)\) must be less than or equal to \(P(B)\).
03

Understanding Disjoint Sets

From the hint, consider the two events \(A\) and \(B \cap A^{\prime}\). These events are disjoint because \(A\) and the complement of \(A\) in \(B\) do not share any outcomes. Disjoint events have no overlap, so they do not affect each other's probabilities directly.
04

Combining Events

Using the union of disjoint events formula, we have \(B = A \cup (B \cap A^{\prime})\). Therefore, \(P(B) = P(A) + P(B \cap A^{\prime})\). Since \(P(B \cap A^{\prime}) \geq 0\), it follows that \(P(A) \leq P(B)\).
05

General Relationship of Events

For any two events \(A\) and \(B\), you can express their relationship in terms of probability as \(P(A \cap B) \leq P(A) \leq P(A \cup B)\). This implies that the probability of their intersection is never greater than the probability of \(A\), and \(A\) is contained within their union.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Subset Relationship
When we say that an event \(A\) is a subset of an event \(B\), we are using the language of set theory. This relationship, denoted \(A \subseteq B\), implies that every possible outcome in \(A\) is also found in \(B\). Imagine a simple scenario where we have a set of colored balls, and \(A\) represents red balls while \(B\) represents all red and blue balls. Since all red balls are part of the entire collection of red and blue balls, we can say \(A\) is a subset of \(B\).
Understanding subsets is crucial in grasping how probabilities are determined in several situations. When analyzing probabilities of events, knowing the subset relation helps predict outcomes more accurately and understand their likelihood.
Event Probability
The probability of an event, denoted as \(P(A)\), is calculated by considering the sum of probabilities of all the outcomes that make up that event. When \(A\) is a subset of \(B\), it directly influences their probabilities: \(P(A) \leq P(B)\). This relationship is intuitive; if event \(A\) is contained within a larger event \(B\), there is no chance for \(A\) to have a higher probability than \(B\).
So let's break it down:
  • Event \(A\): Includes some specific outcomes
  • Event \(B\): Includes all outcomes of \(A\) and potentially more
As a result, the combined likelihood of outcomes in \(A\) can't exceed that of \(B\). This realization helps us gauge and compare different event probabilities succinctly.
Disjoint Sets
In the context of probability, disjoint sets play an essential role. Two events are considered disjoint if they have no common outcomes, meaning the occurrence of one event excludes the other.
In our subset example, consider events \(A\) and \(B \cap A'\). The latter represents the outcomes in \(B\) that are not in \(A\). Since \(A\) and \(B \cap A'\) do not share any outcomes, they are disjoint.
  • This is crucial because disjoint events do not influence each other's probability; their intersection is void.
  • Working with disjoint events often simplifies probability calculations, as we may not need to account for overlap.
Recognizing disjoint events assists in accurately applying probabilities to diverse scenarios, leading to effective decision-making.
Union of Events
The union of two events \(A\) and \(B\), denoted \(A \cup B\), represents all the outcomes that belong to either \(A\), \(B\), or both. For example, if you are considering event \(B\) as the union \(A \cup (B \cap A')\), this tells us how probabilities sum up when events are combined.
The probability of the union is given by:
  • \(P(A \cup B) = P(A) + P(B \cap A')\), where \(B\) covers all outcomes of both events.
Thus, these combinations respect the fundamental principle: \(P(A) \leq P(A \cup B)\).
Understanding the union of events is immensely helpful for predicting probabilities in more complex scenarios, where multiple outcomes are interdependent or overlapping. By breaking down events into unions, the calculation and assessment of probabilities become more manageable.

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Most popular questions from this chapter

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