/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 23 Acrylic bone cement is commonly ... [FREE SOLUTION] | 91Ó°ÊÓ

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Acrylic bone cement is commonly used in total joint arthroplasty as a grout that allows for the smooth transfer of loads from a metal prosthesis to bone structure. The paper "Validation of the Small-Punch Test as a Technique for Characterizing the Mechanical Properties of Acrylic Bone Cement" (J. of Engr. in Med., 2006: 11-21) gave the following data on breaking force \((\mathrm{N})\) : \begin{tabular}{lcccc} Temp & Medium & \(\boldsymbol{n}\) & \(\bar{x}\) & \(\boldsymbol{s}\) \\ \hline \(22^{\circ}\) & Dry & 6 & \(170.60\) & \(39.08\) \\ \(37^{\circ}\) & Dry & 6 & \(325.73\) & \(34.97\) \\ \(22^{\circ}\) & Wet & 6 & \(366.36\) & \(34.82\) \\ \(37^{\circ}\) & Wet & 6 & \(306.09\) & \(41.97\) \\ \hline \end{tabular} Assume that all population distributions are normal. a. Estimate true average breaking force in a dry medium at \(37^{\circ}\) in a way that conveys information about reliability and precision, and interpret your estimate. b. Estimate the difference between true average breaking force in a dry medium at \(37^{\circ}\) and true average force at the same temperature in a wet medium, and do so in a way that conveys information about precision and reliability. Then interpret your estimate. c. Is there strong evidence for concluding that true average force in a dry medium at the higher temperature exceeds that at the lower temperature by more than \(100 \mathrm{~N}\) ?

Short Answer

Expert verified
a. 325.73 N with 95% CI: (289.06, 362.40) b. Difference CI: (-31.30, 70.58) c. Yes, evidence supports the claim.

Step by step solution

01

Calculate the Confidence Interval for Dry Medium at 37°C

To estimate the true average breaking force in a dry medium at 37°C, we calculate the 95% confidence interval (CI) using the formula: \(\bar{x} \pm t_{\alpha/2,\, n-1} \times \frac{s}{\sqrt{n}}\)where \( \bar{x} = 325.73 \), \( s = 34.97 \), and \( n = 6 \). The critical t-value \( t_{0.025, 5} \) is approximately 2.571.Calculating:\[CI = 325.73 \pm 2.571 \times \frac{34.97}{\sqrt{6}}\]\[CI = 325.73 \pm 36.67\]Thus, the 95% CI is (289.06, 362.40).
02

Calculate the Difference in Means and Its Confidence Interval

We estimate the difference between true average breaking force in dry medium at 37°C and wet medium at the same temperature. Use the formula for the CI difference of means:\((\bar{x}_1 - \bar{x}_2) \pm t_{\alpha/2,\, n_1+n_2-2} \times SE\)Where \( SE = \sqrt{\frac{s_{dry}^2}{n_{dry}} + \frac{s_{wet}^2}{n_{wet}}} \). Values: \(\bar{x}_{dry}=325.73\), \(\bar{x}_{wet}=306.09\), \(s_{dry}=34.97\), \(s_{wet}=41.97\).Compute:\[SE = \sqrt{\frac{34.97^2}{6} + \frac{41.97^2}{6}} = 22.86\]Difference in means \(= 19.64\).\[CI = 19.64 \pm 2.228 \times 22.86\]\[CI = 19.64 \pm 50.94\]The 95% CI for difference is (-31.30, 70.58).
03

Hypothesis Test for Dry Medium Forces at Different Temperatures

To decide if the true average force in a dry medium at 37°C exceeds that at 22°C by more than 100N, set up hypotheses:\( H_0: \mu_{37} - \mu_{22} \leq 100 \) and \( H_a: \mu_{37} - \mu_{22} > 100 \).Calculate:\(\Delta \bar{x} = 325.73 - 170.60 = 155.13\).SE of difference: \(SE_{diff} = \sqrt{\frac{39.08^2}{6} + \frac{34.97^2}{6}} = 22.18\).T-statistic:\[T = \frac{155.13 - 100}{22.18} = 2.48\]Comparing with \( t_{0.05, 10} \approx 1.812 \), we find T > critical value; thus, reject \( H_0 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Confidence Intervals
Confidence intervals are essential tools in statistics that give us a range of values where we might expect to find the true value of a parameter. These intervals are calculated from sample data and help us understand how reliable and precise an estimate is.

A confidence interval is usually expressed as: \( \bar{x} \pm t_{\alpha/2, n-1} \times \frac{s}{\sqrt{n}} \). Here, \( \bar{x} \) is the sample mean, \( s \) is the standard deviation, and \( n \) is the sample size. \( t_{\alpha/2, n-1} \) is a t-score that depends on our confidence level (like 95% or 99%) and the degrees of freedom (\( n-1 \)).

Using confidence intervals, we can convey the precision and reliability of our estimation. For example, if we have a 95% confidence interval for a parameter, it means that there's a 95% chance that this interval contains the true parameter value. In hypothesis testing, confidence intervals are significant because they provide a way to visually assess how estimates like mean differences line up with zero or other critical values.
T-Distribution
The t-distribution is a probability distribution used in statistics when the sample size is small, and the population standard deviation is unknown.

It is similar to the normal distribution but with heavier tails, which means it can account for the extra variability that might occur with small samples. The t-distribution becomes more like the normal distribution as the sample size increases.
  • The mean of a t-distribution is zero.
  • Its shape is symmetric.
  • The variance is greater than one, though it approaches one with larger samples.
The shape of the t-distribution is determined by degrees of freedom (df), which is generally \( n-1 \) for a sample of size \( n \), affecting the width and height of the distribution curve.

When calculating confidence intervals for a mean, use the t-distribution if the sample size is less than 30, or if the population standard deviation is not known. It gives us the "critical value" which helps construct the interval by providing a way to understand how much variation we might expect by chance when taking different samples.
Mechanical Properties
Mechanical properties refer to the behavior of a material when forces are applied to it. These properties can include strength, flexibility, stiffness, and durability.

When evaluating something such as acrylic bone cement, understanding these mechanical properties is crucial, especially since the material is used in medical applications where safety and reliability can't be compromised.
  • Breaking force: One key property often measured is the breaking force, which is the stress or force needed to break a sample. It tells us about the material's strength.
  • Effect of Environment: Temperature and medium (dry or wet) can significantly influence mechanical properties as materials often behave differently under varying conditions.
  • Testing methods: Techniques like the "Small-Punch Test" allow researchers to measure these properties accurately in laboratory settings.
By understanding these properties and how they change under different conditions, engineers and medical professionals can better predict a material's performance in real-world scenarios, ensuring structures can handle expected loads and stresses safely.
Estimation Techniques
In statistics, estimation techniques are methods used to infer the properties of a population based on sample data.

These techniques help us make educated guesses about unknown parameters using known sample statistics.
  • Point Estimate: This involves using a single value, such as the sample mean, to estimate a population parameter.
  • Interval Estimate: Unlike point estimates that give a single value, interval estimates provide a range within which the parameter value is expected to lie, offering more information about precision.
  • Hypothesis Testing: This is a step beyond estimation and involves making decisions or inferences about the population based on sample data. It typically contrasts a null hypothesis against an alternative hypothesis.
Different estimation techniques are valuable because they can communicate uncertainty, reliability, and variability about the estimates.

Selecting the appropriate technique depends on the dataset and the problem at hand, as well as the desired level of precision and confidence.

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Most popular questions from this chapter

The level of monoamine oxidase (MAO) activity in blood platelets (nm/mg protein/h) was determined for each individual in a sample of 43 chronic schizophrenics, resulting in \(\bar{x}=2.69\) and \(s_{1}=2.30\), as well as for 45 normal subjects, resulting in \(\bar{y}=6.35\) and \(s_{2}=4.03\). Does this data strongly suggest that true average MAO activity for normal subjects is more than twice the activity level for schizophrenics? Derive a test procedure and carry out the test using \(\alpha=.01\). [Hint: \(H_{0}\) and \(H_{a}\) here have a different form from the three standard cases. Let \(\mu_{1}\) and \(\mu_{2}\) refer to true average MAO activity for schizophrenics and normal subjects, respectively, and consider the parameter \(\theta=2 \mu_{1}-\mu_{2}\). Write \(H_{0}\) and \(H_{2}\) in terms of \(\theta\), estimate \(\theta\), and derive \(\overrightarrow{\sigma_{\theta}}\) ("Reduced Monoamine Oxidase Activity in Blood Platelets from Schizophrenic Patients, "Nature, July 28, 1972: \(225-226\) ).]

Let \(\mu_{1}\) and \(\mu_{2}\) denote true average densities for two different types of brick. Assuming normality of the two density distributions, test \(H_{0}: \mu_{1}-\mu_{2}=0\) versus \(H_{\mathrm{a}}: \mu_{1}-\mu_{2} \neq 0\) using the following data: \(m=6, \bar{x}=22.73, s_{1}=.164\), \(n=5, \bar{y}=21.95\), and \(s_{2}=.240\).

Do teachers find their work rewarding and satisfying? The article "Work- Related Attitudes" (Psychological Reports, 1991: 443-450) reports the results of a survey of 395 elementary school teachers and 266 high school teachers. Of the elementary school teachers, 224 said they were very satisfied with their jobs, whereas 126 of the high school teachers were very satisfied with their work. Estimate the difference between the proportion of all elementary school teachers who are very satisfied and all high school teachers who are very satisfied by calculating and interpreting a CI.

The accompanying data was obtained in a study to evaluate the liquefaction potential at a proposed nuclear power station ("Cyclic Strengths Compared for Two Sampling Techniques," \(J\). of the Geotechnical Division, Am. Soc. Civil Engrs. Proceedings, 1981: 563-576). Before cyclic strength testing, soil samples were gathered using both a pitcher tube method and a block method, resulting in the following observed values of dry density \(\left(\mathrm{lb} / \mathrm{ft}^{3}\right)\) : \(\begin{array}{lrrrr}\text { Pitcher sampling } & 101.1 & 111.1 & 107.6 & 98.1 \\\ & 99.5 & 98.7 & 103.3 & 108.9 \\ & 109.1 & 104.1 & 110.0 & 98.4 \\ & 105.1 & 104.5 & 105.7 & 103.3 \\ & 100.3 & 102.6 & 101.7 & 105.4 \\ & 99.6 & 103.3 & 102.1 & 104.3 \\ \text { Block sampling } & 107.1 & 105.0 & 98.0 & 97.9 \\ & 103.3 & 104.6 & 100.1 & 98.2 \\ & 97.9 & 103.2 & 96.9 & \end{array}\) Calculate and interpret a \(95 \% \mathrm{CI}\) for the difference between true average dry densities for the two sampling methods.

The level of lead in the blood was determined for a sample of 152 male hazardous-waste workers ages \(20-30\) and also for a sample of 86 female workers, resulting in a mean \(\pm\) standard error of \(5.5 \pm 0.3\) for the men and \(3.8 \pm 0.2\) for the women ("Temporal Changes in Blood Lead Levels of Hazardous Waste Workers in New Jersey, 19841987, Environ. Monitoring and Assessment, 1993: 99-107). Calculate an estimate of the difference between true average blood lead levels for male and female workers in a way that provides information about reliability and precision.

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