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a. Show for the upper-tailed test with \(\sigma_{1}\) and \(\sigma_{2}\) known that as either \(m\) or \(n\) increases, \(\beta\) decreases when \(\mu_{1}-\mu_{2}>\Delta_{0}\) b. For the case of equal sample sizes \((m=n)\) and fixed \(\alpha\), what happens to the necessary sample size \(n\) as \(\beta\) is decreased, where \(\beta\) is the desired type II error probability at a fixed alternative?

Short Answer

Expert verified
As either m or n increases, \(\beta\) decreases. For equal sample sizes and fixed \(\alpha\), \(n\) must increase as \(\beta\) decreases.

Step by step solution

01

Understand the Problem

We need to consider an upper-tailed hypothesis test for two population means given known population variances (\(\sigma_1^2\) and \(\sigma_2^2\)). Specifically, we want to show how increasing sample sizes \(m\) or \(n\) affects the type II error probability \(\beta\), and also examine the relationship between \(n\) and \(\beta\) when \(m = n\) and \(\alpha\) is fixed.
02

Set Up the Upper-Tailed Test

In a hypothesis test for the difference in means, the null hypothesis \(H_0: \mu_1 - \mu_2 = \Delta_0\) is tested against the alternative hypothesis \(H_a: \mu_1 - \mu_2 > \Delta_0\). The test statistic is given by \(Z = \frac{(\bar{X} - \bar{Y}) - \Delta_0}{{\sqrt{\frac{\sigma_1^2}{m} + \frac{\sigma_2^2}{n}}}}\), which follows a standard normal distribution under the null.
03

Analyze the Effect of Increasing Sample Sizes

As the sample sizes \(m\) or \(n\) increase, the standard error \(\sqrt{\frac{\sigma_1^2}{m} + \frac{\sigma_2^2}{n}}\) decreases. This makes the magnitude of the test statistic \(Z\) larger under the alternative hypothesis (assuming \(\mu_1 - \mu_2 > \Delta_0\)), which increases the power of the test and hence decreases \(\beta\), the probability of a type II error.
04

Consider Equal Sample Sizes and a Fixed \(\alpha\)

With \(m = n\), the expression for the standard error simplifies to \(\sqrt{2 \frac{\sigma^2}{n}}\). If \(\beta\) is decreased (i.e., higher power) while \(\alpha\) is kept constant, the critical value for \(Z\) remains the same, but the magnitude of \(Z\) must be increased under \(H_a\). This requires a larger sample size \(n\). Thus, as \(\beta\) decreases, \(n\) must increase to maintain the fixed \(\alpha\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Type II Error
Type II error happens when the hypothesis test fails to reject the null hypothesis, even though the alternative hypothesis is true. In simpler terms, it's a false negative result. This type of error is related to the probability \( \beta \), which signifies the test's chance of missing a true effect.

The importance of understanding Type II error lies in making informed decisions. For instance, in a clinical trial, failing to detect a true effect could mean not administering a beneficial treatment. In hypothesis testing, every test usually has a balance to maintain between Type I error (\( \alpha \), a false positive) and Type II error (\( \beta \)).
  • Smaller \( \beta \) value: going for smaller type II error typically means higher power. Power is the ability of the test to correctly identify a true effect (1-\( \beta \)).
  • Understanding \( \beta \) leads to better test design: this explains why changing sample size affects \( \beta \).
Adjusting \( \beta \) involves sample size modifications. An increase in sample size often results in a lower \( \beta \), indicating improved sensitivity of the test.
Sample Size
In hypothesis testing, the sample size \( n \) plays a crucial role in determining the accuracy and power of the test. The sample size affects the standard error of the test's statistical measurements.

Larger sample sizes mean more accurate estimates of the population parameters, thus stronger evidence when testing hypotheses. Here's how sample size specifically impacts hypothesis tests:
  • Reducing standard error: larger samples lead to smaller standard errors, making tests more sensitive.
  • Influencing test power and type II error: increasing sample sizes enhances test power and reduces type II error \( \beta \).
  • Equal-sized groups \( m = n \): when working with equal sample sizes and fixed \( \alpha \), further increasing \( n \) decreases \( \beta \).
It is crucial for researchers to balance resources, study constraints, and desired power levels to determine the optimal sample size. In practical scenarios, determining the right \( n \) can help ensure that the test conclusions are both accurate and reliable.
Population Means
Population means are the average values of a variable from entire groups of interest. In hypothesis testing, comparing population means helps identify if there is a significant difference between groups.

Consider a situation where you have two populations with means \( \mu_1 \) and \( \mu_2 \), and you're interested to see if their difference is greater than a threshold \( \Delta_0 \). Hypothesis testing for population means typically involves:
  • Formulating the null hypothesis \( H_0: \mu_1 - \mu_2 = \Delta_0 \) and the alternative hypothesis \( H_a: \mu_1 - \mu_2 > \Delta_0 \).
  • Using test statistics to evaluate differences: typically with a Z-test or T-test dependent on known variances and sample sizes.
  • Interpreting results: checking if the observed differences are statistically significant compared to theoretical expectations.
Understanding population means helps in making data-driven decisions, by confirming whether any observed differences are due to random chance or if they're significant enough to warrant further investigation.

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Most popular questions from this chapter

Persons having Reynaud's syndrome are apt to suffer a sudden impairment of blood circulation in fingers and toes. In an experiment to study the extent of this impairment, each subject immersed a forefinger in water and the resulting heat output \(\left(\mathrm{cal} / \mathrm{cm}^{2} / \mathrm{min}\right)\) was measured. For \(m=10\) subjects with the syndrome, the average heat output was \(\bar{x}=.64\), and for \(n=10\) nonsufferers, the average output was \(2.05\). Let \(\mu_{1}\) and \(\mu_{2}\) denote the true average heat outputs for the two types of subjects. Assume that the two distributions of heat output are normal with \(\sigma_{1}=2\) and \(\sigma_{2}=.4\). a. Consider testing \(H_{0}: \mu_{1}-\mu_{2}=-1.0\) versus \(H_{a}: \mu_{1}-\) \(\mu_{2}<-1.0\) at level .01. Describe in words what \(H_{\mathrm{a}}\) says, and then carry out the test. b. Compute the \(P\)-value for the value of \(Z\) obtained in part (a). c. What is the probability of a type II error when the actual difference between \(\mu_{1}\) and \(\mu_{2}\) is \(\mu_{1}-\mu_{2}=-1.2\) ? d. Assuming that \(m=n\), what sample sizes are required to ensure that \(\beta=\), l when \(\mu_{1}-\mu_{2}=-1,2\) ?

Give as much information as you can about the \(P\)-value of the \(F\) test in each of the following situations: a. \(v_{1}=5, v_{2}=10\), upper-tailed test, \(f=4.75\) b. \(v_{1}=5, v_{2}=10\), upper-tailed test, \(f=2.00\) c. \(v_{1}=5, v_{2}=10\), two-tailed test, \(f=5.64\) d. \(v_{1}=5, v_{2}=10\), lower-tailed test, \(f=.200\) e. \(v_{1}=35, v_{2}=20\), upper-tailed test, \(f=3.24\)

The level of lead in the blood was determined for a sample of 152 male hazardous-waste workers ages \(20-30\) and also for a sample of 86 female workers, resulting in a mean \(\pm\) standard error of \(5.5 \pm 0.3\) for the men and \(3.8 \pm 0.2\) for the women ("Temporal Changes in Blood Lead Levels of Hazardous Waste Workers in New Jersey, 19841987, Environ. Monitoring and Assessment, 1993: 99-107). Calculate an estimate of the difference between true average blood lead levels for male and female workers in a way that provides information about reliability and precision.

Acrylic bone cement is commonly used in total joint arthroplasty as a grout that allows for the smooth transfer of loads from a metal prosthesis to bone structure. The paper "Validation of the Small-Punch Test as a Technique for Characterizing the Mechanical Properties of Acrylic Bone Cement" (J. of Engr. in Med., 2006: 11-21) gave the following data on breaking force \((\mathrm{N})\) : \begin{tabular}{lcccc} Temp & Medium & \(\boldsymbol{n}\) & \(\bar{x}\) & \(\boldsymbol{s}\) \\ \hline \(22^{\circ}\) & Dry & 6 & \(170.60\) & \(39.08\) \\ \(37^{\circ}\) & Dry & 6 & \(325.73\) & \(34.97\) \\ \(22^{\circ}\) & Wet & 6 & \(366.36\) & \(34.82\) \\ \(37^{\circ}\) & Wet & 6 & \(306.09\) & \(41.97\) \\ \hline \end{tabular} Assume that all population distributions are normal. a. Estimate true average breaking force in a dry medium at \(37^{\circ}\) in a way that conveys information about reliability and precision, and interpret your estimate. b. Estimate the difference between true average breaking force in a dry medium at \(37^{\circ}\) and true average force at the same temperature in a wet medium, and do so in a way that conveys information about precision and reliability. Then interpret your estimate. c. Is there strong evidence for concluding that true average force in a dry medium at the higher temperature exceeds that at the lower temperature by more than \(100 \mathrm{~N}\) ?

Determine the number of degrees of freedom for the twosample \(t\) test or \(\mathrm{CI}\) in each of the following situations: a. \(m=10, n=10, s_{1}=5.0, s_{2}=6.0\) b. \(m=10, n=15, s_{1}=5.0, s_{2}=6.0\) c. \(m=10, n=15, s_{1}=2.0, s_{2}=6.0\) d. \(m=12, n=24, s_{1}=5.0, s_{2}=6.0\)

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