91影视

Two are more numbers of mathematical average called mean.

The T Method for Identifying Significantly Different 渭i 鈥檚

Find value \({Q_{\alpha ,}}I,{I_{\left( {j - 1} \right)}}\)at the Table A.10. in the appendix of the book for given \(\alpha \).

Compute and list the sample means in increasing order. Calculate

\(w = {Q_{\alpha ,}}I,{I_{\left( {j - 1} \right)}}.\sqrt {\frac{{MSE}}{J}} \)

underline pairs of the sample means that differ by less than W . The pair of sample which are not underscored by the same line corresponding of population or treatment means that they are significantly different.

From the mentioned table, and\(\alpha = 0.05\)\(I = 6,J = 26\)

\({Q_{\alpha ,}}I,{I_{\left( {J - 1} \right)}} = {Q_{0.05,6,150}} \approx {Q_{0.05,6,120 = 4.1}}\)

\( = 4.02\)

The value of of estimate using the table.

\(MSE = 13.929\)

Compute the w value as

\(w = {Q_{\alpha ,}}I,{I_{\left( {j - 1} \right)}}.\sqrt {\frac{{MSE}}{J}} = 4.1.\sqrt {\frac{{13.929}}{{26}}} = 3\)

First order the sample means

\({\overline x _{3.}} < {\overline x _{1.}}\,\,\, < {\overline x _{4.}}\,\, < {\overline x _{2.}} < {\overline x _{5.}} < {\overline x _{6.}}\,{\overline x _{7.}}\,\)

The bold value are smaller than w

The following table

Differences can be computed manually very easy thus there is not going to be an explanation of the part.conclusion is that three group have been created,first group containing only mixture\(1\),second group containing mixture\(2,3\,and\,4\)third group containing mixture\(5,6\) between the group there is significant difference but within the groups there are no significant differences.This can be represented using line .

\(\begin{aligned}{l}\,\,\,\,\,{\overline x _{1.}}\\\underline {14.18} \end{aligned}\) \(\begin{aligned}{l}\,\,\,\,\,{\overline x _{2.}}\,\,\,\,\,\,\,\,\,{\overline x _{3.}}\,\,\,\,\,\,\,\,{\overline x _{4.}}\\\underline {\,\,17.94\,\,\,\,\,18\,\,\,\,\,\,18\,\,} \,\,\end{aligned}\) \(\begin{aligned}{l}\,\,\,\,\,{\overline x _{5.}}\,\,\,\,\,\,\,\,\,{\overline x _{6.}}\,\,\,\,\,\\\underline {\,\,25.74\,\,\,\,\,26.67\,\,\,} \end{aligned}\)

Hence,

\(\begin{aligned}{l}\,\,\,\,\,{\overline x _{1.}}\\\underline {14.18} \end{aligned}\) \(\begin{aligned}{l}\,\,\,\,\,{\overline x _{2.}}\,\,\,\,\,\,\,\,\,{\overline x _{3.}}\,\,\,\,\,\,\,\,{\overline x _{4.}}\\\underline {\,\,17.94\,\,\,\,\,18\,\,\,\,\,\,18\,\,} \,\,\end{aligned}\)\(\begin{aligned}{l}\,\,\,\,\,{\overline x _{5.}}\,\,\,\,\,\,\,\,\,{\overline x _{6.}}\,\,\,\,\,\\\underline {\,\,25.74\,\,\,\,\,26.67\,\,\,} \end{aligned}\)