/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q32E An electronics store is offering... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

An electronics store is offering a special price on a complete set of components (receiver, compact disc player, speakers, turntable). A purchaser is offered a choice of manufacturer for each component:

A switchboard display in the store allows a customer to hook together any selection of components (consisting of one of each type). Use the product rules to answer the following questions:

a. In how many ways can one component of each type be selected?

b. In how many ways can components be selected if both the receiver and the compact disc player are to be Sony?

c. In how many ways can components be selected if none is to be Sony?

d. In how many ways can a selection be made if at least one Sony component is to be included?

e. If someone flips switches on the selection in a completely random fashion, what is the probability that the system selected contains at least one Sony component? Exactly one Sony component?

Short Answer

Expert verified
  1. \({\rm{240}}\) ways
  2. \({\rm{12}}\) ways
  3. \({\rm{108}}\) ways
  4. \({\rm{132}}\) ways
  5. At least one sony component

\({\rm{P( }}\)at least one sony component\({\rm{) = }}\frac{{{\rm{11}}}}{{{\rm{20}}}}{\rm{ = 0}}{\rm{.55 = 55\% }}\)

Exactly one sony cokmponent

\({\rm{P(}}\)exactly one sony component\({\rm{) = }}\frac{{{\rm{33}}}}{{{\rm{80}}}}{\rm{ = 0}}{\rm{.4125 = 41}}{\rm{.25\% }}\)

Step by step solution

01

Definition of product rule and also types of component

The product rule of probability refers to the occurrence of two or more independent occurrences at the same time. This is the sum of the likelihood of each of these occurrences occurring independently.

02

Determining the ways in which one can component of each type be selected 

Receiver, CD player, speakers, and turntable are the four sorts of components. With the exception of the receiver (which has five manufacturers) and speakers, all have four possible manufacturers (which have \({\rm{3}}\) possible manufacturers).

Receiver: \({\rm{5}}\) options

There are four methods to use a compact disc player.

There are three options for speakers.

\({\rm{4}}\)different ways to turn the turntable

The basic counting principle is as follows: If one event may happen in \({\rm{m}}\) ways and another can happen in \({\rm{n}}\)ways, the total number of ways the two events can happen in order is \({\rm{m*n}}\)

Make use of the basic counting principle

\({\rm{5*4*3*4 = 240}}\)

03

Determining the ways in which can components be selected if both the receiver and the compact disc player are to be Sony 

Counting principle: If one event may happen in\({\rm{m}}\)ways and another can happen in\({\rm{n}}\)ways, the number of ways the two events can happen in order is\({\rm{m*n}}\)

There is just one method to use the receiver (Sony), and there is only one way to use the compact disc player (Sony) (Sony)

\({\rm{1*1*3*4 = 12}}\)

04

Determining the ways in which components be selected if none is to be Sony?

The counting principle is as follows: If one event may happen in \({\rm{m}}\) ways and another can happen in \({\rm{n}}\) ways, the total number of ways the two events can happen in order is \({\rm{m*n}}\)

We are unable to choose Sony. The receiver only has four options (rather than five), the CD player only has three options (rather than four), and the turntable only has three options (instead of\({\rm{4}}\)).

\({\rm{4*3*3*3 = 108}}\)

05

Determining the ways in which selection be made if at least one Sony component is to be included

We know there are a total of 240 potential methods from section (a).

We know there are 108 methods to do it without using a Sony component because of section (c).

The total number of potential ways to choose at least one Sony component is then reduced by the number of conceivable ways to choose no Sony component:

\({\rm{240 - 108 = 132}}\)

06

Determining the probability that the system selected contains at least one Sony component

If we choose a Sony component, the other components can't have Sony components in them. Then, using the basic counting concept, we get:

Additional from the Sony receiver, there are no other Sony components: \({\rm{1*3*3*3 = 27}}\)

There are no additional Sony components save the compact disc player: \({\rm{4*1*3*3 = 36}}\)

There are no additional Sony components save the turntable: \({\rm{4*3*3*1 = 36}}\)

The number of positive outcomes divided by the total number of potential outcomes equals the probability:

\(\begin{aligned}{{\rm{P(\;At least one Sony component\;) = }}\frac{{{\rm{\# \;of favorable outcomes\;}}}}{{{\rm{\# \;of possible outcomes\;}}}}{\rm{ = }}\frac{{{\rm{132}}}}{{{\rm{240}}}}{\rm{ = }}\frac{{{\rm{11}}}}{{{\rm{20}}}}{\rm{ = 0}}{\rm{.55 = 55\% }}}\\{{\rm{P(\;Exactly one Sony component\;) = }}\frac{{{\rm{\# \;of favorable outcomes\;}}}}{{{\rm{\# \;of possible outcomes\;}}}}{\rm{ = }}\frac{{{\rm{27 + 36 + 36}}}}{{{\rm{240}}}}{\rm{ = }}\frac{{{\rm{99}}}}{{{\rm{240}}}}{\rm{ = }}\frac{{{\rm{33}}}}{{{\rm{80}}}}{\rm{ = 0}}{\rm{.4125 = 41}}{\rm{.25\% }}}\end{aligned}\)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

An experimenter is studying the effects of temperature, pressure, and type of catalyst on yield from a certain chemical reaction. Three different temperatures, four different pressures, and five different catalysts are under consideration.

a. If any particular experimental run involves the use of a single temperature, pressure, and catalyst, how many experimental runs are possible?

b. How many experimental runs are there that involve use of the lowest temperature and two lowest pressures?

c. Suppose that five different experimental runs are to be made on the first day of experimentation. If the five are randomly selected from among all the possibilities, so that any group of five has the same probability of selection, what is the probability that a different catalyst is used on each run?

Consider independently rolling two fair dice, one red and the other green. Let A be the event that the red die shows \({\rm{3}}\) dots, B be the event that the green die shows \({\rm{4}}\) dots, and C be the event that the total number of dots showing on the two dice is \({\rm{7}}\). Are these events pairwise independent (i.e., are \({\rm{A}}\) and \({\rm{B}}\) independent events, are \({\rm{A}}\) and \({\rm{C}}\) independent, and are \({\rm{B}}\) and \({\rm{C}}\) independent)? Are the three events mutually independent?

A box in a supply room contains \({\rm{15}}\) compact fluorescent lightbulbs, of which \({\rm{5}}\) are rated \({\rm{13}}\)-watt, \({\rm{6}}\)are rated \({\rm{18}}\)-watt, and \({\rm{4}}\) are rated \({\rm{23}}\)-watt. Suppose that three of these bulbs are randomly selected.

a. What is the probability that exactly two of the selected bulbs are rated \({\rm{23}}\)-watt?

b. What is the probability that all three of the bulbs have the same rating?

c. What is the probability that one bulb of each type is selected?

d. If bulbs are selected one by one until a \({\rm{23}}\)-watt bulb is obtained, what is the probability that it is necessary to examine at least 6 bulbs?

An aircraft seam requires \({\rm{25}}\) rivets. The seam will have to be reworked if any of these rivets is defective. Suppose rivets are defective independently of one another, each with the same probability.

a. If \({\rm{15\% }}\)of all seams need reworking, what is the probability that a rivet is defective?

b. How small should the probability of a defective rivet be to ensure that only \({\rm{10\% }}\) of all seams need reworking?

In five-card poker, a straight consists of five cards with adjacent denominations (e.g., \({\rm{9}}\)of clubs, \({\rm{10}}\)of hearts, jack of hearts, queen of spades, and king of clubs). Assuming that aces can be high or low, if you are dealt a five-card hand, what is the probability that it will be a straight with high card \({\rm{10}}\)? What is the probability that it will be a straight? What is the probability that it will be a straight flush (all cards in the same suit)?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.