/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q15E Consider the type of clothes dry... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 2: Q15E (page 65)

Consider the type of clothes dryer (gas or electric) purchased by each of five different customers at a certain store.

a. If the probability that at most one of these purchases an electric dryer is .428, what is the probability that at least two purchase an electric dryer?

b. If P(all five purchase gas) =.116 and P(all five purchase electric) =.005, what is the probability that at least one of each type is purchased?

Short Answer

Expert verified

a. Theprobability that at least two purchase an electric dryer is 0.572

b. The probability that at least one of each type is purchased is 0.879

Step by step solution

01

Given information

Five different customers at a certain store purchased two types of clothes dryer.

02

Compute the probability

a.

The probability that at most one of these purchases an electric dryer is 0.428.

The probability that at least two purchase an electric dryer is computed as,

\(\begin{aligned}1 - P\left( {atmost\;one\;of{\rm{ }}these{\rm{ }}purchases{\rm{ }}an{\rm{ }}electric{\rm{ }}dryer} \right) &= 1 - 0.428\\ &= 0.572\end{aligned}\)

Therefore, the probability that at least two purchase an electric dryer is 0.572.

b.

The probability that all five purchase gas is 0.116.

The probability that all five purchase electric is 0.005.

The probability that at least one of each type is purchased is computed as,

\(\begin{aligned}P\left( {atleast\;one\;of\,each\;type} \right) &= 1 - \left( {P\left( {all\;five\;purchase\;gas} \right) + P\left( {all\;five\;purchase\;electric} \right)} \right)\\ &= 1 - \left( {0.116 + 0.005} \right)\\ &= 0.879\end{aligned}\)

Therefore, the probability that at least one of each type is purchased is 0.879.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The accompanying table gives information on the type of coffee selected by someone purchasing a single cup at a particular airport kiosk.

Small

Medium

Large

Regular

\(14\% \)

\(20\% \)

\(26\% \)

Decaf

\(20\% \)

\(10\% \)

\(10\% \)

Consider randomly selecting such a coffee purchaser.

a. What is the probability that the individual purchased a small cup? A cup of decaf coffee?

b. If we learn that the selected individual purchased a small cup, what now is the probability that he/she chose decaf coffee, and how would you interpret this probability?

c. If we learn that the selected individual purchased decaf, what now is the probability that small size was selected, and how does this compare to the corresponding unconditional probability of (a)?

In Exercise 5, suppose that any incoming individual is equally likely to be assigned to any of the three stations irrespective of where other individuals have been assigned. What is the probability that

a. All three family members are assigned to the same station?

b. At most two family members are assigned to the same station?

c. Every family member is assigned to a different station?

Consider the following information about travellers on vacation (based partly on a recent Travelocity poll): \({\rm{40\% }}\) check work email, \({\rm{30\% }}\) use a cell phone to stay connected to work, \({\rm{25\% }}\) bring a laptop with them, \({\rm{23\% }}\) both check work email and use a cell phone to stay connected, and \({\rm{51\% }}\) neither check work email nor use a cell phone to stay connected nor bring a laptop. In addition, \({\rm{88}}\) out of every \({\rm{100}}\) who bring a laptop also check work email, and \({\rm{70}}\) out of every \({\rm{100}}\) who use a cell phone to stay connected also bring a laptop. a. What is the probability that a randomly selected traveller who checks work email also uses a cell phone to stay connected? b. What is the probability that someone who brings a laptop on vacation also uses a cell phone to stay connected? c. If the randomly selected traveller checked work email and brought a laptop, what is the probability that he/ she uses a cell phone to stay connected?

Use Venn diagrams to verify the following two relationships for any events Aand B (these are called De Morgan鈥檚 laws):

a.\(\left( {A \cup B} \right)' = A' \cap B'\)

b.\(\left( {A \cap B} \right)' = A' \cup B'\)

Hint:In each part, draw a diagram corresponding to the left side and another corresponding to the right side.)

A certain factory operates three different shifts. Over the last year, 200 accidents have occurred at the factory. Some of these can be attributed at least in part to unsafe working conditions, whereas the others are unrelated to working conditions. The accompanying table gives the percentage of accidents falling in each type of accident鈥搒hift category.

Unsafe Unrelated

Conditions to Conditions

Day 10% 35%

Shift Swing 8% 20%

Night 5% 22%

Suppose one of the 200 accident reports is randomly selected from a file of reports, and the shift and type of accident are determined.

a. What are the simple events?

b. What is the probability that the selected accident was attributed to unsafe conditions?

c. What is the probability that the selected accident did not occur on the day shift?
See all solutions

Recommended explanations on Math Textbooks

Statistics

Read Explanation

Probability and Statistics

Read Explanation

Applied Mathematics

Read Explanation

Pure Maths

Read Explanation

Logic and Functions

Read Explanation

Theoretical and Mathematical Physics

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.