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Show that if, then\({\rm{Corr(X,Y) = + 1}}\) or\({\rm{ - 1}}\). Under what conditions will\({\rm{\rho = + 1}}\)?

Short Answer

Expert verified

If \({\rm{a > 0}}\) then\({\rm{Corr(X,aX + b) = 1}}\), if\({\rm{a < 0}}\), then\({\rm{Corr(X,aX + b) = - 1}}\).

Step by step solution

01

Definition

Probability particular outcomes—how likely they are—when we're unclear about the result of an event. Statistics is the study of occurrences guided by probability.

02

Showing \({\rm{Corr(X,Y) =  + 1}}\) or\({\rm{ - 1}}\)

Assume that

\(\text{Y=aX+b,}\text{a }\!\!{}^\text{1}\!\!\text{0}\text{.}\)

The

correlation coefficient

of \({\rm{X}}\) and \({\rm{Y}}\)is

\({{\rm{\rho }}_{{\rm{X,Y}}}}{\rm{ = Corr(X,Y) = }}\frac{{{\rm{Cov(X,Y)}}}}{{{{\rm{\sigma }}_{\rm{X}}}{\rm{ \times }}{{\rm{\sigma }}_{\rm{Y}}}}}\)

The following holds

\(\begin{aligned}{\rm{Corr(X,aX + b) = }}\frac{{{\rm{Cov(X,aX + b)}}}}{{\sqrt {{\rm{\sigma }}_{\rm{X}}^{\rm{2}}{\rm{ \times \sigma }}_{{\rm{aX + b}}}^{\rm{2}}} }}\\\mathop {\rm{ = }}\limits^{{\rm{(1)}}} \frac{{{\rm{a\sigma }}_{\rm{X}}^{\rm{2}}}}{{\sqrt {{\rm{\sigma }}_{\rm{X}}^{\rm{2}}{\rm{ \times }}{{\rm{a}}^{\rm{2}}}{\rm{\sigma }}_{\rm{X}}^{\rm{2}}} }}\\{\rm{ = }}\frac{{{\rm{a\sigma }}_{\rm{X}}^{\rm{2}}}}{{{\rm{a}}\mid {\rm{\sigma }}_{\rm{X}}^{\rm{2}}}}\\\mathop {\rm{ = }}\limits^{{\rm{(1)}}} {\rm{ \pm 1,}}\end{aligned}\)

(1): here we use

\(\begin{aligned}{\rm{Cov(X,Y) = Cov(X,aX + b)}}\\{\rm{ = E(X(aX + b)) - E(X) \times E(aX + b)}}\\{\rm{ = a}}\left( {{\rm{E}}\left( {{{\rm{X}}^{\rm{2}}}} \right){\rm{ - (E(X)}}{{\rm{)}}^{\rm{2}}}} \right)\\{\rm{ = aV(X)}}\\{\rm{ = a\sigma }}_{\rm{X}}^{\rm{2}}\end{aligned}\)

and rules of variance,

(2): if \({\rm{a > 0}}\)then

\({\rm{Corr(X,aX + b) = 1}}\)

if\({\rm{a < 0}}\), then

\({\rm{Corr(X,aX + b) = - 1}}\)

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Most popular questions from this chapter

Show that when \({\rm{X}}\) and \({\rm{Y}}\) are independent, \({\rm{Cov(X,Y) = Corr(X,Y) = 0}}\).

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Each front tire on a particular type of vehicle is supposed to be filled to a pressure of 26 psi. Suppose the actual air pressure in each tire is a random variable—X for the right tire and Y for the left tire, with joint pdf fsx, yd 5 5 Ksx2 1 y2 d 20 # x # 30, 20 # y # 30 0 otherwise

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