/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q117SE Let Z have a standard normal dis... [FREE SOLUTION] | 91影视

91影视

Let Z have a standard normal distribution and define a new rv Y by \[{\text{Y = \sigma Z + \mu }}\]. Show that Y has a normal distribution with parameters \[{\text{\mu }}\] and \[{\text{\sigma }}\]. (Hint: \[{\text{Y\poundsy}}\]if \[{\text{Z\pounds}}\]? Use this to find the cdf of Y and then differentiate it with respect to y.)

Short Answer

Expert verified

The solution is

\(\begin{array}{c}{{\rm{F}}_{\rm{y}}}{\rm{(y) = P(Y\poundsy)}}\\{\rm{ = P}}\left( {{\rm{Z\pounds}}\frac{{{\rm{y - \mu }}}}{{\rm{\sigma }}}} \right)\\{\rm{ = }}{{\rm{F}}_{\rm{z}}}\left( {\frac{{{\rm{y - \mu }}}}{{\rm{\sigma }}}} \right){{\rm{f}}_{\rm{y}}}{\rm{(y)}}\\{\rm{ = }}\frac{{\rm{d}}}{{{\rm{dy}}}}{{\rm{F}}_{\rm{z}}}\left( {\frac{{{\rm{y - \mu }}}}{{\rm{\sigma }}}} \right)\\{\rm{ = }}\frac{{\rm{1}}}{{\rm{\sigma }}}{{\rm{f}}_{\rm{z}}}\left( {\frac{{{\rm{y - \mu }}}}{{\rm{\sigma }}}} \right){{\rm{f}}_{\rm{y}}}{\rm{(y)}}\\{\rm{ = }}\frac{{\rm{1}}}{{\rm{\sigma }}}{\rm{ \times }}\frac{{\rm{1}}}{{\sqrt {{\rm{2\pi }}} }}{\rm{ \times exp}}\left( {\frac{{{\rm{ - }}{{\left( {\frac{{{\rm{y - \mu }}}}{{\rm{\sigma }}}} \right)}^{\rm{2}}}}}{{\rm{2}}}} \right)\end{array}\)

Step by step solution

01

Definition

Probability simply refers to the likelihood of something occurring. We may talk about the probabilities of particular outcomes鈥攈ow likely they are鈥攚hen we're unclear about the result of an event. Statistics is the study of occurrences guided by probability.

02

Find the cdf of  Y

It is given that Z has a standard normal distribution then pdf of Z can be written as:

\[{{\text{f}}_{\text{z}}}{\text{(z) = }}\frac{{\text{1}}}{{\sqrt {{\text{2\pi }}} }}{\text{ \times exp}}\left( {\frac{{{\text{ - }}{{\text{z}}^{\text{2}}}}}{{\text{2}}}} \right)\]

It is also given that Y is a linear function of Z such that:

\[{\text{Y = \sigma Z + \mu }}\]

If we denote the cdf of \[{\text{Z}}\] and Y as Fz(z)and Fy(y) respectively, then we can write cdf of Y as:

\[\begin{gathered}

{{\text{F}}_{\text{y}}}{\text{(y) = P(Y\poundsy)}} \\

{\text{ = P(\sigma Z + \mu \poundsy)}} \\

{\text{ = P}}\left( {{\text{Z\pounds}}\frac{{{\text{y - \mu }}}}{{\text{\sigma }}}} \right){{\text{F}}_{\text{y}}}{\text{(y)}} \\

{\text{ = }}{{\text{F}}_{\text{z}}}\left( {\frac{{{\text{y - \mu }}}}{{\text{\sigma }}}} \right) \\

\end{gathered} \]

03

Differentiate it with respect to y

We denote the pdf of Y as \[{{\text{f}}_{\text{y}}}{\text{(y)}}\] , then

\[\begin{gathered}

{{\text{f}}_{\text{y}}}{\text{(y) = }}\frac{{\text{d}}}{{{\text{dy}}}}{{\text{F}}_{\text{y}}}{\text{(y)}} \\

{\text{ = }}\frac{{\text{d}}}{{{\text{dy}}}}{{\text{F}}_{\text{z}}}\left( {\frac{{{\text{y - \mu }}}}{{\text{\sigma }}}} \right){{\text{f}}_{\text{y}}}{\text{(y)}} \\

{\text{ = }}\frac{{\text{1}}}{{\text{\sigma }}}{{\text{f}}_{\text{z}}}\left( {\frac{{{\text{y - \mu }}}}{{\text{\sigma }}}} \right) \\

\end{gathered} \]

Using equations (1) and (2), we can write:

\[\begin{gathered}

{{\text{f}}_{\text{y}}}{\text{(y) = }}\frac{{\text{1}}}{{\text{\sigma }}}{\text{ \times }}\frac{{\text{1}}}{{\sqrt {{\text{2\pi }}} }}{\text{ \times exp}}\left( {\frac{{{\text{ - }}{{\left( {\frac{{{\text{y - \mu }}}}{{\text{\sigma }}}} \right)}^{\text{2}}}}}{{\text{2}}}} \right){{\text{f}}_{\text{y}}}{\text{(y)}} \\

{\text{ = \times }}\frac{{\text{1}}}{{{\text{(\sigma )}}\sqrt {{\text{2\pi }}} }}{\text{ \times exp}}\left( {\frac{{{\text{ - [y - \mu }}{{\text{]}}^{\text{2}}}}}{{{\text{2}}{{\text{\sigma }}^{\text{2}}}}}} \right] \\

\end{gathered} \]

From a look at the above equation, we can say that Y is also normally distributed with parameters \[{\text{\mu }}\] and \[{\text{\sigma }}\] .

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Find the following percentiles for the standard normal distribution. Interpolate where appropriate.

\(\begin{array}{*{20}{l}}{{\rm{a}}{\rm{. 91st}}}\\\begin{array}{l}{\rm{b}}{\rm{. 9th }}\\{\rm{c}}{\rm{. 75th }}\\{\rm{d}}{\rm{. 25th }}\\{\rm{e}}{\rm{. }}{{\rm{6}}^{{\rm{th}}}}\end{array}\end{array}\)

Let \({\rm{X}}\) denote the vibratory stress (psi) on a wind turbine blade at a particular wind speed in a wind tunnel. The article 鈥淏lade Fatigue Life Assessment with Application to VAWTS鈥 (J. of Solar Energy Engr., \({\rm{1982: 107 - 111}}\)) proposes the Rayleigh distribution, with pdf

\({\rm{f(x;\theta ) = \{ }}\begin{array}{*{20}{c}}{\frac{{\rm{x}}}{{{{\rm{\theta }}^{\rm{2}}}}}{{\rm{e}}^{{\rm{ - }}{{\rm{x}}^{\rm{2}}}{\rm{/(2}}{{\rm{\theta }}^{\rm{2}}}{\rm{)}}}}}&{{\rm{x > 0}}}\\{\rm{0}}&{{\rm{otherwise}}}\end{array}\)

otherwise as a model for the \({\rm{X}}\) distribution.

a. Verify that \({\rm{f(x;\theta )}}\) is a legitimate pdf.

b. Suppose \({\rm{\theta = 100}}\) (a value suggested by a graph in the article). What is the probability that \({\rm{X}}\) is at most \({\rm{200}}\)? Less than \({\rm{200}}\)? At least \({\rm{200}}\)?

c. What is the probability that \({\rm{X}}\) is between \({\rm{100}}\) and \({\rm{200}}\) (again assuming \({\rm{\theta = 100}}\))?

d. Give an expression for \({\rm{P(X}} \le {\rm{x)}}\).

When circuit boards used in the manufacture of compact disc players are tested, the long-run percentage of defectives is\({\rm{5\% }}\). Suppose that a batch of \({\rm{250}}\) boards has been received and that the condition of any particular board is independent of that of any other board.

a. What is the approximate probability that at least \({\rm{10\% }}\) of the boards in the batch are defective?

b. What is the approximate probability that there are exactly \({\rm{10}}\) defectives in the batch?

a. The event \(\left\{ {{X^2} \le y} \right\}\)is equivalent to what event involvingXitself?

b. If \(X\)has a standard normal distribution, use part (a) to write the integral that equals \(P\left( {{X^2} \le y} \right)\). Then differentiate this with respect to \(y\)to obtain the pdf of \({{\rm{X}}^{\rm{2}}}\) (the square of a \({\rm{N(0,1)}}\)variable). Finally, show that \({{\rm{X}}^{\rm{2}}}\)has a chi-squared distribution with \(\nu = 1\) df (see (4.10)). (Hint: Use the following identity.)

\(\frac{d}{{dy}}\left\{ {\int_{a(y)}^{b(y)} f (x)dx} \right\} = f(b(y)) \cdot {b^\prime }(y) - f(a(y)) \cdot {a^\prime }(y)\)

Use a statistical software package to construct a normal probability plot of the tensile ultimate-strength data given in Exercise of Chapter and comment.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.