/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q1E Suppose that \({x_1},...,{x_n}\)... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Suppose that \({x_1},...,{x_n}\) from a random sample from an exponential distribution with parameter\(\theta \).Explain how to use the parametric bootstrap to estimate the variance of the sample average\(\overline X \).(No simulation is required.)

Short Answer

Expert verified

The first step would be estimating parameters\(\theta \) using a maximum likelihood estimator.

M.L.E:

Let random variables\({x_1},{x_2},...,{x_n}\) have joint pdf or pmb

\(f\left( {{x_1},{x_2},...,{x_n};{\theta _1},{\theta _2},...,{\theta _m}} \right)\)

\(\frac{{{{\overline X }^2}}}{n}\)

Step by step solution

01

definition of the random variable is a variable  

A random variableis a factor with an undetermined number or a program that gives numbers to each study's results.

The first step of estimating parameters\(\theta \) using the maximum is the estimator.

M.L.E:

Let random variables\({x_1},{x_2},...,{x_n}\) have joint pdf or pmb

\(f\left( {{x_1},{x_2},...,{x_n};{\theta _1},{\theta _2},...,{\theta _m}} \right)\)

Let random variables have joint pdf or pmb

where the parameters \({\theta _{i,}}i = 1,2,...,m\) are unknown. When function f is a function of parameters\({\theta _{i,}}i = 1,2,...,m\) , it is called the likelihood function. Values\(\widehat {{\theta _i}}\) that maximize the likelihood function are the maximum likelihood estimates or equally values \(\widehat {{\theta _i}}\)for

\(f\left( {{x_1},{x_2},...,{x_n};\widehat {{\theta _1}},{{\widehat \theta }_2},...,{\theta _m}} \right) \ge f\left( {{x_1},{x_2},...,{x_n};{\theta _1},{\theta _2},...,{\theta _m}} \right)\)

For every\({\theta _{i,}}i = 1,2,...,m\) . By substituting\({X_i}\,\,\) with\({x_i}\) , the maximum likelihood estimators are obtained.

The sampling is from the Exponential Distribution function is

\(f\left( {{x_1},{x_2},...,{x_n};\beta } \right) = {\beta ^n}\,{e^{\beta y}},\)

\(y = \sum\limits_{i = 1}^n {\,{x_i}} \)

By maximizing the log of the likelihood function, the maximum likelihood estimates are more accessible to

\(\begin{aligned}{l}L\left( \beta \right) &= \log \,ff\left( {{x_1},{x_2},...,{x_n};\alpha ,\beta } \right)\\ &= n\,\log \beta - \beta y\end{aligned}\)

02

Partial derivative

From which, by finding the partial derivative and equating it with zero, the maximum is obtained.

\(\frac{\partial }{{\partial \beta }}L\left( \beta \right) = n\frac{1}{\beta } - y\)

which yields

\(\widehat \beta = \frac{n}{y} = \frac{1}{{{{\overline x }_n}}}\)

The M.L. estimator

\(\widehat \beta = \frac{1}{{{{\overline x }_n}}} = \widehat {\theta .}\)

The distribution \(\widehat F\)in the bootstrap would be the exponential distribution with parameter \(1/\overline X \). To use bootstrap, let the simulation size be from the distribution\(\widehat F\) .

The variance of the sample average V of simulations would be the bootstrap estimate of the variance of \(\overline X \) .

The variance of a single observation from the distribution\(\widehat F\) is the variance of\({\overline X ^2}\) the sample average of V simulations is \(1/n\) times larger, and thus the bootstrap estimate is

\(\frac{{{{\overline X }^2}}}{n}\)

Hence,

\(\frac{{{{\overline X }^2}}}{n}\)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Let \(U\) have the uniform distribution on the interval\([0,1]\). Show that the random variable \(W\)defined in Eq. (12.4.6) has the p.d.f. \(h\)defined in Eq. (12.4.5).

If \({\bf{X}}\) has the Cauchy distribution, the mean \({\bf{X}}\)does not exist. What would you expect to happen if you simulated a large number of Cauchy random variables and computed their average?

The skewness of a random variable was defined in Definition 4.4.1. Suppose that \({X_1},...,{X_n}\) form a random sample from a distribution \(F\). The sample skewness is defined as

\({M_3} = \frac{{\frac{1}{n}\sum\limits_{i = 1}^n {{{\left( {{X_i} - \bar X} \right)}^3}} }}{{{{\left( {\frac{1}{n}\sum\limits_{i = 1}^n {{{\left( {{X_i} - \bar X} \right)}^2}} } \right)}^{3/2}}}}\)

One might use \({M_3}\) as an estimator of the skewness \(\theta \) of the distribution F. The bootstrap can estimate the bias and standard deviation of the sample skewness as an estimator \(\theta \).

a. Prove that \({M_3}\) is the skewness of the sample distribution \({F_{{n^*}}}\)

b. Use the 1970 fish price data in Table 11.6 on page 707. Compute the sample skewness and then simulate 1000 bootstrap samples. Use the bootstrap samples to estimate the bias and standard deviation of the sample skewness.

Test the standard normal pseudo-random number generator on your computer by generating a sample of size 10,000 and drawing a normal quantile plot. How straight does the plot appear to be?

In this problem, we shall outline a Bayesian solution to the problem described in Example 7.5.10 on page 423. Let \(\tau \)= 1/σ2 and use a proper normal-gamma prior to the form described in Sec. 8.6. In addition to the two parameters, μ and \(\tau \), introduce n additional parameters. For i = 1, n, let Yi = 1 if Xi came from the normal distribution with mean μ and precision \(\tau \), and let Yi = 0 if Xi came from the standard normal distribution

a. Find the conditional distribution of μ given τ; Y1, ..., Yn; and X1, Xn.

b. Find the conditional distribution of τ given μ; Y1, ..., Yn; and X1, Xn.

c. Find the conditional distribution of Yi given μ; τ; X1, Xn; and the other Yj's.

d. Describe how to find the posterior distribution of μ \(\tau \)using Gibbs sampling.

e. Prove that the posterior mean of Yi is the posterior probability that Xi came from the normal distribution with unknown mean and variance

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.