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The skewness of a random variable was defined in Definition 4.4.1. Suppose that \({X_1},...,{X_n}\) form a random sample from a distribution \(F\). The sample skewness is defined as

\({M_3} = \frac{{\frac{1}{n}\sum\limits_{i = 1}^n {{{\left( {{X_i} - \bar X} \right)}^3}} }}{{{{\left( {\frac{1}{n}\sum\limits_{i = 1}^n {{{\left( {{X_i} - \bar X} \right)}^2}} } \right)}^{3/2}}}}\)

One might use \({M_3}\) as an estimator of the skewness \(\theta \) of the distribution F. The bootstrap can estimate the bias and standard deviation of the sample skewness as an estimator \(\theta \).

a. Prove that \({M_3}\) is the skewness of the sample distribution \({F_{{n^*}}}\)

b. Use the 1970 fish price data in Table 11.6 on page 707. Compute the sample skewness and then simulate 1000 bootstrap samples. Use the bootstrap samples to estimate the bias and standard deviation of the sample skewness.

Short Answer

Expert verified

a. Find all corresponding values and substitutes.

b. \({M_3} = 1.218, - 0.282,0.547. \)

Step by step solution

01

(a) To Prove that \({M_3}\) is the skewness of the sample distribution \({F_{{n^*}}}\) 

Comment. For a random variable X, the skewness, denoted by

\({\gamma _1}\)

is defined as

\({\gamma _1} = E\left( {\frac{{{{(X - \mu )}^3}}}{{{\sigma ^3}}}} \right)\)

where\(E(X) = \mu ,Var(X) = {\sigma ^2}\$ ,and\$ E\left( {{X^3}} \right) < \infty .\)

Assume that\({\bar X^*}\)is the random variable taken from the distribution\({F_n}\). Then, it is true that

\(E\left( {{{\bar X}^*}} \right) = \bar X = \mu \)

and the variance is given by

\(Var(X) = \frac{1}{n}\sum\limits_{i = 1}^n {{{\left( {{X_i} - \bar X} \right)}^2}} \)

Next, the expected value of\({\left( {{X^*} - \mu } \right)^3} = {\left( {{X^*} - \bar X} \right)^3}\) is

\(E\left( {{{\left( {{X^*} - \mu } \right)}^3}} \right) = \frac{1}{n}{\left( {{X_i} - \bar X} \right)^3}.\)

Finally, the sample skewness\({M_3}\)and the skewness of the sample distribution\({F_n}\)are identical because

\(\begin{aligned}{l}{\gamma _1} &= E\left( {\frac{{{{(X - \mu )}^3}}}{{{\sigma ^3}}}} \right)\\ &= \frac{{\frac{1}{n}{{\left( {{X_i} - \bar X} \right)}^3}}}{{{{\left( {\frac{1}{n}\sum\limits_{i = 1}^n {{{\left( {{X_i} - \bar X} \right)}^2}} } \right)}^{3/2}}}} = {M_3}\end{aligned}\)

This is true because the third moment is finite.

02

(b) To Use the bootstrap samples to estimate the bias and standard deviation of the sample skewness. 

To manually compute the skewness, you may use the given data and formula

\({M_3} = \frac{{\frac{1}{n}{{\left( {{X_i} - \bar X} \right)}^3}}}{{{{\left( {\frac{1}{n}\sum\limits_{i = 1}^n {{{\left( {{X_i} - \bar X} \right)}^2}} } \right)}^{3/2}}}}.\)

As software is used to simulate the bootstrap estimate of the bias of the sample skewness, you may also use the code. To simulate the \(\nu = 1000\) bootstrap samples, they should first compute the sample skewness of the initial sample. Denote \({M_3}\) the initial data skewness and \(M_3^{*(i)},i = 1,2,...,\nu \) the sample skewness of the bootstrap samples. The estimated bootstrap bias is then the mean of value\(M_3^{*(i)} - {M_3}\)

The estimate of the standard error is the sample standard deviation of \(M_3^{*(i)},i = 1,2,...,\nu .\)

The result obtained is the following. The sample skewness of the initial data is\({M_3} = 1.218\) , the bootstrap estimate of the bias is -0.282, and the estimate of the sample standard deviation is 0.547. Note that the values should change every time you run the software below. The given code is from RStudio.

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