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Fran Tick takes a 10 -problem precalculus test. The problems may be worked in any order. a. In how many different orders could she work all 10 of the problems? b. In how many different orders could she work any 7 of the 10 problems?

Short Answer

Expert verified
Fran can work the problems in 10! different orders for all 10 problems, and 10P7 different orders for any 7 of the 10 problems.

Step by step solution

01

Understanding the Problem for Part (a)

The first part of the exercise is asking for the number of different ways Fran can work through all 10 problems. This is a permutation problem, as the order in which she completes the problems is important.
02

Calculate Total Number of Orders for All 10 Problems

Since Fran has 10 problems and she is going to work on all of them, the number of different orders she could work them is the total number of permutations of 10 items, which is calculated using the formula for permutations: n!, where n is the number of items. In this case, n = 10, so we calculate 10!.
03

Understanding the Problem for Part (b)

The second part of the exercise is asking for the number of different ways Fran can work through any 7 of the 10 problems. This is again a permutation problem, but we're only choosing 7 out of 10.
04

Calculate Total Number of Orders for Any 7 Problems

To find the number of permutations when choosing 7 out of 10 problems, we use the formula for permutations of n items taken k at a time: nPk, which is calculated as n! / (n - k)!. Here, n = 10 and k = 7, so we calculate 10P7.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Permutation Formula
In precalculus, understanding how to count the number of ways in which a set of objects can be arranged is essential. The permutation formula is a fundamental tool for such calculations when the order of arrangement matters. Permutations are particularly important in scenarios where you are dealing with distinct objects and every possible order of arrangement is unique.

For instance, if we are considering Fran Tick's scenario of working through all 10 problems, it's not just about which problems she completes but the order in which she completes them. The permutation formula for arranging n unique items is denoted by n! — which reads as 'n factorial'. In Fran's case, where she has 10 problems to work on, this would translate to 10! or 10 factorial, which represents the product of all positive integers from 1 to 10.

In a general sense, whenever you encounter a question about the order of selection or arrangement, you can think of using the permutation formula as your go-to method for finding the solution.
Factorial Notation
Factorial notation is a mathematical operation that involves multiplying a series of descending natural numbers. For any non-negative integer n, the factorial of n (denoted by n!) is the product of all positive integers equal to or less than n. For instance, 5! equals 5 x 4 x 3 x 2 x 1, which is 120.

It's important to note that the factorial of 0 is defined to be 1; this is commonly known as the 'zero factorial' and is denoted by 0!. This convention is crucial for various combinatorial formulas to work correctly, even when there are no items to arrange. Understanding factorial notation is indispensable in combinatorial calculations, as it comes up in various formulas including permutations, combinations, and more.

Factorial notation is not just used in permutations; it plays a vital role in understanding series, probability, binomial theorem, and other areas of mathematics.
Combinatorial Calculations
Delving into the realm of combinatorial calculations, these involve counting, arranging, and combining objects in a structured way. They form the backbone of combinatorial mathematics, dealing with concepts such as permutations, combinations, and binomial coefficients.

In the context of permutations, as seen in the exercise with Fran Tick, we calculate permutations when we're interested in the order of selection. If Fran chooses 7 out of the 10 problems, we're facing a situation where not all items are selected and thus we need a slightly different formula, often expressed as nPk or P(n, k), representing the permutations of n items taken k at a time. The formula is given by n! / (n-k)!, meaning we divide the factorial of the total number of items by the factorial of the difference between the total number and the number of items chosen. For Fran's part b situation, this would be 10P7 or 10! divided by (10-7)!, simplifying to 10! divided by 3!. Combinatorial calculations like these are not only fascinating but are widely applicable in fields like statistics, computer science, and operations research.

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