Chapter 3: Problem 2
(a) Sketch the graph of \(f\). (b) Find the domain \(D\) and range \(R\) of \(f .\) (c) Find the intervals on which \(f\) is increasing or is decreasing. $$f(x)=\frac{1}{x^{2}}$$
Short Answer
Expert verified
The graph has two branches, domain is \( (-\infty, 0) \cup (0, \infty) \), range is \( (0, \infty) \), decreasing on \( (-\infty, 0) \) and \( (0, \infty) \).
Step by step solution
01
Analyze Basic Graph Shape
The function is given by \( f(x) = \frac{1}{x^2} \). Before sketching, note that this is a reciprocal function flipped along the x-axis due to the negative exponent. It produces a curve with two branches, one in the first quadrant and one in the second quadrant.
02
Determine Asymptotes
The graph of \( f(x) = \frac{1}{x^2} \) has two asymptotes. A vertical asymptote at \( x = 0 \) since division by zero is undefined, meaning the function approaches infinity as \( x \to 0^+ \) and \( x \to 0^- \). The horizontal asymptote is \( y = 0 \), as \( x \to \pm \infty \), \( f(x) \to 0 \).
03
Sketch the Graph
Using the information from the previous steps, sketch the graph with branches in the first and second quadrants approaching the x-axis and diverging at \( x = 0 \).
04
Define the Domain of \( f \)
The domain of \( f(x) = \frac{1}{x^2} \) is all real numbers except \( x = 0 \) because the function is undefined at \( x = 0 \). Thus, the domain \( D \) is \( (-\infty, 0) \cup (0, \infty) \).
05
Define the Range of \( f \)
Since the function \( f(x) = \frac{1}{x^2} \) is always positive and decreases towards zero as \( |x| \) increases, the range \( R \) is \( (0, \infty) \).
06
Find Intervals of Increase and Decrease
For \( f(x) = \frac{1}{x^2} \), observe that as \( x \) moves from negative infinity to zero, \( f(x) \) decreases, and as \( x \) moves from just above zero to infinity, \( f(x) \) also decreases. Therefore, the function is decreasing on both intervals \( (-\infty, 0) \) and \( (0, \infty) \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Domain and Range
The domain of a function represents all the possible values of the variable for which the function is defined. For the function \(f(x) = \frac{1}{x^2}\), the domain excludes \(x = 0\), where the function is undefined due to division by zero. Therefore, the domain is \((-\infty, 0) \cup (0, \infty)\).
The range of a function is the set of all possible output values. For \(f(x) = \frac{1}{x^2}\), the output is always positive since square of any real number is non-negative, making the range \((0, \infty)\).
Understanding domain and range is crucial in comprehending the limitations and behavior of any given function.
The range of a function is the set of all possible output values. For \(f(x) = \frac{1}{x^2}\), the output is always positive since square of any real number is non-negative, making the range \((0, \infty)\).
Understanding domain and range is crucial in comprehending the limitations and behavior of any given function.
- Domain: All possible \(x\)-values. For this function: \((-\infty, 0) \cup (0, \infty)\)
- Range: All possible \(f(x)\)-values. For this function: \((0, \infty)\)
Asymptotes in Functions
Asymptotes are lines that the graph of a function approaches but never actually meets. They provide significant insights into the behavior of the graph at extreme values. For \(f(x) = \frac{1}{x^2}\), there are two types of asymptotes to identify:
- **Vertical Asymptote:** This occurs at \(x = 0\) because the function becomes undefined as \(x\) approaches zero. As \(x\to 0^+\) or \(x\to 0^-\), \(f(x)\) tends towards infinity. Thus, there's a vertical asymptote along this line.
- **Horizontal Asymptote:** At extreme values of \(x\) (as \(x\to\pm \infty\)), the function \(f(x)\) tends towards zero, but never actually reaches zero, resulting in a horizontal asymptote at \(y = 0\).
Recognizing asymptotes informs how the graph stretches towards infinity and how the function behaves at its boundary values.
- **Vertical Asymptote:** This occurs at \(x = 0\) because the function becomes undefined as \(x\) approaches zero. As \(x\to 0^+\) or \(x\to 0^-\), \(f(x)\) tends towards infinity. Thus, there's a vertical asymptote along this line.
- **Horizontal Asymptote:** At extreme values of \(x\) (as \(x\to\pm \infty\)), the function \(f(x)\) tends towards zero, but never actually reaches zero, resulting in a horizontal asymptote at \(y = 0\).
Recognizing asymptotes informs how the graph stretches towards infinity and how the function behaves at its boundary values.
- Vertical Asymptote: \(x = 0\)
- Horizontal Asymptote: \(y = 0\)
Increasing and Decreasing Intervals
When analyzing a function, it's useful to determine where it's increasing or decreasing.
For \(f(x) = \frac{1}{x^2}\), as \(x\) moves from \(-\infty\) to 0, and from 0 to \(+\infty\), the function is decreasing. This means that as we move along the x-values, the output of the function gets smaller.
Remember:
- **Decreasing interval:** Both \((-\infty, 0)\) and \((0, \infty)\). The function decreases in both directions away from zero.
Understanding these intervals helps in predicting the trend of the function as \(x\) varies.
For \(f(x) = \frac{1}{x^2}\), as \(x\) moves from \(-\infty\) to 0, and from 0 to \(+\infty\), the function is decreasing. This means that as we move along the x-values, the output of the function gets smaller.
Remember:
- A function is increasing if the values of \(f(x)\) rise as \(x\) increases.
- A function is decreasing if the values of \(f(x)\) drop as \(x\) rises.
- **Decreasing interval:** Both \((-\infty, 0)\) and \((0, \infty)\). The function decreases in both directions away from zero.
Understanding these intervals helps in predicting the trend of the function as \(x\) varies.