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Graph \(f,\) and estimate all values of \(x\) such that \(f(x)>k\) $$f(x)=x^{5}-2 x^{2}+2 ; \quad k=-2$$

Short Answer

Expert verified
\((-\infty, -1.25)\) and \((0.65, \, \infty)\).

Step by step solution

01

Identify the Problem

We need to graph the function \(f(x) = x^{5} - 2x^{2} + 2\) and estimate the values of \(x\) where \(f(x) > -2\). First, understand the behavior of the function by considering its degree and leading coefficient.
02

Determine Intervals for Analysis

Since \(f(x)\) is a polynomial of degree 5, it extends from negative to positive infinity. We will analyze critical points and test values around them to determine when \(f(x) > -2\).
03

Find Critical Points

Take the derivative of \(f(x)\) to find critical points: \(f'(x) = 5x^{4} - 4x\). Setting \(f'(x) = 0\) gives \(x(5x^3 - 4) = 0\). Solving this, we find the critical points at \(x = 0\) and approximate roots of \(5x^3 = 4\).
04

Solve for Positive and Negative Intervals

Test values around the critical points to determine when \(f(x) > -2\). Plug different values into \(f(x)\) like \(x = -2, -1, 0, 1, 2\) to check the inequality.
05

Graph the Function

Plot the function using the critical points and test values. Visually analyze the graph to see where \(f(x) > -2\). Identify intervals where the curve is above the line \(y=-2\).
06

Estimate the x-Values

From the graph, find the estimated \(x\) values where \(f(x) > -2\). The graph indicates the intervals where the function is above \(y = -2\).
07

Conclude with Intervals

The function is greater than \(-2\) approximately on the intervals \((-\infty, -1.25)\) and \((0.65, \, \infty)\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Graphing Polynomial Functions
Graphing polynomial functions involves plotting a curve based on a polynomial equation. To graph a function like \(f(x) = x^{5} - 2x^{2} + 2\), first consider its degree and leading coefficient. This function is a 5th-degree polynomial. Fifth-degree polynomials typically have a general "W" or "M" shape, depending on the leading coefficient. The leading term, \(x^5\), indicates the end behavior. As \(x\) goes to positive or negative infinity, \(f(x)\) will also tend to infinity or negative infinity in the positive direction, since the coefficient is positive. To create the graph, plot diverse \(x\) values and compute \(f(x)\). This helps capture the shape of the function. Be cautious with turning points and overall scale while plotting these points. This visualization assists in interpreting where the function exceeds the given threshold \(k = -2\).
Critical Points
Critical points are where the function's derivative equals zero or is undefined. These points help us understand changes in the function's slope, indicating local maxima, minima, or points of inflection.For the polynomial \(f(x) = x^{5} - 2x^{2} + 2\), the first derivative is \(f'(x) = 5x^{4} - 4x\). Set \(f'(x) = 0\) to find the critical points:
  • Factor as \(x(5x^3 - 4) = 0\)
  • Solve for \(x = 0\)
  • Solve \(5x^3 - 4 = 0\) for real roots, approximately \(x \approx \pm (\frac{4}{5})^{1/3}\)
Analyzing these critical points gives insight into the behavior of the function and helps identify where significant changes occur in its graph.
Polynomial Derivatives
Polynomial derivatives are crucial in identifying how functions behave over different intervals. The derivative of a polynomial like \(f(x) = x^{5} - 2x^{2} + 2\) involves finding rates of change, which signals shifts in the graph's slope.The derivative is \(f'(x) = 5x^{4} - 4x\). This calculates how \(f(x)\) changes for an infinitesimal change in \(x\). Setting \(f'(x) = 0\) determines where the slope is zero, marking critical points. This step is essential in curve sketching, as these are potential turning points where the direction of the function changes. Derivatives can also inform us about the concavity. For instance, analyzing the second derivative if necessary could suggest where the function bends upwards or downwards, although it's not always required for finding where \(f(x)>k\).
Interval Testing
Interval testing helps determine where a polynomial is greater than a certain value. We use the critical points to divide the real number line into intervals. For example, to find where \(f(x) > -2\) with \(f(x) = x^{5} - 2x^{2} + 2\), use points like \(x = 0\) and solutions to \(5x^3 - 4 = 0\) as endpoints.Select test points within these intervals, such as \(x = -2, -1, 1, 2\), and plug them into \(f(x)\). This helps ascertain which intervals satisfy the inequality \(f(x) > -2\).
  • If \(f(x) > -2\), the inequality is true for this interval.
  • If \(f(x) < -2\), the inequality is false for this interval.
Graphing these helps visually affirm where the polynomial surpasses \(-2\), granting a straightforward means to confirm our interval analysis.

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Most popular questions from this chapter

Refer to Exercise 86 in Section 2.4 The distance \(D\) (in feet) required for a car to safely stop varies directly with its speed \(S\) (in mi/hr). Use the table to determine an approximate value for \(k\) in the variation formula \(D=k S^{23}\) $$\begin{array}{|ccccccc|} \hline \boldsymbol{s} & 20 & 30 & 40 & 50 & 60 & 70 \\ \hline \boldsymbol{D} & 33 & 86 & 167 & 278 & 414 & 593 \\ \hline \end{array}$$ (b) Check your approximation by graphing both the data and \(D\) on the same coordinate axes.

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