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Does there exist a polynomial of degree 3 with real coefficients that has zeros \(1,-1,\) and \(i\) ? Justify your answer.

Short Answer

Expert verified
No, there is no degree 3 polynomial with these zeros.

Step by step solution

01

Identify Given Zeros and Degree

The problem provides the zeros: \(1\), \(-1\), and \(i\). We are asked if a polynomial of degree 3 can have these as its zeros. Polynomials with real coefficients must have complex roots appear in conjugate pairs.
02

Apply Conjugate Root Theorem

Since \(i\) is a complex number, its conjugate, \(-i\), must also be a root of the polynomial if the polynomial has real coefficients. This gives us the roots: \(1, -1, i, -i\).
03

Count the Number of Zeros

List all the zeros: \(1, -1, i, -i\). This gives us four zeros. A polynomial's degree is the same as the highest power of the variable, and a degree \(n\) polynomial can have at most \(n\) zeros.
04

Compare the Number of Zeros to the Degree

To have all provided zeros, the polynomial needs to be of degree 4. Having four zeros contradicts the requirement for a polynomial of degree 3, which can only have three zeros.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Degree of Polynomial
In mathematics, the degree of a polynomial refers to the highest exponent of its variable. For example, in the polynomial \(3x^3 + 2x^2 + x + 5\), the degree is 3 because the highest power of \(x\) is 3. This number is significant because it tells us the maximum number of zeros—or roots—that the polynomial may have. Understanding the degree helps in predicting the behavior of polynomials and in solving polynomial equations efficiently.

Polynomials can have only as many zeros as their degree. Thus, a degree 3 polynomial can have up to three zeros, which can be a combination of real and complex roots. However, each root, complex or real, is counted separately when calculating the total number of roots of the polynomial.
Complex Roots and Conjugates
Complex roots are solutions to equations that include complex numbers, often involving the imaginary unit \(i\), where \(i^2 = -1\). Complex roots usually appear in conjugate pairs when dealing with polynomials with real coefficients.

The conjugate of a complex number \(a + bi\) is \(a - bi\). When a polynomial has real coefficients, if \(a + bi\) is a root, \(a - bi\) must also be a root because the coefficients do not allow for a singular complex number to be a root. This pairing ensures that the contributions of the imaginary parts cancel out, keeping the polynomial's overall result real.
Number of Zeros
The number of zeros a polynomial has is directly linked to its degree, as explained before. A polynomial of degree \(n\) can have at most \(n\) roots. These roots can be real or complex, and they might include repetitions which are called multiplicities.

In the given exercise, we have zeros \(1, -1, i,\) and \(-i\). However, if these are presumed to be the zeros, it would require a polynomial of degree 4, not 3. This discrepancy highlights the essential nature of the degree relation to the number of zeros: each root counts toward the total, whether it is real or part of a complex pair.
Conjugate Root Theorem
The Conjugate Root Theorem is a fundamental principle when dealing with polynomials that have real coefficients. It states that if a polynomial has a complex number as a root, its complex conjugate must also be a root. This theorem is crucial for maintaining the reality of coefficients throughout the polynomial.

In our exercise, \(i\) is listed as a zero. Therefore, by the Conjugate Root Theorem, \(-i\) must also be included as a zero. This requirement results in a total of four zeros, causing a conflict when we attempt to force a polynomial with these roots into degree 3 instead of degree 4. Thus, the existence of \(i\) as a root inherently forces the polynomial to adapt its structure, illustrating how mandatory pairs of complex conjugates influence the polynomial's degree.

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Most popular questions from this chapter

Medicare recipients The function \(f\) given by $$ f(x)=-0.000015 z^{3}-0.005 z^{2}+0.75 z+23.5 $$ where \(z=x-1973,\) approximates the total number of Medicare recipients in millions, from \(x=1973\) to \(x=2005 .\) There were \(23,545,363\) Medicare recipients in 1973 and \(42,394,926\) in 2005 (a) Graph \(f,\) and discuss how the number of Medicare recipients has changed over this time period. (b) Create a linear model similar to \(f\) that approximates the number of Medicare recipients. Which model is more realistic?

Use a graph to determine the number of non-real solutions of the equation. $$x^{5}+1.1 x^{4}-3.21 x^{3}-2.835 x^{2}+2.7 x+0.62=-1$$

Graph \(f\) for each value of \(n\) on the same coordinate plane, and describe how the multiplicity of a zero affects the graph of \(f\). $$f(x)=(x-0.5)^{n}\left(x^{2}+1\right) ; \quad n=1,2,3,4$$

(a) Graph the cubic polynomials $$ \begin{array}{l} f(x)=-3 x^{3} \\ g(x)=-3 x^{3}-x^{2}+1 \\ h(x)=-3 x^{3}+x^{2}-1 \end{array} $$ and $$ k(x)=-3 x^{3}-2 x^{2}+2 x $$ in the same coordinate plane, using each of the following viewing rectangles: (1) \([-2,2]\) by \([-2,2]\) (2) \([-10,10]\) by \([-10,10]\) (3) \([-50,50,10]\) by \([-5000,5000,1000]\) (4) \([-100,100,10]\) by \(\left[-5 \times 10^{5}, 5 \times 10^{5}, 10^{5}\right]\) (b) As the viewing rectangle increases in size, how do the graphs of the four functions compare? (c) Which term has the greatest influence on each function's value when \(|x|\) is large?

Graph \(f\) for each value of \(n\) on the same coordinate plane, and describe how the multiplicity of a zero affects the graph of \(f\). $$f(x)=(x-1)^{n}(x+1)^{n} ; \quad n=1,2,3,4$$

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