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In Problems 13–46, write the partial fraction decomposition of each rational expression.

x(3x-2)(2x+1)

Short Answer

Expert verified

The partial fraction decomposition of a rational expression is

x(3x-2)(2x+1)=27(3x-2)+17(2x+1)

Step by step solution

01

Step 1. Given information

Given rational expression is

x(3x-2)(2x+1)

02

Step 2. Partial fraction decomposition  

partial fraction decomposition of a rational expression

P(x)Q(x)=A1x-a1+A2x-a2+⋯+Anx-anx(3x-2)(2x+1)=A(3x-2)+B(2x+1)⋯(i)x(3x-2)(2x+1)=A(2x+1)(3x-2)(2x+1)+B(3x-2)(3x-2)(2x+1)x=A(2x+1)+B(3x-2)x+0=(2A+3B)x+(A-2B)⋯(ii)

03

Step 3. Values of coefficients and constants of the numerator  

Compare the constants in equation ii

0=A-2BA=2B

Compare the coefficient of xin equation ii and Substitute the expression for A

1=2A+3B1=2(2B)+3(B)B=17

so

A=217=27

04

Step 4. partial fraction decomposition of a rational expression   

Substitute the value of Aand B in the equation i

x(3x-2)(2x+1)=A(3x-2)+B(2x+1)x(3x-2)(2x+1)=27(3x-2)+17(2x+1)

So the partial fraction decomposition of a rational expression isx(3x-2)(2x+1)=27(3x-2)+17(2x+1)

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