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Chapter 11: Q. 47 (page 714)

Solve each system of equations. If the system has no solution, say that it is inconsistent.

x-y-z=1-x+2y-3z=-43x-2y-7z=0

Short Answer

Expert verified

The solution of the given system of equation is

(x,y,z)={(5z-2,4z-3,z)/z鈭�R}

Step by step solution

01

Given information

We are given a system of equation

x-y-z=1(1)-x+2y-3z=-4(2)3x-2y-7z=0(3)

02

Add equation 1 and 2

We get,

x-y-z=1-x+2y-3z=-4y-4z=-3

We get, y-4z=-3

Hencey=4z-3

03

add equation 2 and 3

We get,

-x+2y-3z=-4+3x-2y-7z=02x-10z=-4

Hence2x-10z=-4andx=5z-2

04

Conclusion

The solution set of the given system of equation is

(x,y,z)={(5z-2,4z-3,z)/z鈭�R}

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Most popular questions from this chapter

In Problems 35鈥�42, graph each system of inequalities by hand.

x2+y2鈮�9x+y鈮�3

solve each system of equations. If the system has no solution, say that it is inconsistent

x + 4y - 3z = -8

3x - y + 3z = 12

x + y + 6z = 1

In Problems, use the division algorithm to rewrite each improper fraction as the sum of a quotient and proper fraction. Find the partial fraction decomposition of the proper fraction. Finally, express the improper fraction as the sum of a quotient and the partial fraction decomposition.

x4+x3-x+2x2-2x+1

Solve each system of equations. If the system has no solution, say that it is inconsistent

x + 2y - z = -3

2x - 4y + z = -7

-2x + 2y - 3z = 4

Verify that the values of the variables listed are solutions of the system of equations.

4x-z=78x+5y-z=0-x-y+5z=6x=2,y=-3,z=1;2,-3,1
See all solutions

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