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Chapter 11: Q. 27 (page 773)

Graph each equation of the system. Then solve the system to find the points of intersection.

y=2x+12x2+y2=1

Short Answer

Expert verified

The point of intersection is (0,1)&-23,13.

Step by step solution

01

Step 1. Given information

y=2x+12x2+y2=1

02

Step 2. Graphing each equation

y=2x+1


2x2+y2=1

03

Step 3. Calculation of intersection point

Consider,y=2x+1.....(1)2x2+y2=1.....(2)Nowsubstitutingthevalueofyfromeq.1intoeq.2weget2x2+(2x+1)2=1 2x2+4x2+4x+1=16x2+4x=0x=0,-23Nowsubstitutingvalueofxineq.1wegety=2(0)+1y=1y=2-23+1y=-13

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Most popular questions from this chapter

The perimeter of a rectangle is 16inches, and its area is 15inches2. What are its dimensions?

Verify that the values of the variables listed are solutions of the system of equations.

3x+3y+2z=4x-3y+z=105x-2y-3z=8x=2,y=-2,z=2;2,-2,2

Solve each system of equations. If the system has no solution, say that it is inconsistent.

x-y-z=1-x+2y-3z=-43x-2y-7z=0

Graph each equation of the system. Then solve the system to find the points of intersection.

y=36-x2y=8-x

(a) Graph the line : 3x+4y=12.

(b) What is the slope of a line parallel to this line?
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