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The concentration C of a certain drug in a patient's bloodstream t hours after injection is given by

Ct=50tt2+25

Part (a): Find the horizontal asymptote of Ct. What happens to the concentration of the drug as t increases?

Part (b): Using your graphing utility, graph C=Ct.

Part (c): Determine the time at which the concentration is highest.

Short Answer

Expert verified

Part (a): The horizontal asymptote ofCtis t-axis.

When t increases, the concentration of the drug is given localid="1646069485593" Ct→0.

Part (b): On plotting the graph, we get,

Part (c): Concentration is highest at5hoursafter injection.

Step by step solution

01

Part (a) Step 1. Given information.

Consider the given function,

Ct=50tt2+25

The horizontal of this function can be given by,

role="math" localid="1646068914875" =limx→∞Ct

Using the long division method,

=limx→∞50t+25t

We have the horizontal asymptote of the given function asy=0asx→∞.

02

Part (b) Step 1. Plot the graph.

Plot the function C=Ct,

03

Part (c) Step 1. Determine the time.

Consider the given function,

Ct=50tt2+25

From the graph, it can be said that the concentration of the drug is highest at the time localid="1646069170036" 5hoursafter injection.

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