/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 79 In Problems 75–80, for the giv... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

In Problems 75–80, for the given functions fand g,

(a) Graph fand gon the same Cartesian plane.

(b) Solvefx=gx.

(c) Use the result of part (b) to label the points of intersection of the graphs of fandg.

(d) Shade the region for which fx>gxthat is, the region below fand above g.

fx=-x2+5x;gx=x2+3x-4

Short Answer

Expert verified

(a) The graph of fand gis

(b)x=2,1.

(c) The point of intersection is2,6,-1,6.

(d) The shaded region is

Step by step solution

01

Part (a) Step 1. Given information

It is given that fx=-x2+5x;gx=x2+3x-4.We need to draw the graph offandgin the same cartesian plane.

02

Step 2. Draw the graph

03

Part (b) Step 1. Given information

It is given thatfx=-x2+5x;gx=x2+3x-4.We need to solvefx=gx.

04

Step 2. Solving

fx=gx.

-x2+5x=x2+3x-4.

2x2-2x-4=0.

x2-x-2=0.

x=1±-12-4·1·-22·2.

=1±1+84.

=1±94.

=1±34.

x=1+32=2,andx=1-32=-1.

The values for which fand gare equal, whenx=2,-1.

05

Part (c) Step 1. Given information

It is given thatfx=-x2+5x;gx=x2+3x-4.We need to use the result of part (b) to label the point of intersection.

06

Step 2. Simplify

Let y=-x2+5x=fx.

y=gx=x2+3x-4.

Whenx=2,y=-22+5·2=6.

Whenx=-1,y=--12+5·-1=-6.

The point of intersection is2,6,-1,6.

07

Part (d) Step 1. Given information

It is given that fx=-x2+5x;gx=x2+3x-4.e need to draw the shaded region forfx>gx.

08

Step 2. Draw the shaded region

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.