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The graph of the function fx=ax2+bx+chas vertex at 0,2and passes through the point 1,8. Finda,bandc.

Short Answer

Expert verified

The solutions area=6,b=0, andc=2.

Step by step solution

01

Step 1. Given information.

Given function f(x)=ax2+bx+c.

Vertex at 0,2and passes through the point1,8.

02

Step 2. Determine the value of b and c.

The coordinates of the vertex of a quadratic function of the form fx=ax2+bx+care role="math" localid="1646894449869" -b2a,f-b2a.

So, -b2a,f-b2a=0,2⋯⋯Givenvertex0,2.

-b2a=0-b=0b=0 and f-b2a=2f0=2⋯⋯-b2a=0a02+b0+c=2⋯⋯substitutex=0infx=ax2+bx+cc=2

03

Step 3. Determine the value of a.

From the point 1,8, we find that f1=8.

Substitute 1for x, 0for b, 2for c, and 8for f1in fx=ax2+bx+c.

fx=ax2+bx+cf1=a12+01+28=a+2a+2=8a=8-2a=6

04

Step 4. Simplified answer.

Hence,a=6,b=0, andc=2.

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