91Ó°ÊÓ

Given that the linear function is $F\left(x\right)=4.$

Here, the linear function is $F\left(x\right)=4.$We know that in a linear function $f\left(x\right)=mx+b$,$m$is the slope and $b$is y- intercept.

So, in the given function slope is$0$and y- intercept is$4.$

The graph of the given function is

Linear functions have a constant average rate of change. That is, the average rate of change of a linear function $f\left(x\right)=mx+b$is $\frac{∆y}{∆x}=m.$

So, in the given linear function $F\left(x\right)=4,$ the average rate of change is$0.$

Since, we know that the linear function $f\left(x\right)=mx+b,$is increasing over its domain if its slope $m,$is positive. It is decreasing over its domain if its slope $m,$is negative. It is constant over its domain if its slope $m,$is zero.

Here, in given linear function $F\left(x\right)=4$, slope is zero, so function is constant.