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Two sides and an angle are given. Determine whether the given information results in one triangle, two triangles, or no triangle at all. Solve each triangle that resultsa=2,c=1,C=25°.

Short Answer

Expert verified

With the given measurements two triangles are possible.

For△A1B1C,a=2,b1=2.3,c=1,A1=57.69°,B1=97.31°,C=25°For△A2B2C,a=2,b2=1.3,c=1,A2=122.31°,B2=32.69°,C=25°

Step by step solution

01

Step 1. Given information

a=2,c=1,C=25°

For a triangle with sides a, b, c and opposite angles A, B, C, respectively, Law of sines is given as:

sinAa=sinBb=sinCc

02

Step 2. Calculation

ByLawofSines,ForA,⇒sinAa=sinCc⇒sinA=sin(C)×ac=sin(25°)×21=0.4226×2=0.8452A1≈57.69°orA2≈180°-57.69°=122.31°Since,A1+C<180°,△A1B1CispossibleandA2+C<180°,△A2B2Cispossible.In△A1B1CForB1,⇒B1=180°-A1-C=180°-57.69°-25°=180°-82.69°=97.31°Forb1,⇒sinCc=sinB1b1⇒b1=sin(B1)×csinC=sin(97.31°)×1sin25°=0.99180.4226=2.3469≈2.3In△A2B2C,ForB2,⇒B2=180°-A2-C=180°-122.31°-25°=180°-147.31°=32.69°Forb2,⇒sinCc=sinB2b2⇒b2=sin(B2)×csinC=sin(32.69°)×1sin25°=0.540.4226=1.277≈1.3

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