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A person in a small boat, offshore from a vertical cliff known to be 100 feet in height, takes a sighting of the top of the cliff. If the angle of elevation is found to be25°, how far offshore is the boat?

Short Answer

Expert verified

Hence, the boat is approx 214.4542 feet far from the vertical cliff.

Step by step solution

01

Given Information

A person in a small boat, offshore from a vertical cliff known to be 100 feet in height, takes a sighting of the top of the cliff. If the angle of elevation is found to be 25°.

02

Solution

We can draw a figure as: -

So, in â–³ABCwe have to find BC.

Therefore,

tan(C)=ABBC

tan(25°)×BC=ABBC=ABtan(25°)BC=1000.46630BC≈214.4542

03

Final Answer

Hence, the boat is approx 214.4542 feet far from the vertical cliff.

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