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A rectangle is inscribed in a semicircle of radius 1. See the illustration.

Part (a): Express the area A of the rectangle as a function of the angle shown in the illustration.

Part (b): Show that A=sin2.

Part (c): Find the angle that results in the largest area A.

Part (d): Find the dimensions of this largest rectangle.

Short Answer

Expert verified

Part (a): Area A as a function is given by A=2cossin.

Part (b): To prove A=sin2use the double angle formula and solve the equations.

Part (c): The area Ais largest at =45.

Part (d): The dimension of largest rectangle is1unit1unit.

Step by step solution

01

Part (a) Step 1. Write function of area.

Consider the given question,

Radius of circle is 1unit.

x is the half width and y is the length of the rectangle.

localid="1646410018881" length=21cosbreadth=1sin

We know area of rectangle islocalid="1646410062384" A=lengthbreadth.

Substituting the values in the formula,

localid="1646410078022" A=2cossin

02

Part (b) Step 1. To prove Aθ=sin2θ.

Consider the previous part,

A=2cossin......(i)

From the double angle formula,

sin2=2cossin......(ii)

From equations (i) and (ii),

A=sin2

Hence, proved.

03

Part (c) Step 1. When the angle results in largest area.

Consider the previous part,

A=sin2

For the area to be the largest, maximum value of sin2. Then,

sin2=12=90=45

04

Part (d) Step 1. Find the dimensions of this largest rectangle.

Consider the previous part,

A=sin2

Then,

localid="1646411213709" A=sin90=1

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